Practice Questions

Q52.The correct order of the spin –only magnetic moment of metal ions in the following low-spin complexes, 4 - 4 - 3 + 2 + [V ( CN ) 6] , [Fe ( CN ) 6] , [Ru ( NH3 ) 6] and [Cr ( NH3 ) 6] , is: (1) V2 + > Cr2 + > Ru3 +(2)>Cr2Fe2++ > V2 + > Ru3 +(3)> Cr2Fe2++ > Ru3 + > Fe2 +(4)> V2V2++ > Ru3 + > Cr2 + > Fe2 + JEE Main 2019 (08 Apr Shift 1) JEE Main Previous Year Paper

Q53.The complex ion that will lose its crystal field stabilization energy upon oxidation of metal to +3 state is: (1) Niphen3 2 + (2) Fephen3 2 + (3) Cophen3 2 + (4) Znphen3 2 +

Q53.The total number of isomers for a square planar complex: [MCl(F)(NO2)(SCN)] is: (1) 12 (2) 16 (3) 4 (4) 8

Q53.The major product in the following conversion is JEE Main 2019 (12 Jan Shift 2) JEE Main Previous Year Paper (1) (2) (3) (4)

Q55.The major product of the following reaction is: JEE Main 2019 (10 Apr Shift 1) JEE Main Previous Year Paper (1) (2) (3) (4)

Q56. In the following compound, the favourable site/s for protonation is/are : JEE Main 2019 (11 Jan Shift 2) JEE Main Previous Year Paper (1) (a) and (e) (2) (b), (c) and (d) (3) (a) and (d) (4) (a)

Q58.With dehydrating agent present which dicarboxylic acid is least reactive towards forming an anhydride? JEE Main 2019 (10 Jan Shift 1) JEE Main Previous Year Paper (1) (2) (3) (4)

Q59.The correct match between column-I and column-II is Column-I (drug) Column-II (test) (A) Chloroxylenol (P) Carbylamine test (B) Norethindrone (Q) Sodium hydrogen carbonate test (C) Sulphapyridine (R) Ferric chloride test (D) Penicillin (S) Baeyer’s test (1) A →R, B →P, C →S, D →Q (2) A →Q, B →S, C →P, D →R (3) A →Q, B →P, C →S, D →R (4) A →R, B →S, C →P, D →Q

Q60.The correct structure of the product ‘P’ in the following reaction is NEt3 −Asn −Ser + (CH3 CO)2O → P (excess) JEE Main 2019 (10 Jan Shift 1) JEE Main Previous Year Paper (1) (2) (3) (4)

Q60.The increasing order of pKa of the following amino acids in aqueous solution is Glycine, Aspartate, Lysine, Arginine. (1) Arginine < Lysine < Glycine < Aspartate (2) Aspartate < Glycine < Arginine < Lysine (3) Glycine < Aspartate < Arginine < Lysine (4) Aspartate < Glycine < Lysine < Arginine

Q61.If α and β are the roots of the quadratic equation x2 + xsinθ −2sinθ = 0, θ ∈(0, 2π ) , then α12+β12 is equal to : (α−12+β−12).(α−β)24 (1) 26 (2) 212 (sinθ+8)12 (sinθ−4)12 (3) 212 (4) 212 (sinθ+8)12 (sinθ−8)6 , has magnitude , then −z is equal to:

Q61.Consider the quadratic equation (c −5)x2 −2cx + (c −4) = 0, c ≠5. Let S be the set of all integral values of c for which one root of the equation lies in the interval (0, 2) and its other root lies in the interval (2, 3). Then the number of elements in S is (1) 11 (2) 12 (3) 18 (4) 10

Q61.If m is chosen in the quadratic equation (m2 + 1)x2 −3x + (m2 + 1)2 = 0 such that the sum of its roots is greatest, then the absolute difference of the cubes of its roots is: (1) 4√3 (2) 10√5 (3) 8√3 (4) 8√5

Q61.The number of real roots of the equation 5 + 2𝑥- 1 = 2𝑥2𝑥- 2 is : (1) 2 (2) 3 (3) 1 (4) 4 π

Q61.If λ be the ratio of the roots of the quadratic equation in x, 3m2x2 + m(m −4)x + 2 = 0, then the least value of m for which λ + λ1 = 1, is : JEE Main 2019 (12 Jan Shift 1) JEE Main Previous Year Paper (1) 2 −√3 (2) −2 + √2 (3) 4 −2√3 (4) 4 −3√2 α −

Q62.If 𝑧 and 𝜔 are two complex numbers such that 𝑧𝜔= 1 and 𝑎𝑟𝑔𝑧- 𝑎𝑟𝑔( 𝜔) = 2, then: (1) 𝑧¯ω = 1 - 𝑖 (2) ¯𝑧𝜔= 𝑖 √2 (3) 𝑧¯ω = -1 + 𝑖 (4) ¯𝑧ω = - 𝑖 √2

Q64.Let Sn = 1 + q + q2 + … . +qn and Tn = 1 + ( q+12 ) ( q+12 ) ( q+12 ) and q ≠1. If 101C1 + 101C2 ⋅S1 + … . +101C101 ⋅S100 = αT100, then α is equal to : (1) 299 (2) 202 (3) 200 (4) 2100

Q65.The sum ∑ 𝑘 is equal to 𝑘= 1 2𝑘 11 21 (1) 1 – (2) 2 – 220 220 3 11 (3) 2 – (4) 2 – 217 219 6 Q66. 1 1 If the fourth term in the binomial expansion of √𝑥 1 + log10𝑥+ 𝑥 12 is equal to 200, and 𝑥> 1, then the value of 𝑥 is (1) 100 (2) 104 (3) 103 (4) 10

Q65.If 20C1 + (22) 20C2 + (32) 20C3+. . . . . +(202) 20C20 = A(2β), then the ordered pair (A, β) is equal to JEE Main 2019 (12 Apr Shift 2) JEE Main Previous Year Paper (1) (380, 19) (2) (420, 18) (3) (420, 19) (4) (380, 18) − 3 ) 6 is equal to x2

Q65.Let 𝑎1, 𝑎2, … , 𝑎30 be an A.P., 𝑆= ∑𝑖=30 1 𝑎𝑖 and 𝑇= ∑𝑖=15 1 𝑎( 2𝑖- 1 ) . If 𝑎5 = 27 and 𝑆- 2𝑇= 75, then 𝑎10 is equal to: (1) 52 (2) 47 (3) 42 (4) 57

Q65.The sum of the following series 1 + 6 + 9(12+22+32)7 + 12(12+22+32+42)9 + 15(12+22+…+52)11 +. . . . is: (1) 7520 (2) 7510 (3) 7830 (4) 7820

Q65.If sin4α + 4cos4β + 2 = 4√2sinαcosβ, α, β ∈[0, π] , then cos(α + β) −cos(α −β) is equal to (1) −1 (2) −√2 (3) √2 (4) 0 JEE Main 2019 (12 Jan Shift 2) JEE Main Previous Year Paper

Q67.All the pairs (x, y), that satisfy the inequality 2√sin2x−2sinx+5 ⋅ 1 ≤1 also satisfy the equation: 4sin2y (1) 2 sin x = sin y (2) sin x = 2 sin y (3) |sin x| = |sin y| (4) 2|sin x| = 3 sin y

Q69.If a circle of radius R passes through the origin O and intersects the coordinate axes at A and B, then the locus of the foot of perpendicular from O on AB is : (1) (x2 + y2)(x + y) = R2xy (2) (x2 + y2)3 = 4R2x2y2 (3) (x2 + y2) 2 = 4R2x2y2 (4) (x2 + y2) 2 = 4Rx2y2

Q69.The locus of the centres of the circles, which touch the circle, 𝑥2 + 𝑦2 = 1 externally, also touch the 𝑦-axis and lie in the first quadrant, is: (1) 𝑦= √1 + 2𝑥, 𝑥≥0 (2) 𝑦= √1 + 4𝑥, 𝑥≥0 (3) 𝑥= √1 + 2𝑦, 𝑦≥0 (4) 𝑥= √1 + 4𝑦, 𝑦≥0