Practice Questions
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Q21.If βa and βb makes an angle cosβ1 ( 9 ) with each other, then |βa + βb| = β2|βa ββb| value of n is ____
Q61.The sum of all the solutions of the equation (8)2x β16 β (8)x + 48 = 0 is : (1) 1 + log8(6) (2) 1 + log6(8) (3) log8(6) (4) log8(4) βz+1 1
Q61.Let S1 = {z βC : |z| β€5}, S2 = {z ( z+1ββ3i1ββ3i ) β₯0} area of the region S1 β©S2 β©S3 is : (1) 125Ο (2) 125Ο 12 4 (3) 125Ο (4) 125Ο 24 6 Q62.60 words can be made using all the letters of the word BHBJO, with or without meaning. If these words are written as in a dictionary, then the 50th word is : (1) JBBOH (2) OBBJH (3) OBBHJ (4) HBBJO
Q61.If z = 21 β2i, is such that z + 1 = Ξ±z + Ξ²(1 i), (1) β4 (2) 3 (3) 2 (4) β1
Q61.The number of solutions, of the equation πsinπ₯β2πβsinπ₯= 2 is (1) 2 (2) more than 2 (3) 1 (4) 0
Q61.Let Ξ±, Ξ²; Ξ± > Ξ² , be the roots of the equation x2 ββ2x ββ3 = 0. Let Pn = Ξ±n βΞ²n, n βN . Then (11β3 β10β2)P10 + (11β2 + 10)P11 β11P12 is equal to (1) 10β3P9 (2) 11β3P9 (3) 10β2P9 (4) 11β2P9
Q61.Let π be the set of positive integral values of π for which ππ₯2 + 2π+ 1π₯+ 9π+ 4 < 0, βπ₯ββ. Then, the number π₯2 - 8π₯+ 32 of elements in π is: (1) 1 (2) 0 (3) β (4) 3
Q61.If z1, z2 are two distinct complex number such that z1β2z21 = 2, then 2 βz1Β―z2 (1) z1 lies on a circle of radius 21 and z2 lies on a (2) both z1 and z2 lie on the same circle. both z1 and circle of radius 1 . z2 lie on the same circle. (3) either z1 lies on a circle of radius 21 or z2 lies on (4) either z1 lies on a circle of radius 1 or z2 lies on a a circle of radius 1 . circle of radius 1 . 2
Q61.Let Ξ±, Ξ² be the roots of the equation x2 + 2β2x β1 = 0. The quadratic equation, whose roots are Ξ±4 + Ξ²4 and 1 (Ξ±6 + Ξ²6), is : 10 (1) x2 β190x + 9466 = 0 (2) x2 β180x + 9506 = 0 (3) x2 β195x + 9506 = 0 (4) x2 β195x + 9466 = 0
Q61.Let r and ΞΈ respectively be the modulus and amplitude of the complex number z = 2 βi(2 tan 5Ο8 ), then (r, ΞΈ) is equal to (1) (2 sec 3Ο8 , 3Ο8 ) (2) (2 sec 3Ο8 , 5Ο8 ) (3) (2 sec 5Ο8 , 3Ο8 ) (4) (2 sec 11Ο8 , 11Ο8 )
Q61.If S = z βC : |z βi| = |z + i| = |z β1|, then, n(S) is: (1) 1 (2) 0 (3) 3 (4) 2
Q61.Let π= π₯βπ : β3 + β2 π₯+ β3 ββ2 π₯= 10. Then the number of elements in π is: (1) 4 (2) 0 (3) 2 (4) 1
Q61.Let Ξ±, Ξ² be the distinct roots of the equation x2 β(t2 β5t + 6)x + 1 = 0, t βR and an = Ξ±n + Ξ²n . Then the minimum value of a2023+a2025 is a2024 (1) β1/4 (2) β1/4 (3) β1/2 (4) 1/4
Q61.Let πΌ and π½ be the roots of the equation ππ₯2 + ππ₯βπ= 0, where πβ 0. If π, π and π be the consecutive terms of a non-constant G.P and 1 1 3 then the value of πΌβπ½2 is: πΌ+ π½= 4, (1) 80 (2) 9 9 20 (3) (4) 8 3
Q62.The number of common terms in the progressions 4, 9, 14, 19, β¦ β¦, up to 25th term and 3, 6, 9, 12,.... up to 37th term is : (1) 9 (2) 5 (3) 7 (4) 8 n
Q62.If π§ is a complex number such that π§β€1, then the minimum value of π§+ 1 + 4π is: 23 5 (1) 2 (2) 2 3 (3) (4) 3 2
Q62.Number of ways of arranging 8 identical books into 4 identical shelves where any number of shelves may remain empty is equal to (1) 18 (2) 16 (3) 12 (4) 15
Q62.Let π= π§βπΆ: π§β1 = 1 and β2 β1π§+ Β―π§- ππ§- Β―π§= 2β2. Let π§1, π§2 βπ be such that π§1 = maxπ§βπ π§ and 2 π§2 = minπ§βπ π§. Then β2π§1 βπ§2 equals: (1) 1 (2) 4 (3) 3 (4) 2
Q62.Let Ξ± and Ξ² be the sum and the product of all the non-zero solutions of the equation (Β―z)2 + |z| = 0, z β C. Then 4 (Ξ±2 + Ξ²2) is equal to : (1) 6 (2) 8 (3) 2 (4) 4
Q62.For 0 < π< π< π, let ( π+ πβ 2π) π₯2 + ( π+ πβ 2π) π₯+ ( π+ πβ 2π) = 0 and πΌβ 1 be one of its root. Then, among the two statements (I) If πΌβ-1, 0, then π cannot be the geometric mean of π and π. (II) If πΌβ0, 1, then π may be the geometric mean of π and π. (1) Both (I) and (II) are true (2) Neither (I) nor (II) is true (3) Only (II) is true (4) Only (I) is true 1 2 3
Q62.Let z be a complex number such that the real part of zβ2i is zero. Then, the maximum value of |z β(6 + 8i)| z+2i is equal to (1) 12 (2) 10 (3) 8 (4) β
Q62.Let z be a complex number such that |z + 2| = 1 and Im ( z+2 ) = 5 . Then the value of |Re(z + 2)| is (1) 2β6 (2) 24 5 5 (3) 1+β6 (4) β6 5 5
Q62.The number of ways five alphabets can be chosen from the alphabets of the word MATHEMATICS, where the chosen alphabets are not necessarily distinct, is equal to : (1) 179 (2) 177 (3) 181 (4) 175
Q62.If the sum of the series 1 + 1 + β¦ + 1 is equal to 5 , then 50 d is equal to : 1β (1+d) (1+d)(1+2 d) (1+9 d)(1+10 d) (1) 10 (2) 5 (3) 15 (4) 20
Q62.Let π§1 and π§2 be two complex number such that π§1 + π§2 = 5 and π§13 + π§23 = 20 + 15π. Then π§14 + π§24 equals- (1) 30β3 (2) 75 (3) 15β15 (4) 25β3