Practice Questions
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Q72.Let π: π βπ and π: π βπ be defined as ππ₯= logππ₯, π₯> 0 and ππ₯= π₯, π₯β₯0 . Then, πππ: π βπ is: πβπ₯, π₯β€0 ππ₯, π₯< 0 (1) one-one but not onto (2) neither one-one nor onto (3) onto but not one-one (4) both one-one and onto
Q72.Let the sum of the maximum and the minimum values of the function f(x) = 2x2+3x+82x2β3x+8 be mn , where gcd(m, n) = 1. Then m + n is equal to : (1) 195 (2) 201 (3) 217 (4) 182 2x , x < 0
Q72.Let the range of the function f(x) = 2+sin 3x+cos1 3x , x βR be [a, b]. If Ξ± and Ξ² are respectively the A.M. and the G.M. of a and b, then Ξ±Ξ² is equal to (1) Ο (2) βΟ (3) 2 (4) β2
Q72.Given that the inverse trigonometric function assumes principal values only. Let x, y be any two real numbers in [β1, 1] such that cosβ1 x βsinβ1 y = Ξ±, βΟ2 β€Ξ± β€Ο. Then, the minimum value of x2 + y2 + 2xy sin Ξ± is (1) 0 (2) -1 (3) 1 2 (4) β12 72xβ9xβ8x+1
Q72.A variable line L passes through the point (3, 5) and intersects the positive coordinate axes at the points A and B. The minimum area of the triangle OAB, where O is the origin, is : (1) 30 (2) 25 (3) 40 (4) 35
Q72.If the domain of the function ππ₯= βπ₯2 β25 + + 2π₯β15 is ββ, πΌβͺπ½, β, then πΌ2 + π½3 is equal to: 4 βπ₯2 log10π₯2 (1) 140 (2) 175 (3) 150 (4) 125
Q72.If the function f(x) = sin 3x+Ξ± sin xβΞ² cos 3x , x βR , is continuous at x = 0 , then f(0) is equal to : x3 (1) 2 (2) -2 (3) 4 (4) -4
Q72.The number of critical points of the function f(x) = (x β2)2/3(2x + 1) is (1) 1 (2) 2 (3) 0 (4) 3 6
Q72.Consider the function f : [ 12 , 1] βR defined by f(x) = 4β2x3 β3β2x β1. Consider the statements (I) The curve y = f(x) intersects the x-axis exactly at one point (II) The curve y = f(x) intersects the x-axis at x = cos 12Ο Then (1) Only (II) is correct (2) Both (I) and (II) are incorrect (3) Only (I) is correct (4) Both (I) and (II) are correct
Q72.Let f : [β1, 2] βR be given by f(x) = 2x2 + x + [x2] β[x], where [t] denotes the greatest integer less than or equal to t. The number of points, where f is not continuous, is : (1) 5 (2) 6 (3) 3 (4) 4
Q72.The function f: R->R, f(x) = x2+2xβ15 , x βR is x2β4x+9 (1) one-one but not onto. (2) both one-one and onto. (3) onto but not one-one. (4) neither one-one nor onto. JEE Main 2024 (06 Apr Shift 1) JEE Main Previous Year Paper 1 ), x β 0 x then
Q72.Suppose for a differentiable function h, h(0) = 0, h(1) = 1 and hβ²(0) = hβ²(1) = 2. If g(x) = h (ex)eh(x) , then gβ²(0) is equal to: (1) 5 (2) 4 (3) 8 (4) 3
Q72.If the domain of the function f(x) = cosβ1( 2β|x|4 ) equal to : (1) 12 (2) 9 (3) 11 (4) 8
Q72.Let a and b be real constants such that the function π defined by ππ₯= π₯2 + 3π₯+ π, π₯β€1 be differentiable ππ₯+ 2, π₯> 1 2 on π . Then, the value of β«-2 ππ₯ππ₯ equals 15 19 (1) (2) 6 6 (3) 21 (4) 17
Q72.If π= sinβ1sin5 and π= cosβ1cos5, then π2 + π2 is equal to (1) 4π2 + 25 (2) 8π2 β40π+ 50 (3) 4π2 β20π+ 50 (4) 25
Q72.Let y = loge( 1βx21+x2 ), (1) 732 (2) 746 (3) 742 (4) 736
Q73.Suppose f(x) = (2x+2βx) tan xβtanβ1(x2βx+1) . Then the value of f β²(0) is equal to (7x2+3x+1)3 (1) Ο (2) 0 (3) βΟ (4) Ο2 Ο + = 4 ( Ο + a) β2, then the value of a is
Q73.Let g : R βR be a non constant twice differentiable such that gβ²( 21 ) = gβ²( 23 ). If a real valued function f is defined as f(x) = 12 [ g(x) + g(2 βx)], then (1) f β²β²(x) = 0 for atleast two x in (0, 2) (2) f β²β²(x) = 0 for exactly one x in (0, 1) (3) f β²β²(x) = 0 for no x in (0, 1) (4) f β²( 23 ) + f β²( 21 ) = 1
Q73.Let π: π - {0} βπ be a function satisfying π π₯ π( π₯) for all π₯, π¦, π( π¦) β 0. If π' (1) = 2024, then π¦= π( π¦) (1) π₯π'π₯- 2024ππ₯= 0 (2) π₯π'π₯+ 2024ππ₯= 0 (3) π₯' (π₯) + π(π₯) = 2024 (4) π₯π' (π₯) - 2023π(π₯) = 0
Q73.If the function π: ββ, β1 βπ, π defined by ππ₯= ππ₯3 β3π₯+ 1 is one-one and onto, then the distance of the point π2π+ 4, π+ 2 from the line π₯+ πβ3π¦= 4 is: (1) 2β1 + π6 (2) 4β1 + π6 (3) 3β1 + π6 (4) β1 + π6 JEE Main 2024 (31 Jan Shift 2) JEE Main Previous Year Paper
Q73.Let I(x) = β« dx. If I(0) = 3, then I ( 12Ο ) is equal to sin2 x(1βcot x)2 JEE Main 2024 (08 Apr Shift 1) JEE Main Previous Year Paper (1) 2β3 (2) β3 (3) 3β3 (4) 6β3 n βN, satisfies 147I20 = 148I21 is
Q73.If the function f(x) = 2x3 β9x2 + 12a2x + 1, a > 0 has a local maximum at x = Ξ± and a local minimum at x = Ξ±2 , then Ξ± and Ξ±2 are the roots of the equation : JEE Main 2024 (08 Apr Shift 2) JEE Main Previous Year Paper (1) x2 β6x + 8 = 0 (2) x2 + 6x + 8 = 0 (3) 8x2 + 6x β1 = 0 (4) 8x2 β6x + 1 = 0 = Ο6 . Then eΞ± and eβΞ± are the roots of the equation :
Q73.Let β«2βtan3+tan xx dx = 12 (Ξ±x + loge |Ξ² sin x + Ξ³ cos x|) + C , where C is the constant of integration. Then Ξ± + Ξ²Ξ³ is equal to : (1) 7 (2) 4 (3) 1 (4) 3
Q73.If loge y = 3 sinβ1 x, then (1 βx2)yβ²β² βxyβ² at x = 12 is equal to (1) 3eΟ/6 (2) 9eΟ/2 (3) 3eΟ/2 (4) 9eΟ/6 y β₯0, y(0) = 0. Then at x = 2, yβ²β² + y + 1 is equal to
Q73.The function f : N β{1} βN; defined by f(n) = the highest prime factor of n, is : (1) both one-one and onto (2) one-one only (3) onto only (4) neither one-one nor onto JEE Main 2024 (27 Jan Shift 1) JEE Main Previous Year Paper Q74. , x < 3 β§ a(7xβ12βx2)b|x2β7x+12| Consider the function f(x) = sin(xβ3) ,where [x] denotes the greatest integer less than or equal xβ[x] β¨ 2 , x > 3 β© b , x = 3 to x . If S denotes the set of all ordered pairs (a, b) such that f(x) is continuous at x = 3, then the number of elements in S is : (1) 2 (2) Infinitely many (3) 4 (4) 1 dx = a + bβ2 + cβ3, where a, b, c are rational numbers, then 2a + 3 b β4c is equal to :