Practice Questions

Q76.The area (in sq. units) of the part of the circle 𝑥2 + 𝑦2 = 36, which is outside the parabola 𝑦2 = 9𝑥, is equal to (1) 12𝜋+ 3√3 (2) 24𝜋+ 3√3 (3) 24𝜋- 3√3 (4) 12𝜋- 3√3

Q76.Let a vector →a be coplanar with vectors b = 2ˆi + ˆj + ˆk and →c= ˆi −ˆj + ˆk. If →a is perpendicular to → → → → → d = 3ˆi + 2ˆj + 6ˆk, and →a = √10. Then a possible value of [→a b →c] + [→a b d ] + [→a →c d ] is equal to: (1) −42 (2) −40 (3) −29 (4) −38 → → →

Q76.The value of ∫ −11 1 ) √2 (( x−1x+1 + ( x−1x+1 ) 2 −2) 2 √2 (1) loge 4 (2) 2 loge 16 + (3) loge 16 (4) 4 loge(3 2√2)

Q76.If In = ∫ π2 cotn xdx, then 4 (1) I2 + I4, (I3 + I5)2, I4 + I6 are in G. P. (2) I2 + I4, I3 + I5, I4 + I6 are in A. P. (3) 1 , 1 , 1 are in A. P. (4) 1 , 1 , 1 are in G. P. I2+I4 I3+I5 I4+I6 I2+I4 I3+I5 I4+I6 is equal to lim n1 + (n+1)2n + (n+2)2n + … + (2n−1)2n ]

Q76.Let C1 be the curve obtained by the solution of differential equation 2xy dxdy = y2 −x2, x > 0 . Let the curve C2 be the solution of x2−y22xy = dxdy . If both the curves pass through (1, 1), then the area (in sq. units) enclosed by the curves C1 and C2 is equal to : (1) π −1 (2) π2 −1 (3) π + 1 (4) π4 + 1 → → = 3 and

Q76.The area, enclosed by the curves 𝑦= sin𝑥+ cos𝑥 and 𝑦= | cos𝑥- sin𝑥| and the lines 𝑥= 0, 𝑥= 2, is : (1) 2√2 ( √2 + 1 ) (2) 2√2 ( √2 - 1 ) (3) 4 ( √2 - 1 ) (4) 2 ( √2 + 1 )

Q76.Let slope of the tangent line to a curve at any point P(x, y) be given by xy2+yx x + 2y = 4 at x = −2, then the value of y, for which the point (3, y) lies on the curve, is : (1) −43 (2) 3518 (3) −1819 (4) −1811 −−

Q77.Let y = y(x) be the solution of the differential equation (x −x3)dy = (y + yx2 −3x4)dx, x > 2 If y(3) = 3, then y(4) is equal to: (1) 4 (2) 12 (3) 8 (4) 16 b If magnitudes of the vectors →a, b and →care √2, 1 and

Q77.Let y(x) be the solution of the differential equation 2x2 dy + (ey −2x)dx = 0, x > 0. If y(e) = 1, then y(1) is equal to: (1) loge(2e) (2) loge 2 (3) 2 (4) 0

Q77.Let y = y(x) be the solution of the differential equation dxdy = (y + 1)((y + 1)ex2/2 −x), y(2) = 0. Then the value of dxdy at x = 1 is equal to (1) −e3/2 (2) − 2e2 (e2+1)2 (1+e2)2 (3) e5/2 (4) 5e1/2 (1+e2)2 (e2+1)2 −−−−−

Q77.Let →a = ˆi + 2ˆj −3ˆk and b = 2ˆi −3ˆj + 5ˆk. If →r×→a = b ×→r,→r⋅(αˆi + 2ˆj + ˆk) 2 is equal to : = −1, α ∈R, then the value of α + →r →r⋅(2ˆi + 5ˆj −αˆk) (1) 9 (2) 15 (3) 13 (4) 11

Q77.Let α be the angle between the lines whose direction cosines satisfy the equations l + m −n = 0 and l2 + m2 −n2 = 0. Then the value of sin4 α + cos4 α is : (1) 5 (2) 1 8 2 (3) 3 (4) 3 8 4

Q77.Let 𝑦= 𝑦( 𝑥) be the solution of the differential equation 𝑑𝑦 1 + 𝑥𝑒𝑦- 𝑥, - √2 < 𝑥< √2, 𝑦0 = 0 𝑑𝑥= , then the minimum value of 𝑦𝑥, 𝑥∈-√2, √2 is equal to : (1) 2 - √3 - loge2 (2) 2 + √3 + loge2 (3) 1 + √3 - loge√3 - 1 (4) 1 - √3 - loge√3 - 1

Q77.Let y = y(x) be solution of the differential equation loge( dxdy ) y(−23 loge 2) = α loge 2 , then the value of α is equal to: JEE Main 2021 (27 Jul Shift 1) JEE Main Previous Year Paper (1) −14 (2) 41 (3) 2 (4) −12 →

Q77.Let three vectors →a, b and →cbe such that →a× b =→c, b ×→c=→a and →a = 2. Then which one of the following is not true? b b b × is 2 (1) →a× ((→ → → (2) → +→c) ( −→c)) = 0 Projection of →a on ( ×→c) + = 8 (4) 3→a+→b −2→c 2 = 51 (3) [→a →b →c] [→c →a →b ] JEE Main 2021 (22 Jul Shift 1) JEE Main Previous Year Paper = 2. If P(α, β, γ) is the

Q77.If the curve y = y(x) is the solution of the differential equation 2(x2 + x5/4)dy −y(x + x1/4)dx = 2x9/4dx, x > 0 which passes through the point (1, 1 −43 loge 2), then the value of y(16) is equal to (1) 4( 313 + 38 loge 3) (2) ( 313 + 38 loge 3) (3) 4( 313 −83 loge 3) (4) ( 313 −83 loge 3) −−

Q78.Let L be the line of intersection of planes →r⋅(ˆi −ˆj + 2ˆk) = 2 and →r⋅(2ˆi + ˆj −ˆk) foot of perpendicular on L from the point (1, 2, 0), then the value of 35(α + β + γ) is equal to: (1) 101 (2) 119 (3) 143 (4) 134

Q78.Let the position vectors of two points P and Q be 3ˆi −ˆj + 2ˆk and ˆi + 2ˆj −4ˆk, respectively. Let R and S be two points such that the direction ratios of lines PR and QS are (4, −1, 2) and (−2, 1, −2), respectively. Let −−−→ → → lines PR and QS intersect at T . If the vector TA is perpendicular to both PR and QS and the length of vector −→ TA is √5 units, then the modulus of a position vector of A is : (1) √482 (2) √171 (3) √5 (4) √227 P divides the line

Q78.If dy dx = 2y , y(0) = 1, then y(1) is equal to : (1) log2(1 + e2) (2) log2(2e) (3) log2(2 + e) (4) log2(1 + e) → → → → 1 is a unit

Q78.A plane passes through the points A(1, 2, 3), B(2, 3, 1) and C(2, 4, 2). If O is the origin and P is (2, −1, 1) −→ , then the projection of OP on this plane is of length: (1) √25 (2) √27 (3) √23 (4) √211

Q79.Consider the line L given by the equation x−3 2 = y−11 = z−21 . Let Q be the mirror image of the point (2, 3, −1) with respect to L. Let a plane P be such that it passes through Q, and the line L is perpendicular to P. Then which of the following points is on the plane P? (1) (−1, 1, 2) (2) (1, 1, 1) (3) (1, 1, 2) (4) (1, 2, 2)

Q79.Let a, b ∈R. If the mirror image of the point P(a, 6, 9) with respect to the line x−37 = y−25 = z−1−9 is (20, b, −a −9), then |a + b| is equal to: (1) 86 (2) 90 (3) 84 (4) 88

Q79.If the foot of the perpendicular from point (4, 3, 8) on the line L1 : x−al = y−23 = z−b4 , l ≠0 is (3, 5, 7), then the shortest distance between the line L1 and line L2 : x−23 = y−44 = z−55 is equal to (1) 1 (2) 1 2 √6 (3) √23 (4) √31 JEE Main 2021 (16 Mar Shift 2) JEE Main Previous Year Paper

Q79.Let the foot of perpendicular from a point 𝑃( 1, 2, - 1 ) to the straight line 𝐿: 𝑥 = 𝑦 = 𝑧 be 𝑁. Let a line be 1 0 -1 drawn from 𝑃 parallel to the plane 𝑥+ 𝑦+ 2𝑧= 0 which meets 𝐿 at point 𝑄. If 𝛼 is the acute angle between the lines 𝑃𝑁 and 𝑃𝑄, then cos𝛼 is equal to . 1 √3 (1) (2) √5 2 1 1 (3) (4) √3 2√3

Q79.The distance of the point ( - 1, 2, - 2 ) from the line of intersection of the planes 2𝑥+ 3𝑦+ 2𝑧= 0 and 𝑥- 2𝑦+ 𝑧= 0 is : 1 √42 (1) (2) √2 2 5 √34 (3) (4) 2 2