Q28.Taking the wavelength of first Balmer line in hydrogen spectrum (n = 3 to n = 2) as 660 nm , the wavelength of the 2nd Balmer line (n = 4 to n = 2) will be : (1) 889.2 nm (2) 488.9 nm (3) 388.9 nm (4) 642.7 nm
What This Question Tests
This question tests the application of the Rydberg formula for the hydrogen spectrum, specifically for the Balmer series, to find the wavelength of a spectral line given another line's wavelength.
Concepts Tested
Formulas Used
1/λ = R (1/n₁² - 1/n₂²)
📚 NCERT Sections This Tests
12.5 — A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 · Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
12.7 — The Radius Of The Innermost Electron Orbit Of A Hydrogen Atom Is
Physics Class 12 · Chapter 12
12.7 The radius of the innermost electron orbit of a hydrogen atom is 5.3×10–11 m. What are the radii of the n = 2 and n =3 orbits?
12.8 — A 12.5 Ev Electron Beam Is Used To Bombard Gaseous Hydrogen At
Physics Class 12 · Chapter 12
12.8 A 12.5 eV electron beam is used to bombard gaseous hydrogen at room temperature. What series of wavelengths will be emitted?
📋 Question Details
- Chapter
- Atoms
- Topic
- Bohr's Model & Hydrogen Spectrum
- Year
- 2019
- Shift
- 09 Apr Shift 1
- Q Number
- Q28
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 12: Atoms
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