Practice Questions

Q53.The correct order of the following complexes in terms of their crystal field stabilization energies is : (1) [Co(NH3)4]2+ < [Co(NH3)6]2+ < [Co(en)3]3+ < [Co(NH3)6]3+ (2) [Co(NH3)6]2+ < [Co(NH3)6]3+ < [Co(NH3)4]2+ < [Co(en)3]3+ (3) [Co(en)3]3+ < [Co(NH3)6]3+ < [Co(NH3)6]2+ < [Co(NH3)4]2+ (4) [Co(NH3)4]2+ < [Co(NH3)6]2+ < [Co(NH3)6]3+ < [Co(en)3]3+

Q54.The element that does not belong to the same period of the remaining elements (modern periodic table) is: 2025 (23 Jan Shift 1) JEE Main Previous Year Paper (1) Iridium (2) Platinum (3) Osmium (4) Palladium

Q54.A molecule (" P ") on treatment with acid undergoes rearrangement and gives ("Q"). ("Q") on ozonolysis followed by reflux under alkaline condition gives (" R "). The structure of (" R ") is given below. The structure of (" P′′ ) is (1) (2) (3) (4) 2025 (28 Jan Shift 1) JEE Main Previous Year Paper

Q54. Aman has been asked to synthesise the molecule (x).He thought of preparing the molecule using an aldol condensation reaction. He found a few cyclic alkenes in his laboratory. He thought of performing ozonolysis reaction on alkene to produce a dicarbonyl compound followed by aldol reaction to prepare " x ". Predict the suitable alkene that can lead to the formation of " x ". 2025 (24 Jan Shift 1) JEE Main Previous Year Paper (1) (2) (3) (4)

Q59.Find the compound ' A ' from the following reaction sequences. A aqua-regia→ B (1) KNO2∣NH4OH→ yellow ppt (2) AcOH (1) CoS (2) ZnS (3) NiS (4) MnS

Q61. CrCl3 ⋅xNH3 can exist as a complex. 0.1 molal aqueous solution of this complex shows a depression in freezing point of 0.558∘C. Assuming 100% ionisation of this complex and coordination number of Cr is 6 , the complex will be (Given Kf = 1.86 K kg mol−1 ) (1) [Cr(NH3)5Cl]Cl2 (2) [Cr(NH3)6]Cl3 (3) [Cr(NH3)3Cl3] (4) [Cr(NH3)4Cl2]Cl

Q66.When sec-butylcyclohexane reacts with bromine in the presence of sunlight, the major product is : (1) (2) (3) (4)

Q70.From the magnetic behaviour of [NiCl4]2− (paramagnetic) and [Ni(CO)4] (diamagnetic), choose the correct geometry and oxidation state. (1) [NiCl4]2−: NiII , tetrahedral [Ni(CO)4] : NiII , (2) [NiCl4]2− : NiII , square planar [Ni(CO)4] : Ni(0) square planar , square planar (3) [NiCl4]2−: NiII , tetrahedral [Ni(CO)4] : Ni(0), (4) [NiCl4]2−: Ni(0), tetrahedral [Ni(CO)4] : Ni(0), tetrahedral square planar

Q71.Electrolysis of 600 mL aqueous solution of NaCl for 5 min changes the pH of the solution to 12 . The current in Amperes used for the given electrolysis is ____. (Nearest integer).

Q71.The compound with molecular formula C6H6 , which gives only one monobromo derivative and takes up four moles of hydrogen per mole for complete hydrogenation has ________ = electrons. 2025 (22 Jan Shift 2) JEE Main Previous Year Paper Q72.20 mL of 2 M NaOH solution is added to 400 mL of 0.5 M NaOH solution. The final concentration of the solution is _______ ×10−2M. (Nearest integer)

Q72.Isomeric hydrocarbons → negative Baeyer's test (Molecular formula C9H12 ) The total number of isomers from above with four different non-aliphatic substitution sites is -

Q72. A → B The molecule A changes into its isomeric form B by following a first order kinetics at a temperature of 1000 K . If the energy barrier with respect to reactant energy for such isomeric transformation is 191.48 kJ mol−1 and the frequency factor is 1020 , the time required for 50% molecules of A to become B is _________ picoseconds (nearest integer). [R = 8.314 J K−1 mol−1]

Q73.Consider a complex reaction taking place in three steps with rate constants k1, k2 and k3 respectively. The overall rate constant k is given by the expression k = . If the activation energies of the three steps are √k1k3k2 60,30 and 10 kJ mol−1 respectively, then the overall energy of activation in kJmol−1 is … … . (Nearest integer)

Q73.Consider the following low-spin complexes K3 [Co(NO2)6], K4 [Fe(CN)6], K3 [Fe(CN)6], Cuu2 [Fe(CN)6] and Zn2 [Fe(CN)6] The sum of the spin-only magnetic moment values of complexes having yellow colour is. _____ B.M. (answer in nearest integer)

Q73.The sum of sigma (σ) and pi (π) bonds in Hex-1,3-dien-5-yne is _______. Q74. 0.1 mole of compound ' S ' will weigh _______ g. (Given molar mass in gmol−1C : 12, H : 1, O : 16)

Q73.Total number of molecules/species from following which will be paramagnetic is ______ O2, O+2 , O−2 , NO, NO2, CO, K2 [NiCl4], [Co(NH3)6]Cl3, K2 [Ni(CN)4]

Q73.Consider the following sequence of reactions: 11.25 mg of chlorobenzene will produce __________ ×10−1mg of product B . (Consider the reactions result in complete conversion.) [Given molar mass of C, H, O, N and Cl as 12, 1, 16, 14 and 35.5 g mol−1 respectively]

Q74.Some CO2 gas was kept in a sealed container at a pressure of 1 atm and at 273 K . This entire amount of CO2 gas was later passed through an aqueous solution of Ca(OH)2 . The excess unreacted Ca(OH)2 was later neutralized with 0.1 M of 40 mL HCl . If the volume of the sealed container of CO2 was x, then x is ________ cm3 (nearest integer). [Given : The entire amount of CO2( g) reacted with exactly half the initial amount of Ca(OH)2 present in the aqueous solution.] 2025 (22 Jan Shift 1) JEE Main Previous Year Paper

Q74.In the Claisen-Schmidt reaction to prepare, dibenzalacetone from 5.3 g of benzaldehyde, a total of 3.51 g of product was obtained. The percentage yield in this reaction was ______ %.

Q74.The bond dissociation enthalpy of X2ΔHbond calculated from the given data is kJmol−1 . (Nearest M+X−(s) →M+(g) + X−(g)ΔH∗lattice = 800 kJ mol−1 integer) M( s) →M( g)ΔH∘sub = 100 kJ mol−1 M( g) →M+(g) + e−(g)ΔHi = 500 kJ mol−1 X( g) + e−(g) →X−(g)ΔH∗eg = −300 kJ mol−1 M( s) + 12 X2( g) →M+X−(s)ΔH∘f = −400 kJ mol−1 [Given : M+X− is a pure ionic compound and X forms a diatomic molecule X2 in gaseous state] 2025 (23 Jan Shift 2) JEE Main Previous Year Paper

Q34. List - I List - II A. Melting Point [K] I. T1 > In > Ga > A1 > B Match List I with List II B. Ionic Radius [M+3/pm] II. B > T1 > A1 ≈Ga > In Choose the C. ΔiH1 [ kJ mol−1] III. T1 > In > A1 > Ga > B D. Atomic Radius [pm] IV. B > A1 > T1 > In > Ga correct answer from the options given below: (1) A-II, B-III, C-IV, D-I (2) A-IV, B-I, C-II, D-III (3) A-I, B-II, C-III, D-IV (4) A-III, B-IV, C-I, D-II

Q37. For the given compounds, the correct order of increasing pKa value : Choose the correct answer from the options given below : (1) (B) < (D) < (C) < (A) < (E) (2) (D) < (E) < (C) < (B) < (A) (3) (E) < (D) < ( C ) < ( B ) < ( A ) (4) (E) < (D) < (B) < (A) < (C) JEE Main 2024 (09 Apr Shift 1) JEE Main Previous Year Paper

Q47.Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): SN2 reaction of C6H5CH2Br occurs more readily than the SN2 reaction of CH3CH2Br . Reason (R) : The partially bonded unhybridized p-orbital that develops in the trigonal bipyramidal transition state is stabilized by conjugation with the phenyl ring. In the light of the above statements, choose the most appropriate answer from the options given below : (1) (A) is correct but (R) is not correct (2) (A) is not correct but (R) is correct (3) Both (A) and (R) are correct but (R) is not the (4) Both (A) and (R) are correct and (R) is the correct explanation of (A) correct explanation of (A) JEE Main 2024 (09 Apr Shift 1) JEE Main Previous Year Paper

Q47.Identify the major products A and B respectively in the following set of reactions. (1) (2) (3) (4)

Q49.Which one of the following reactions is NOT possible? (1) (2) (3) (4)