Practice Questions
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Q61.Let Ξ±, Ξ² be two roots of the equation x2 + (20)1/4x + (5)1/2 = 0 . Then Ξ±8 + Ξ²8 is equal to JEE Main 2021 (27 Jul Shift 1) JEE Main Previous Year Paper (1) 10 (2) 100 (3) 50 (4) 160
Q61.Let ππ be the sum of the first π terms of an arithmetic progression. If π3π= 3π2π, then the value of π4π is : π2π JEE Main 2021 (25 Jul Shift 1) JEE Main Previous Year Paper (1) 6 (2) 4 (3) 2 (4) 8
Q61.The sum of the roots of the equation, π₯+ 1 - 2log23 + 2π₯+ 2log410 - 2-π₯= 0, is : (1) log214 (2) log212 (3) log213 (4) log211
Q61.The value of 4 + 1 1 is: 5+ 1 4+ 1 5+ 4+β¦β¦β (1) 2 + 52 β30 (2) 2 + β54 β30 (3) 4 + 4 β30 (4) 5 + 25 β30 β5
Q61.If for x β(0, Ο2 ), log10 sin x + log10 cos x = β1 and log10(sin x + cos x) = 12 (log10 n β1), n > 0 , then the value of n is equal to : (1) 20 (2) 12 (3) 9 (4) 16
Q61.If Ξ± and Ξ² are the distinct roots of the equation x2 + (3) 1 1 4 x + 3 2 = 0 , then the value of Ξ±96(Ξ±12 β1) + Ξ²96(Ξ²12 β1) is equal to: (1) 56 Γ 325 (2) 56 Γ 324 (3) 52 Γ 324 (4) 28 Γ 325
Q61.A natural number has prime factorization given by n = 2x3y5z , where y and z are such that y + z = 5 and yβ1 + zβ1 = 56 , y > z. Then the number of odd divisors of n, including 1 , is: (1) 12 (2) 6 (3) 11 (4) 6x
Q61.If x2 + 9y2 β4x + 3 = 0, x, y βR, then x and y respectively lie in the intervals (1) [β13 , 13 ] and [β13 , 13 ] (2) [1, 3] and [β13 , 13 ] (3) [β13 , 13 ] and [1, 3] (4) [1, 3] and [1, 3]
Q61.The least value of |z| where z is complex number which satisfies the inequality ||z|+1| loge 2) e( (|z|+3)(|z|β1) β₯logβ2 5β7 + 9i , i = ββ1, is equal to : (1) 3 (2) β5 (3) 2 (4) 8
Q61.The number of real solutions of the equation, x2 β|x| β12 = 0 is: (1) 2 (2) 3 (3) 1 (4) 4
Q61.The sum of 10 terms of the series 3 + 5 + 7 + β¦ is : 12Γ22 22Γ32 32Γ42 (1) 143 (2) 99 144 100 (3) 1 (4) 120121
Q61.Let S1, S2 and S3 be three sets defined as : z β1 S1 = β€β2}, {z βC S2 = {z βC : Re((1 βi)z) β₯1} and S3 = {z βC : Im(z) β€1}. Then, the set S1 β©S2 β©S3 (1) is a singleton (2) has exactly two elements (3) has infinitely many elements (4) has exactly three elements
Q61.The value of 3 + 1 1 is equal to 4+ 1 3+ 1 4+ 3+β¦β (1) 1. 5 + β3 (2) 2 + β3 (3) 3 + 2β3 (4) 4 + β3 Β―Β―
Q61.Let a, b, c be in arithmetic progression. Let the centroid of the triangle with vertices (a, c), (2, b) and (a, b) be ( 103 , 73 ). If Ξ±, Ξ² are the roots of the equation ax2 + bx + 1 = 0, then the value of Ξ±2 + Ξ²2 βΞ±Ξ² is: (1) β71256 (2) 25669 (3) 256 71 (4) β69256
Q61.The equation arg( z+1zβ1 ) = Ο4 represents a circle with: (1) centre at (0, 0) and radius β2 (2) centre at (0, 1) and radius 2 (3) centre at (0, β1) and radius β2 (4) centre at (0, 1) and radius β2 22
Q61.Let π and π be two positive numbers such that π+ π= 2 and π4 + π4 = 272. Then π and π are roots of the equation: (1) π₯2 - 2π₯+ 2 = 0 (2) π₯2 - 2π₯+ 8 = 0 (3) π₯2 - 2π₯+ 136 = 0 (4) π₯2 - 2π₯+ 16 = 0
Q61.The integer k, for which the inequality x2 β2(3k β1)x + 8k2 β7 > 0 is valid for every x in R is: (1) 4 (2) 2 (3) 3 (4) 0 JEE Main 2021 (25 Feb Shift 1) JEE Main Previous Year Paper Β―Β―
Q62.The area of the triangle with vertices P(z), Q(iz) and R(z + iz) is (1) 1 (2) 12 z 2 (3) 1 (4) 1 z + iz 2 2 2
Q62.The sum of the series 1 + 2 + + β¦ + 2100 when x = 2 is: x+1 x2+1 x4+1 x2100+1 (1) 1 β 2101 (2) 1 + 2101 4101β1 4101β1 (3) 1 + 2100 (4) 1 β 2100 4101β1 4201β1
Q62.Three numbers are in an increasing geometric progression with common ratio r. If the middle number is doubled, then the new numbers are in an arithmetic progression with common difference d. If the fourth term of GP is 3r2, then r2 βd is equal to : (1) 7 ββ3 (2) 7 + 3β3 (3) 7 β7β3 (4) 7 + β3
Q62.A 10 inches long pencil AB with mid point C and a small eraser P are placed on the horizontal top of a table such that PC = β5 inches and β PCB = tanβ1(2). The acute angle through which the pencil must be rotated about C so that the perpendicular distance between eraser and pencil becomes exactly 1 inch is : (1) tanβ1( 43 ) (2) tanβ1( 21 ) (3) tanβ1( 43 ) (4) tanβ1(1)
Q62.The sum of all those terms which are rational numbers in the expansion of 1 1 12 3 + 3 4 (2 ) is: (1) 89 (2) 27 (3) 35 (4) 43 , then the
Q62.If 0 < x < 1 and y = 21 x2 + 32 x3 + 43 x4 + β¦ β¦ , then the value of e1+y at x = 21 is: (1) 1 e2 (2) 2e 2 (3) 2e2 (4) 21 βe
Q62.If S = {z βC : z+2izβi βR}, then (1) S is a circle in the complex plane (2) S contains exactly two elements (3) S contains only one element (4) S is a straight line in the complex plane
Q62.If sum of the first 21 terms of the series log91/2 x + log91/3 x + log91/4 x + β¦ . . where x > 0 is 504, then x is equal to (1) 243 (2) 9 (3) 7 (4) 81