Q71.Equation of the tangent to the circle, at the point (1, −1), whose center, is the point of intersection of the straight lines x −y = 1 and 2x + y = 3 is: JEE Main 2016 (10 Apr Online) JEE Main Previous Year Paper (1) x + 4y + 3 = 0 (2) 3x −y −4 = 0 (3) x −3y −4 = 0 (4) 4x + y −3 = 0
What This Question Tests
Tests the ability to find the center of a circle by solving simultaneous equations, calculate its radius using a given point, and then write the equation of the tangent at that point.
Concepts Tested
Formulas Used
Equation of tangent at (x1, y1) to (x-h)^2 + (y-k)^2 = r^2 is (x-h)(x1-h) + (y-k)(y1-k) = r^2
Distance formula for radius
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📋 Question Details
- Chapter
- Circles
- Topic
- Tangent to a circle
- Year
- 2016
- Shift
- 10 Apr Online
- Q Number
- Q71
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 11: Conic Sections
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