Practice Questions
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Q61.The area of the polygon, whose vertices are the non-real roots of the equation z = iz2 is (1) 3β3 (2) 3β3 2 4 (3) β3 (4) β3 4 2
Q61.The minimum value of the sum of the squares of the roots of π₯2 + 3 - ππ₯= 2π- 1 is (1) 6 (2) 4 (3) 5 (4) 8
Q61.Let a circle πΆ in complex plane pass through the points π§1 = 3 + 4π, π§2 = 4 + 3π and π§3 = 5π. If π§β π§1 is a point on πΆ such that the line through π§ and π§1 is perpendicular to the line through π§2 and π§3, then argπ§ is equal to 2 (1) tan-124 - π (2) tan-1 - π 7 β5 (3) tan-13 - π (4) tan-13 - π 4 JEE Main 2022 (25 Jun Shift 1) JEE Main Previous Year Paper 1 1 1 πΎ
Q61.The sum of all real roots of equation (e2x β4)(6e2x β5ex + 1) = 0 is (1) ln 4 (2) βln 3 (3) ln 3 (4) ln 5
Q61.For z βC if the minimum value of ( z β3β2 + z βpβ2i ) is 5β2 , then a value of (1) 3 (2) 72 (3) 4 (4) 92
Q61.If the sum of the squares of the reciprocals of the roots Ξ± and Ξ² of the equation 3x2 + Ξ»x β1 = 0 is 15 , then 6(Ξ±3 + Ξ²3)2 is equal to (1) 46 (2) 36 (3) 24 (4) 18
Q61.If πΌ, π½, πΎ, πΏ are the roots of the equation π₯4 + π₯3 + π₯2 + π₯+ 1 = 0, then πΌ2021 + π½2021 + πΎ2021 + πΏ2021 is equal to (1) 4 (2) 1 (3) -4 (4) -1
Q61.Let π΄= π₯βπ : π₯+ 1 < 2 and π΅= π₯βπ : π₯- 1 β₯2. Then which one the following statements is NOT true? (1) π΄- π΅= -1, 1 (2) π΅- π΄= π - -3, 1 (3) π΄β©π΅= ( - 3, - 1] (4) π΄βͺπ΅= π - [1, 3 )
Q61.The number of points of intersection |z β(4 + 3i)| = 2| and |z| + |z β4| = 6, z βC is (1) 1 (2) 2 (3) 3 (4) 4
Q61.The total number of 5-digit numbers, formed by using the digits 1, 2, 3, 5, 6, 7 without repetition, which are multiple of 6, is (1) 72 (2) 48 (3) 24 (4) 60
Q61.If z = 2 + 3i, then z5 + (z)5 is equal to: (1) 244 (2) 224 (3) 245 (4) 265
Q61.If Ξ±, Ξ² are the roots of the equation x2 β(5 + 3βlog3 β5βlog5 3)x 3(3(log3 β1) the equation, whose roots are Ξ± + Ξ²1 and Ξ² + Ξ±1 , (1) 3x2 β20x β12 = 0 (2) 3x2 β10x β4 = 0 (3) 3x2 β10x + 2 = 0 (4) 3x2 β20x + 16 = 0
Q61.Let π1 = π§1 βπΆ: π§1 - 3 = 2 and π2 = π§2 βπΆ: π§2 - π§2 + 1 = π§2 + π§2 - 1 . Then, for π§1 βπ1 and π§2 βπ2, the least value of π§2 - π§1 is (1) 0 (2) 1 2 3 5 (3) (4) 2 2
Q61.Let Ξ± and Ξ² be the roots of the equation x2 + (2i β1) = 0 . Then, the value of Ξ±8 + Ξ²8 is equal to (1) 50 (2) 250 (3) 1250 (4) 1550
Q61.If A = ββn=1 (3+(β1)n)n and B = ββn=1 (3+(β1)n)n , then B is equal to (1) 11 (2) 1 9 (3) β119 (4) β113 Q62. 16 sin(20Β°) sin(40Β°) sin(80Β°) is equal to (1) β3 (2) 2β3 (3) 3 (4) 4β3 y2
Q62.If π§= π₯+ ππ¦ satisfies π§- 2 = 0 and π§- π- π§+ 5π= 0, then (1) π₯+ 2π¦- 4 = 0 (2) π₯2 + π¦- 4 = 0 (3) π₯+ 2π¦+ 4 = 0 (4) π₯2 - π¦+ 3 = 0 Q63. βπ,π π= 0 ππΆπ ππΆπ is equal to πβ π (1) 22π- 2ππΆπ (2) 22π- 1 - 2π- 1πΆπ- 1 1 1 2π- (3) 22π- 2 2ππΆπ (4) 2π- + 1πΆπ
Q62.If the minimum value of ππ₯= 5π₯2 + πΌ π₯> 0, is 14, then the value of πΌ is equal to 2 π₯5, (1) 32 (2) 64 (3) 128 (4) 256 2
Q62.For πβπ, let ππ= π§βπΆ: π§- 3 + 2π= π and ππ= π§βπΆ: π§- 2 + 3π= 1 Then the number of elements in the 4 π. set πβπ: ππβ©ππ= π is (1) 0 (2) 2 (3) 3 (4) 4
Q62.Let x, y > 0 . If x3y2 = 215 , then the least value of 3x + 2y is JEE Main 2022 (24 Jun Shift 2) JEE Main Previous Year Paper (1) 30 (2) 32 (3) 36 (4) 40
Q62.Let (z) represent the principal argument of the complex number z. The, |z| = 3 and arg(z β1) βarg(z + 1) = Ο4 intersect: (1) Exactly at one point (2) Exactly at two points (3) Nowhere (4) At infinitely many points.
Q62.If x = ββn=0 an, y = ββn=0 bn, z = ββn=0 cn , where a, b, c are in A.P. and |a| < 1, |b| < 1, |c| < 1, abc β 0, then (1) x, y, z are in A.P. (2) x, y, z are in G.P. (3) x 1 , 1y , 1z are in A.P. (4) x1 + 1y + 1z = 1 β(a + b + c)
Q62.Let {an}βn=0 be a sequence such that a0 = a1 = 0 and an+2 = 2an+1 βan + 1 for all n β₯0 . Then, ββn=2 an7n is equal to (1) 6 (2) 7 343 216 (3) 8 (4) 49 343 216 5 10
Q62.Suppose a1, a2, β¦ , an, β¦ be an arithmetic progression of natural numbers. If the ratio of the sum of the first five terms to the sum of first nine terms of the progression is 5 : 17 and 110 < a15 < 120 , then the sum of the JEE Main 2022 (27 Jul Shift 1) JEE Main Previous Year Paper first ten terms of the progression is equal to (1) 290 (2) 380 (3) 460 (4) 510
Q62.The number of ways to distribute 30 identical candies among four children C1, C2, C3 and C4 so that C2 receives atleast 4 and atmost 7 candies, C3 receives atleast 2 and atmost 6 candies, is equal to (1) 205 (2) 615 (3) 510 (4) 430 JEE Main 2022 (28 Jun Shift 2) JEE Main Previous Year Paper
Q62.If (20βa)(40βa) 1 + (40βa)(60βa)1 + β¦ β¦ + (180βa)(200βa)1 = 2561 , then the maximum value of a is (1) 198 (2) 202 (3) 212 (4) 218