Q16.Experimentally it is found that 12. 8 eV energy is required to separate a hydrogen atom into a proton and an electron. So the orbital radius of the electron in a hydrogen atom is 9 × 10−10 m. x The value of the x is: _____. ( 1 eV = 1. 6 × 10−19 J, 1 = 9 × 109 Nm2C2 and electronic charge = 1. 6 × 10−19 C) 4πε0
What This Question Tests
This question links the binding energy of a hydrogen atom to its total energy and electrostatic potential energy, and then uses this to determine the orbital radius.
Concepts Tested
Formulas Used
Total Energy = -1/2 (kq²/r)
Binding Energy = |Total Energy|
1/(4πε₀) = 9 × 10⁹ Nm²C⁻²
📚 NCERT Sections This Tests
12.4 — The Ground State Energy Of Hydrogen Atom Is –13.6 Ev. What Are The
Physics Class 12 · Chapter 12
12.4 The ground state energy of hydrogen atom is –13.6 eV. What are the kinetic and potential energies of the electron in this state?
12.7 — The Radius Of The Innermost Electron Orbit Of A Hydrogen Atom Is
Physics Class 12 · Chapter 12
12.7 The radius of the innermost electron orbit of a hydrogen atom is 5.3×10–11 m. What are the radii of the n = 2 and n =3 orbits?
12.3 — A Difference Of 2.3 Ev Separates Two Energy Levels In An Atom. What
Physics Class 12 · Chapter 12
12.3 A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom make a transition from the upper level to the lower level?
📋 Question Details
- Chapter
- Atoms
- Topic
- Binding energy and orbital radius
- Year
- 2023
- Shift
- 06 Apr Shift 2
- Q Number
- Q16
- Type
- Numerical
- NCERT Ref
- Class 12 Physics Ch 12: Atoms
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