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MathsHardMCQ2019 · 09 Apr Shift 1

Q69.If a tangent to the circle x2 + y2 = 1 intersects the coordinate axes at distinct points P and Q, then the locus of the mid-point of PQ is: (1) x2 + y2–16x2y2 = 0 (2) x2 + y2–4x2y2 = 0 (3) x2 + y2–2xy = 0 (4) x2 + y2–2x2y2 = 0

What This Question Tests

This question integrates concepts from circles and straight lines. It requires finding the equation of a tangent to a circle, determining its intercepts on the coordinate axes, and then finding the locus of the midpoint of these intercepts through algebraic elimination.

Concepts Tested

Equation of tangent to a circleIntercept form of a lineMidpoint formulaLocus

Formulas Used

Equation of tangent at (x1, y1) to x²+y²=r² is xx1+yy1=r²

Intercept form x/a + y/b = 1

Midpoint formula

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