Practice Questions
1,013 questions across 23 years of JEE Main β find and practise any topic!
Found 1,013 results
Q76.Let C1 be the curve obtained by the solution of differential equation 2xy dxdy = y2 βx2, x > 0 . Let the curve C2 be the solution of x2βy22xy = dxdy . If both the curves pass through (1, 1), then the area (in sq. units) enclosed by the curves C1 and C2 is equal to : (1) Ο β1 (2) Ο2 β1 (3) Ο + 1 (4) Ο4 + 1 β β = 3 and
Q76.If In = β« Ο2 cotn xdx, then 4 (1) I2 + I4, (I3 + I5)2, I4 + I6 are in G. P. (2) I2 + I4, I3 + I5, I4 + I6 are in A. P. (3) 1 , 1 , 1 are in A. P. (4) 1 , 1 , 1 are in G. P. I2+I4 I3+I5 I4+I6 I2+I4 I3+I5 I4+I6 is equal to lim n1 + (n+1)2n + (n+2)2n + β¦ + (2nβ1)2n ]
Q76.The value of β« β11 1 ) β2 (( xβ1x+1 + ( xβ1x+1 ) 2 β2) 2 β2 (1) loge 4 (2) 2 loge 16 + (3) loge 16 (4) 4 loge(3 2β2)
Q77.Let y = y(x) be solution of the differential equation loge( dxdy ) y(β23 loge 2) = Ξ± loge 2 , then the value of Ξ± is equal to: JEE Main 2021 (27 Jul Shift 1) JEE Main Previous Year Paper (1) β14 (2) 41 (3) 2 (4) β12 β
Q77.Let π¦= π¦( π₯) be the solution of the differential equation ππ¦ 1 + π₯ππ¦- π₯, - β2 < π₯< β2, π¦0 = 0 ππ₯= , then the minimum value of π¦π₯, π₯β-β2, β2 is equal to : (1) 2 - β3 - loge2 (2) 2 + β3 + loge2 (3) 1 + β3 - logeβ3 - 1 (4) 1 - β3 - logeβ3 - 1
Q77.Let βa = Λi + 2Λj β3Λk and b = 2Λi β3Λj + 5Λk. If βrΓβa = b Γβr,βrβ (Ξ±Λi + 2Λj + Λk) 2 is equal to : = β1, Ξ± βR, then the value of Ξ± + βr βrβ (2Λi + 5Λj βΞ±Λk) (1) 9 (2) 15 (3) 13 (4) 11
Q77.Let three vectors βa, b and βcbe such that βaΓ b =βc, b Γβc=βa and βa = 2. Then which one of the following is not true? b b b Γ is 2 (1) βaΓ ((β β β (2) β +βc) ( ββc)) = 0 Projection of βa on ( Γβc) + = 8 (4) 3βa+βb β2βc 2 = 51 (3) [βa βb βc] [βc βa βb ] JEE Main 2021 (22 Jul Shift 1) JEE Main Previous Year Paper = 2. If P(Ξ±, Ξ², Ξ³) is the
Q77.Let y(x) be the solution of the differential equation 2x2 dy + (ey β2x)dx = 0, x > 0. If y(e) = 1, then y(1) is equal to: (1) loge(2e) (2) loge 2 (3) 2 (4) 0
Q77.Let y = y(x) be the solution of the differential equation dxdy = (y + 1)((y + 1)ex2/2 βx), y(2) = 0. Then the value of dxdy at x = 1 is equal to (1) βe3/2 (2) β 2e2 (e2+1)2 (1+e2)2 (3) e5/2 (4) 5e1/2 (1+e2)2 (e2+1)2 βββββ
Q77.If the curve y = y(x) is the solution of the differential equation 2(x2 + x5/4)dy βy(x + x1/4)dx = 2x9/4dx, x > 0 which passes through the point (1, 1 β43 loge 2), then the value of y(16) is equal to (1) 4( 313 + 38 loge 3) (2) ( 313 + 38 loge 3) (3) 4( 313 β83 loge 3) (4) ( 313 β83 loge 3) ββ
Q77.Let Ξ± be the angle between the lines whose direction cosines satisfy the equations l + m βn = 0 and l2 + m2 βn2 = 0. Then the value of sin4 Ξ± + cos4 Ξ± is : (1) 5 (2) 1 8 2 (3) 3 (4) 3 8 4
Q77.Let y = y(x) be the solution of the differential equation (x βx3)dy = (y + yx2 β3x4)dx, x > 2 If y(3) = 3, then y(4) is equal to: (1) 4 (2) 12 (3) 8 (4) 16 b If magnitudes of the vectors βa, b and βcare β2, 1 and
Q78.A plane passes through the points A(1, 2, 3), B(2, 3, 1) and C(2, 4, 2). If O is the origin and P is (2, β1, 1) ββ , then the projection of OP on this plane is of length: (1) β25 (2) β27 (3) β23 (4) β211
Q78.If dy dx = 2y , y(0) = 1, then y(1) is equal to : (1) log2(1 + e2) (2) log2(2e) (3) log2(2 + e) (4) log2(1 + e) β β β β 1 is a unit
Q78.Let y = y(x) be the solution of the differential equation exβ1 βy2 dx + ( xy )dy = 0, y(1) = β1 Then the value of (y(3))2 is equal to: (1) 1 β4e3 (2) 1 β4e6 (3) 1 + 4e3 (4) 1 + 4e6 β
Q78.Let L be the line of intersection of planes βrβ (Λi βΛj + 2Λk) = 2 and βrβ (2Λi + Λj βΛk) foot of perpendicular on L from the point (1, 2, 0), then the value of 35(Ξ± + Ξ² + Ξ³) is equal to: (1) 101 (2) 119 (3) 143 (4) 134
Q78.Let the position vectors of two points P and Q be 3Λi βΛj + 2Λk and Λi + 2Λj β4Λk, respectively. Let R and S be two points such that the direction ratios of lines PR and QS are (4, β1, 2) and (β2, 1, β2), respectively. Let ββββ β β lines PR and QS intersect at T . If the vector TA is perpendicular to both PR and QS and the length of vector ββ TA is β5 units, then the modulus of a position vector of A is : (1) β482 (2) β171 (3) β5 (4) β227 P divides the line
Q79.Let a, b βR. If the mirror image of the point P(a, 6, 9) with respect to the line xβ37 = yβ25 = zβ1β9 is (20, b, βa β9), then |a + b| is equal to: (1) 86 (2) 90 (3) 84 (4) 88
Q79.If the foot of the perpendicular from point (4, 3, 8) on the line L1 : xβal = yβ23 = zβb4 , l β 0 is (3, 5, 7), then the shortest distance between the line L1 and line L2 : xβ23 = yβ44 = zβ55 is equal to (1) 1 (2) 1 2 β6 (3) β23 (4) β31 JEE Main 2021 (16 Mar Shift 2) JEE Main Previous Year Paper
Q79.Consider the line L given by the equation xβ3 2 = yβ11 = zβ21 . Let Q be the mirror image of the point (2, 3, β1) with respect to L. Let a plane P be such that it passes through Q, and the line L is perpendicular to P. Then which of the following points is on the plane P? (1) (β1, 1, 2) (2) (1, 1, 1) (3) (1, 1, 2) (4) (1, 2, 2)
Q79.If the equation of plane passing through the mirror image of a point (2, 3, 1) with respect to line x+1 2 = yβ31 = z+2β1 and containing the line xβ23 = 1βy2 = z+11 is Ξ±x + Ξ²y + Ξ³z = 24 then Ξ± + Ξ² + Ξ³ is equal to: (1) 20 (2) 19 (3) 18 (4) 21
Q79.Let the foot of perpendicular from a point π( 1, 2, - 1 ) to the straight line πΏ: π₯ = π¦ = π§ be π. Let a line be 1 0 -1 drawn from π parallel to the plane π₯+ π¦+ 2π§= 0 which meets πΏ at point π. If πΌ is the acute angle between the lines ππ and ππ, then cosπΌ is equal to . 1 β3 (1) (2) β5 2 1 1 (3) (4) β3 2β3
Q79.The distance of the point ( - 1, 2, - 2 ) from the line of intersection of the planes 2π₯+ 3π¦+ 2π§= 0 and π₯- 2π¦+ π§= 0 is : 1 β42 (1) (2) β2 2 5 β34 (3) (4) 2 2
Q80.The probability that two randomly selected subsets of the set {1, 2, 3, 4, 5} have exactly two elements in their intersection, is: (1) 65 (2) 65 28 27 (3) 35 (4) 135 27 29
Q80.Let π= {1, 2, 3, 4, 5, 6} . Then the probability that a randomly chosen onto function π from π to π satisfies π3 = 2 π1 is : 1 1 (1) (2) 15 5 (3) 1 (4) 1 30 10