Practice Questions

Q41.A solution of FeCl3 when treated with K4Fe ( CN ) gives a prussian blue precipitate due to the formation of 6 (1) KFe2 ( CN ) (2) FeFe ( CN ) 6 6 (3) Fe3Fe ( CN ) (4) Fe4Fe ( CN ) 62 63

Q41.Given below are two statements: Statement I: Sulphanilic acid gives esterification test for carboxyl group. Statement II: Sulphanilic acid gives red colour in Lassigne’s test for extra element detection. In the light of the above statements, choose the most appropriate answer from the options given below: JEE Main 2023 (01 Feb Shift 2) JEE Main Previous Year Paper (1) Statement I is correct but Statement II is (2) Both Statement I and Statement II are incorrect incorrect. (3) Both Statement I and Statement II are correct (4) Statement I is incorrect but Statement II is correct.

Q41.During the qualitative analysis of SO32 - using dilute H2SO4, SO2 gas is evolved which turns K2Cr2O7 solution (acidified with dilute H2SO4): (1) Black (2) Red (3) Green (4) Blue

Q41.An ammoniacal metal salt solution gives a brilliant red precipitate on addition of dimethylglyoxime. The metal ion is : (1) 𝐶𝑢2 + (2) 𝑁𝑖2 + (3) 𝐹𝑒2 + (4) Co2 +

Q41.Compound from the following that will not produce precipitate on reaction with AgNO3 is JEE Main 2023 (11 Apr Shift 2) JEE Main Previous Year Paper (1) (2) (3) (4)

Q41.Some reactions of NO2 relevant to photochemical smog formation are Identify A, B, X and Y (1) X = [O], Y = NO, A = O2, B = O3 (2) X = N2O, Y = [O], A = O3, B = NO (3) X = 12 O2, Y = NO2, A = O3, B = O2 (4) X = NO, Y = [O], A = O2, B = N2O3 JEE Main 2023 (25 Jan Shift 1) JEE Main Previous Year Paper

Q41.The difference between electron gain enthalpies will be maximum between : (1) Ne and F (2) Ar and F (3) Ne and Cl (4) Ar and Cl

Q41.When 0. 01 mol of an organic compound containing 60% carbon was burnt completely, 4. 4 g of CO2 was produced. The molar mass of compound is _____ gmol−1 (Nearest integer)

Q41.The number of alkali metal(s), from Li, K, Cs, Rb having ionization enthalpy greater than 400 kJ mol−1 and forming stable super oxide is

Q41.Which of the following can reduce decomposition of H2O2 on exposure to light (1) Urea (2) Alkali (3) Glass containers (4) Dust

Q41.Given below are two statements, one is labelled as Assertion A and the other is labelled as Reason R. Assertion A : The diameter of colloidal particles in solution should not be much smaller than wavelength of light to show Tyndall effect. Reason R : The light scatters in all directions when the size of particles is large enough. In the light of the above statements, choose the correct answer from the options given below : JEE Main 2023 (13 Apr Shift 2) JEE Main Previous Year Paper (1) Both A and R are correct but R is NOT the (2) A is true but R is false correct explanation of A (3) A is false but R is true (4) Both A and R are correct and R is the correct explanation of A

Q41.The density of alkali metals is in the order (1) K < Cs < Na < Rb (2) Na < Rb < K < Cs (3) Na < K < Cs < Rb (4) K < Na < Rb < Cs

Q42.Compound that will give positive Lassaigne's test for both nitrogen and halogen is (1) N2H4 ⋅HCl (2) CH3 NH2. HCl (3) NH4 Cl (4) NH2 OH. HCl

Q42.The correct order of basicity of oxides of vanadium is JEE Main 2023 (31 Jan Shift 1) JEE Main Previous Year Paper (1) V2O3 > V2O4 > V2O5 (2) V2O3 > V2O5 > V2O4 (3) V2O5 > V2O4 > V2O3 (4) V2O4 > V2O3 > V2O5

Q42.Molar mass of the hydrocarbon (X) which on ozonolysis consumes one mole of O3 per mole of (X) and gives one mole each of ethanal and propanone is ______ g mol–1 (Molar mass of C : 12 g mol–1 , H : 1 g mol–1 )

Q42.Given below are two statements: Statement I : Aqueous solution of K2Cr2O7 is preferred as a primary standard in volumetric analysis over Na2Cr2O7 aqueous solution. Statement II : K2Cr2O7 has a higher solubility in water than Na2Cr2O7. In the light of the above statements, choose the correct answer from the options given below: (1) Statement I is false but Statement II is true (2) Both Statement I and Statement II are true (3) Statement I is true but Statement II is false (4) Both Statement I and Statement II are false

Q42.A cubic solid is made up of two elements X and Y. Atoms of X are present on every alternate corner and one at 1 rd the center of cube. Y is at 3 of the total faces. The empirical formula of the compound is (1) X2Y1.5 (2) X1.5Y (3) XY2.5 (4) X1.5Y2

Q42.The Lewis acid character of boron tri halides follows the order: (1) BCl3 > BF3 > BBr3 > Bl3 (2) Bl3 > BBr3 > BCl3 > BF3 (3) BBr3 > Bl3 > BCl3 > BF3 (4) BF3 > BCl3 > BBr3 > Bl3

Q42.Which will undergo deprotonation most readily in basic medium? (1) a only (2) c only (3) Both a and c (4) b only

Q42.Match List I with List II: List II List I (Mixture) (Separation Technique) (A) CHCl3 + C6H5 NH2 I Steam distillation JEE Main 2023 (30 Jan Shift 2) JEE Main Previous Year Paper Differential (B) C6H14 + C5H12 II extraction (C) C6H5 NH2 + H2O III Distillation Fractional (D) Organic compound in H2O IV distillation (1) A-IV, B-I, C-III, D-II (2) A-III, B-IV, C-I, D-II (3) A-II, B-I, C-III, D-IV (4) A-III, B-I, C-IV, D-II

Q42.Which one of the following is not an example of calcination? (1) CaCO3 Δ→CaO + CO2 (2) Fe2 O3. xH2 O Δ→Fe2 O3 + xH2 O (3) (4) 2PbS + 3O2 Δ→2PbO + 2 SO2 CaCO3. MgCO3 Δ→CaO + MgO + 2 CO2

Q42.The number of possible isomeric products formed when 3 -chloro- 1 -butene reacts with HCl through carbocation formation is.........

Q42.Testosterone, which is a steroidal hormone, has the following structure. The total number of asymmetric carbon atom/s in testosterone is ____________. Q43. ‘ X ’ is: JEE Main 2023 (01 Feb Shift 2) JEE Main Previous Year Paper (1) (2) (3) (4)

Q42.Which of the following is correct order of ligand field strength? (1) CO < en < NH3 < C2O42 - < S2 - (2) S2 - < C2O42 - < NH3 < en < CO (3) NH3 < en < CO < S2 - < C2O42 - (4) S2 - < NH3 < en < CO < C2O42 -

Q42.For a good quality cement, the ratio of lime to the total of the oxides of Si, Al and Fe should be as close as to (1) 4 (2) 1 (3) 2 (4) 3