Practice Questions

Q35.Gibbs energy vs T plot for the formation of oxides is given below. For the given diagram, the correct statement is- (1) At 600°C, CO cannot reduce FeO (2) At 600°C, CO can reduce ZnO (3) At 600°C, C can reduce ZnO (4) At 600°C, C can reduce FeO

Q35.At 298 K N2(g) + 3H2(g) ⇌2 NH3(g), K1 = 4 × 105 N2(g) + O2(g) ⇌2 NO(g), K2 = 1. 6 × 1012 H2(g) + 12 O2(g) ⇌H2O(g), K3 = 1. 0 × 10−13 Based on above equilibria, the equilibrium constant of the reaction, 2 NH3(g) + 25 O2( g) ⇌2 NO(g) + 3H2O(g) is _____ ×10−33 (Nearest integer)

Q35.But-2-yne is reacted separately with one mole of Hydrogen as shown below: Na Pd / C ← B CH3 - C ≡ C - CH3 →∆ A¯ ¯ liq NH3 +H2 Identify the incorrect statements from the options given below: A. A is more soluble than B. B. The boiling point & melting point of A are higher and lower than B respectively. C. A is more polar than B because dipole moment of A is zero. D. Br2 adds easily to B than A. (1) B and C only (2) B, C and D only (3) A, C and D only (4) A and B only

Q35.Consider the following reaction approaching equilibrium at 27°C and 1 atm pressure Kt=03 A + B ⇌ C + D Kr=102 The standard Gibb's energy change (ΔrG°) at 27°C is (−) _____ kJmol−1 (Nearest integer). (Given : R = 8. 3J K−1 mol−1 and ln 10 = 2. 3 )

Q35.Given below are two statements: Statement I: SbCl5 is more covalent than SbCl3 Statement II: The higher oxides of halogens also tend to be more stable than the lower ones. In the light of the above statements, choose the most appropriate answer from the options given below. (1) Statement I is incorrect but statement II is correct (2) Both Statement I and Statement II are incorrect (3) Both Statement I and Statement II are correct (4) Statement I is correct but statement II is incorrect

Q35.Lithium aluminium hydride can be prepared from the reaction of (1) LiCl and Al2H6 (2) LiH and Al2Cl6 (3) LiCl, Al and H2 (4) LiH and AlOH3

Q35.Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R: Assertion (A) : BeCl2 and MgCl2 produce characteristic flame JEE Main 2023 (15 Apr Shift 1) JEE Main Previous Year Paper Reason (R) : The excitation energy is high in BeCl2 and MgCl2 In the light of the above statements, choose the correct answer from the options given below: (1) (A) is true but (R) is false (2) Both (A) and (R) are true but (R) is NOT the correct explanation of (A) (3) Both ( (A) and (R) are true and (R) is the correct (4) (A) is false but (R) is true explanation of (A)

Q35.Reaction of BeO with ammonia and hydrogen fluoride gives 'A' which on thermal decomposition gives BeF2 and NH4F. What is 'A' ? (1) H3NBeF3 (2) NH42BeF4 (3) NH4BeF3 (4) NH42Be2F6

Q35.The setting time of Cement is increased by adding (1) Clay (2) Silica (3) Gypsum (4) Limestone

Q35.Given (A) 2COg + O2g →2CO2g ΔH1o = - x kJ mol-1 (B) Cgraphite + O2g →CO2g ΔH2o = - y kJ mol-1 1 The ∆Ho for the reaction Cgraphite + 2O2g →COg is (1) 2x - y (2) x + 2y 2 2 x - 2y (3) (4) 2y - x 2

Q35.Arrange the following gases in increasing order of van der Waals constant ′a′ (A) Ar (B) CH4 (C) H2O (D) C6H6 Choose the correct option from the following. (1) D, C, B and A (2) B, C, D and A (3) C, D, B and A (4) A, B, C and D

Q35.Match List-I with List-II: List-I Species List-II Geometry/Shape A. H3O+ I. Tetrahedral B. Acetylide anion II. Linear C. NH4+ III. Pyramidal D. ClO2- IV. Bent Choose the correct answer from the options given below: (1) A(III), B(IV), C(I), D(II) (2) A(III), B(I), C(II), D(IV) (3) A(III), B(II), C(I), D(IV) (4) A(III), B(IV), C(II), D(I)

Q35. ClF5 at room temperature is a (1) Colourless liquid with trigonal (2) Colourless gas with square pyramidal geometry bipyramidal geometry (3) Colourless gas with trigonal bipyramidal (4) Colourless liquid with square pyramidal geometry geometry

Q35.Amongst the following, the number of species having the linear shape is XeF2, I+3 , C3O2, I−3 , CO2, SO2, BeCl2 and BCl⊖2

Q35.When the hydrogen ion concentration [H+]changes by a factor of 1000 , the value of pH of the solution (1) increases by 1000 units (2) decreases by 3 units (3) decreases by 2 units (4) increases by 2 units

Q35.One mole of an ideal monoatomic gas is subjected to changes as shown in the graph. The magnitude of the work done (by the system or on the system) is _______ J (nearest integer) Given : log 2 = 0.3, ln 10 = 2.3

Q35.The effect of addition of helium gas to the following reaction in equilibrium state at constant volume, is : PCI5( g) ⇌PCl3( g) + Cl2( g) JEE Main 2023 (01 Feb Shift 2) JEE Main Previous Year Paper (1) the equilibrium will shift in the forward direction (2) the equilibrium will go backward due to and more of Cl2 and PCl3 gases will be suppression of dissociation of PCl5 . produced. (3) helium will deactivate PCl5 and reaction will (4) addition of helium will not affect the equilibrium. stop.

Q35.Given below are two statements, one is labelled as Assertion A and the other is labelled as Reason R. Assertion A : Isotopes of hydrogen have almost same chemical properties, but difference in their rates of reactions. Reason R: Isotopes of hydrogen have different enthalpy of bond dissociation. In the light of the above statements, choose the most appropriate answer from the options given below: (1) Both A and R are correct but R is NOT the (2) Both A and R are correct and R is the correct correct explanation of A explanation of A (3) A is not correct but R is correct (4) A is correct but R is not correct

Q35.Consider the following equation: 2 SO2(g) + O2(g) ⇌2 SO3(g), ΔH = −190 kJ. The number of factors which will increase the yield of SO3 at equilibrium from the following is _____ . A. Increasing temperature B. Increasing pressure C. Adding more SO2 D. Adding more O2 E. Addition of catalyst

Q35.The number of following factors which affect the percent covalent character of the ionic bond is______ A) Polarising power of cation B) Extent of distortion of anion C) Polarisability of the anion D) Polarising power of anion

Q35.Match items of column I and II Column I (Mixture of compounds) Column II (Separation Technique) A. H2O / CH2Cl2 i. Crystallization ii. Differential solvent extraction B. C. Kerosene/Naphthalene iii. Column chromatography D. C6H12O6 / NaCl iv. Fractional Distillation (1) A - ( iii ) , B - ( iv ) , C - ( ii ) , D - ( i ) (2) A - ( ii ) , B - ( iii ) , C - ( iv ) , D - ( i ) (3) A - ( i ) , B - ( iii ) , C - ( ii ) , D - ( iv ) (4) A - ( ii ) , B - ( iv ) , C - ( i ) , D - ( iii )

Q35.The maximum number of lone pairs of electron on the central atom from the following species is ...... ClO3−, XeF4, SF4 and l3−

Q36.How can photochemical smog be controlled? (1) By using tall chimneys (2) By complete combustion of fuel (3) By using catalytic converters in (4) By using catalyst the automobiles/industry

Q36.Match List-I with List-II. List-I List-II Element detected Reagent used/Product formed A Nitrogen I Na2FeCN5NO B Sulphur II AgNO3 C Phosphorus III Fe4FeCN63 D Halogen IV NH42MoO4 Choose the correct answer from the options given below: (1) A →III; B →I; C →IV; D →II (2) A →II; B →IV; C →I; D → III (3) A →IV; B →II; C →I; D →III (4) A →II; B →I; C →IV; D →III

Q36.Water decomposes at 2300 K H2O(g) →H2(g) + 12 O2(g) The percent of water decomposing at 2300 K and 1 bar is _____ (Nearest integer). Equilibrium constant for the reaction is 2 × 10−3 at 2300 K