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Practice Questions

10,171 questions across 23 years of JEE Main β€” find and practise any topic!

Found 10,171 results

Q70.In an ellipse, with centre at the origin, if the difference of the lengths of major axis and minor axis is 10 and one of the foci is at 0,5√3, then the length of its latus rectum is: (1) 6 (2) 10 (3) 8 (4) 5

201908 Apr Shift 2Ellipses
MathsMedium

Q70.If the line x βˆ’2y = 12 is a tangent to the ellipse x2 + = 1 at the point (3, βˆ’92 ), then the length of the a2 b2 latus rectum of the ellipse is (1) 5 units (2) 12√2 units (3) 9 units (4) 8√3 units 5x = 4√5

201910 Apr Shift 1Ellipses
MathsMedium

Q70.If a circle C passing through the point (4, 0) touches the circle x2 + y2 + 4x βˆ’6y = 12 externally at the point (1, βˆ’1), then the radius of C is: (1) 4 units (2) 5 units (3) 2√5 units (4) √57 units

201910 Jan Shift 1Circles
MathsMedium

Q70.If one end of a focal chord of the parabola, y2 = 16x is at (1, 4), then the length of this focal chord is (1) 24 (2) 25 (3) 22 (4) 20 , then a value of m is:

201909 Apr Shift 1Parabola
MathsMedium

Q70.Let C1 and C2 be the centres of the circles x2 + y2 βˆ’2x βˆ’2y βˆ’2 = 0 and x2 + y2 βˆ’6x βˆ’6y + 14 = 0 respectively. If P and Q are the points of intersection of these circles, then the area (in sq. units) of the quadrilateral PC1 QC2 is : JEE Main 2019 (12 Jan Shift 1) JEE Main Previous Year Paper (1) 6 (2) 4 (3) 8 (4) 9

201912 Jan Shift 1Circles
MathsMedium

Q70.A circle touching the xβˆ’ axis at (3, 0) and making an intercept of length 8 on the yβˆ’ axis passes through the point: (1) (3, 10) (2) (2, 3) (3) (3, 5) (4) (1, 5)

201912 Apr Shift 2Circles
MathsMedium

Q70.The common tangent to the circles x2 + y2 = 4 and x2 + y2 + 6x + 8y βˆ’24 = 0 also passes through the point: (1) (4, βˆ’2) (2) (βˆ’4, 6) (3) (6, βˆ’2) (4) (βˆ’6, 4) JEE Main 2019 (09 Apr Shift 2) JEE Main Previous Year Paper

201909 Apr Shift 2Circles
MathsMedium

Q70.Two circles with equal radii are intersecting at the points (0,1) and (0,-1) . The tangent at the point (0,1) to one of the circles passes through the centre of the other circle. Then the distance between the centres of these circles is: (1) 1 (2) 2 (3) 2√2 (4) √2

201911 Jan Shift 1Circles
MathsMedium

Q71.Let S and S β€² be the foci of an ellipse and B be any one of the extremities of its minor axis. If Ξ”S β€²BS is a right angled triangle with right angle at B and area (Ξ”S β€²BS) = 8 sq. units, then the length of a latus rectum of the ellipse is : (1) 2√2 (2) 2 (3) 4 (4) 4√2 Q72. βˆšΟ€βˆ’βˆš2 sinβˆ’1 x lim is equal to xβ†’1βˆ’ √1βˆ’x (1) βˆšΟ€ (2) √2Ο€ (3) 1 (4) βˆšΟ€2 √2Ο€

201912 Jan Shift 2Ellipse
MathsMedium

Q71.If the tangents on the ellipse 4π‘₯2 + 𝑦2 = 8 at the points 1, 2 and ( π‘Ž, 𝑏) are perpendicular to each other, then π‘Ž2 is equal to (1) 2 (2) 4 (3) 64 (4) 128 17 17 17 17

201908 Apr Shift 1Ellipse
MathsMedium

Q71.If the line y = mx + 7√3 is normal to the hyperbola x224 βˆ’y218 = 1 (1) √5 (2) 3 2 √5 (3) √15 (4) 2 2 √5

201909 Apr Shift 1Hyperbola
MathsMedium

Q71.The straight line x + 2y = 1 meets the coordinate axes at A and B. A circle is drawn through A, B and the origin. Then the sum of perpendicular distances from A and B on the tangent to the circle at the origin is: (1) √5 (2) 2√5 2 (3) √5 (4) 4√5 4

201911 Jan Shift 1Circles
MathsMedium

Q71.If the circles x2 + y2 βˆ’16x βˆ’20y + 164 = r2 and (x βˆ’4)2 + (y βˆ’7)2 = 36 intersect at two distinct points, then: (1) r > 11 (2) 0 < r < 1 (3) 1 < r < 11 (4) r = 11

201909 Jan Shift 2Circles
MathsMedium

Q71.Equation of a common tangent to the circle, π‘₯2 + 𝑦2 - 6π‘₯= 0 and the parabola, 𝑦2 = 4π‘₯ is: (1) 2√3𝑦= - π‘₯- 12 (2) √3𝑦= π‘₯+ 3 (3) √3𝑦= 3π‘₯+ 1 (4) 2√3𝑦= 12π‘₯+ 1

201909 Jan Shift 1Parabola
MathsMedium

Q71.If a directrix of a hyperbola centered at the origin and passing through the point (4, βˆ’2√3) is and its eccentricity is e, then: (1) 4e4 + 8e2 βˆ’35 = 0 (2) 4e4 βˆ’24e2 + 35 = 0 (3) 4e4 βˆ’24e2 + 27 = 0 (4) 4e4 βˆ’12e2 βˆ’27 = 0 x4βˆ’1

201910 Apr Shift 1Hyperbola
MathsMedium

Q71.If the eccentricity of the standard hyperbola passing through the point ( 4,6 ) is 2, then the equation of the tangent to the hyperbola at ( 4,6 ) is: (1) 2π‘₯- 3𝑦+ 10 = 0 (2) π‘₯- 2𝑦+ 8 = 0 (3) 3π‘₯- 2𝑦= 0 (4) 2π‘₯- 𝑦- 2 = 0 1 1 + 𝑓3 + π‘₯- 𝑓3 π‘₯

201908 Apr Shift 2Hyperbola
MathsMedium

Q71.The tangents to the curve y = (x βˆ’2)2 βˆ’1 at its points of intersection with the line x βˆ’y = 3, intersect at the point: (1) ( 25 , 1) (2) ( 52 , βˆ’1) (3) (βˆ’52 , βˆ’1) (4) (βˆ’52 , 1)

201912 Apr Shift 2Applications of Derivatives
MathsMedium

Q71. limx→0 x cot(4x) is equal to: sin2 x cot2(2x) JEE Main 2019 (11 Jan Shift 2) JEE Main Previous Year Paper (1) 0 (2) 2 (3) 4 (4) 1

201911 Jan Shift 2Limits & Continuity
MathsMedium

Q71.The tangent and normal to the ellipse 3π‘₯2 + 5𝑦2 = 32 at the point 𝑃2, 2 meet the π‘₯-axis at 𝑄 and 𝑅, respectively. Then the area (in sq. units) of the triangle 𝑃𝑄𝑅 is: 68 16 (1) (2) 15 3 (3) 14 (4) 34 3 15

201910 Apr Shift 2Applications of Derivatives
MathsMedium

Q72.If the mean and standard deviation of 5 observations x1, x2, x3, x4, x5 are 10 and 3, respectively, then the variance of 6 observations x1, x2, … , x5 and βˆ’50 is equal to (1) 582.5 (2) 507.5 (3) 509.5 (4) 586.5

201910 Jan Shift 2Statistics
MathsMedium

Q72.Let 𝑓: 𝑅→𝑅 be a differentiable function satisfying 𝑓'3 + 𝑓'2 = 0 . Then lim is equal to π‘₯β†’0 1 + 𝑓2 - π‘₯- 𝑓2 (1) 1 (2) e (3) 𝑒2 (4) e-1

201908 Apr Shift 2Limits & Continuity
MathsMedium

Q72.The equation of a tangent to the hyperbola, 4x2 βˆ’5y2 = 20, parallel to the line x βˆ’y = 2, is (1) x βˆ’y + 7 = 0 (2) x βˆ’y βˆ’3 = 0 (3) x βˆ’y + 1 = 0 (4) x βˆ’y + 9 = 0 (1βˆ’|x|+sin|1βˆ’x|)sin([1βˆ’x] Ο€2 )

201910 Jan Shift 1Hyperbola
MathsMedium

Q72.An ellipse, with foci at (0,2) and (0, βˆ’2) and minor axis of length 4 , passes through which of the following points? (1) (1, 2√2) (2) (2, √2) (3) (√2, 2) (4) (2, 2√2)

201912 Apr Shift 2Ellipses
MathsMedium

Q72. lim sin2π‘₯ equals π‘₯β†’0 √2 - √1 + cosπ‘₯ (1) 4√2 (2) 2√2 (3) √2 (4) 4

201908 Apr Shift 1Limits & Continuity
MathsMedium

Q72.If x3βˆ’k3 , then k is lim lim xβˆ’1 = x2βˆ’k2 xβ†’1 xβ†’k (1) 3 (2) 4 2 3 (3) 3 (4) 8 8 3

201910 Apr Shift 1Limits & Continuity
MathsMedium

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