Practice Questions
14,828 questions across 23 years of JEE Main β find and practise any topic!
Difficulty
Q65.Let the tangent to the parabola S : y2 = 2x at the point P(2, 2) meet the xβaxis at Q and normal at it meet the parabola S at the point R. Then the area (in sq. units) of the triangle PQR is equal to: (1) 25 (2) 35 2 2 (3) 15 (4) 25 2
Q65.In a triangle PQR, the co-ordinates of the points P and Q are (β2, 4) and (4, β2) respectively. If the equation of the perpendicular bisector of PR is 2x βy + 2 = 0, then the centre of the circumcircle of the ΞPQR is: (1) (β1, 0) (2) (β2, β2) (3) (0, 2) (4) (1, 4) JEE Main 2021 (17 Mar Shift 1) JEE Main Previous Year Paper
Q65.The length of the latus rectum of a parabola, whose vertex and focus are on the positive x-axis at a distance R and S(> R) respectively from the origin, is : (1) 2( S βR) (2) 2(S + R) (3) 4(S βR) (4) 4(S + R)
Q65.Let C be the locus of the mirror image of a point on the parabola y2 = 4x with respect to the line y = x. Then the equation of tangent to C at P(2, 1) is : (1) x βy = 1 (2) 2x + y = 5 (3) x + 3y = 5 (4) x + 2y = 4 = 1 and the circle x2 + y2 = 4 b, b > 4 lie on the curve
Q65.Let π΄ be the set of all points πΌ, π½ such that the area of triangle formed by the points 5, 6, 3, 2 and πΌ, π½ is 12 square units. Then the least possible length of a line segment joining the origin to a point in π΄, is : 8 12 (1) (2) β5 β5 (3) 16 (4) 4 β5 β5
Q65.If π is the number of solutions of the equation 2cosπ₯4sin + π₯sin - π₯- 1 = 1, π₯β0, π and π is the sum of all 4 4 these solutions, then the ordered pair π, π is : (1) 2, 8π (2) 3, 13Ο 9 9 2π 5π (3) 2, (4) 3, 3 3 JEE Main 2021 (01 Sep Shift 2) JEE Main Previous Year Paper 1 3 1
Q65.The point P(β2β6, β3) lies on the hyperbola x2a2 βy2b2 normal at P to the hyperbola intersect its conjugate axis at the points Q and R respectively, then QR is equal to: (1) 4β3 (2) 6 (3) 3β6 (4) 6β3
Q65.Let P be a variable point on the parabola y = 4x2 + 1. Then, the locus of the mid-point of the point P and the foot of the perpendicular drawn from the point P to the line y = x is: (1) (3x βy)2 + (x β3y) + 2 = 0 (2) 2(3x βy)2 + (x β3y) + 2 = 0 (3) (3x βy)2 + 2(x β3y) + 2 = 0 (4) 2(x β3y)2 + (3x βy) + 2 = 0
Q65.The value of -15πΆ1 + 2 Β· 15πΆ2 - 3 Β·15 πΆ3 + . . . . . - 15 Β· 15πΆ15 + 14πΆ1 + 14πΆ3 + 14πΆ5 + . . . . + 14πΆ11 is equal to (1) 214 (2) 213 - 13 (3) 216 - 1 (4) 213 - 14
Q65.For the statements p and q, consider the following compound statements: (a) (~q β§(p βq)) β~p (b) ((p β¨q) β§~p) βq Then which of the following statements is correct? (1) (b) is a tautology but not (a). (2) (a) and (b) both are tautologies. (3) (a) and (b) both are not tautologies. (4) (a) is a tautology but not (b).
Q65.Let E1 : x2a2 + y2b2 and the foci of E2 are the end points of minor axis of E1. If E1 and E2 have same eccentricities, then its value is: (1) β1+β5 (2) β1+β8 2 2 (3) β1+β3 (4) β1+β6 2 2
Q65.The number of roots of the equation, (81)sin2 x + (81)cos2 x = 30 in the interval [0, Ο] is equal to : JEE Main 2021 (16 Mar Shift 1) JEE Main Previous Year Paper (1) 3 (2) 4 (3) 8 (4) 2
Q65.Two tangents are drawn from the point P(β1, 1) to the circle x2 + y2 β2x β6y + 6 = 0. If these tangents touch the circle at points A and B, and if D is a point on the circle such that length of the segments AB and AD are equal, then the area of the triangle ABD is equal to: + (1) 2 (2) (3β2 2) (3) 4 (4) 3(β2 β1)
Q65.The intersection of three lines x βy = 0, x + 2y = 3 and 2x + y = 6 is a/an (1) Isosceles triangle (2) Equilateral triangle (3) Right angled triangle (4) None of the above
Q65.If the curve x2 + 2y2 = 2 intersects the line x + y = 1 at two points P and Q , then the angle subtended by the line segment PQ at the origin is (1) Ο 2 βtanβ1( 31 ) (2) Ο2 + tanβ1( 31 ) (3) Ο 2 + tanβ1( 41 ) (4) Ο2 βtanβ1( 41 ) y2
Q65.Let S1 : x2 + y2 = 9 and S2 : (x β2)2 + y2 = 1 . JEE Main 2021 (18 Mar Shift 2) JEE Main Previous Year Paper Then the locus of center of a variable circle S which touches S1 internally and S2 externally always passes through the points : (1) (0, Β±β3) (2) ( 12 , Β± β52 ) (3) (2, Β± 32 ) (4) (1, Β±2)
Q66.The Boolean expression (p β§~q) β(q β¨~p) is equivalent to: (1) q βp (2) p βq (3) ~q βp (4) p β~q
Q66.The value of cot 24Ο is: (1) β2 + β3 + 2 ββ6 (2) β2 + β3 + 2 + β6 (3) β2 ββ3 β2 + β6 (4) 3β2 ββ3 ββ6 JEE Main 2021 (25 Jul Shift 2) JEE Main Previous Year Paper
Q66.The line 2x βy + 1 = 0 is a tangent to the circle at the point (2, 5) and the centre of the circle lies on x β2y = 4. Then, the radius of the circle is: (1) 3β5 (2) 5β3 (3) 5β4 (4) 4β5
Q66.The Boolean expression (p β§q) β((r β§q) β§p) is equivalent to: (1) (p β§r) β(p β§q) (2) (q β§r) β(p β§q) (3) (p β§q) β(r β§q) (4) (p β§q) β(r β¨q)
Q66.The locus of the centroid of the triangle formed by any point π on the hyperbola 16π₯2 - 9π¦2 + 32π₯+ 36π¦- 164 = 0 and its foci is (1) 16π₯2 - 9π¦2 + 32π₯+ 36π¦- 36 = 0 (2) 9π₯2 - 16π¦2 + 36π₯+ 32π¦- 144 = 0 (3) 16π₯2 - 9π¦2 + 32π₯+ 36π¦- 144 = 0 (4) 9π₯2 - 16π¦2 + 36π₯+ 32π¦- 36 = 0
Q66.Let P and Q be two distinct points on a circle which has center at C(2, 3) and which passes through origin O. If OC is perpendicular to both the line segments CP and CQ, then the set {P, Q} is equal to 3 + (1) {(4, 0), (0, 6)} (2) {(2 + 2β2, 3 ββ5), (2 β2β2, β5)} + 2β2, 3 + β2β2, 3 (3) {(2 β5), (2 ββ5)} (4) {(β1, 5), (5, 1)}
Q66.The angle of elevation of a jet plane from a point A on the ground is 60Β°. After a flight of 20 seconds at the speed of 432 km / hour, the angle of elevation changes to 30Β°. If the jet plane is flying at a constant height, then its height is: (1) 1200β3 m (2) 2400β3 m (3) 1800β3 m (4) 3600β3 m
Q66.If the points of intersection of the ellipse x216 + y2b2 y2 = 3x2 , then b is equal to : (1) 12 (2) 5 (3) 6 (4) 10
Q66.If the three normals drawn to the parabola, y2 = 2x pass through the point (a, 0), a β 0, then a must be greater than : (1) 1 2 (2) β12 (3) β1 (4) 1