Practice Questions
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Q76.Consider a triangular plot ABC with sides AB = 7 m, BC = 5 m and CA = 6 m. A vertical lamp-post at the mid-point D of AC subtends an angle 30Β° at B. The height (in m ) of the lamp-post is: (1) 2β21 (2) 23 β21 (3) 3 2 β21 (4) 7β3 JEE Main 2019 (10 Jan Shift 1) JEE Main Previous Year Paper
Q76.If the function f : R β{1, β1} βA defined by f(x) = x2 , is surjective, then A is equal to 1βx2 (1) [0, β) (2) R β{β1} (3) R β[β1, 0) (4) R β(β1, 0)
Q76.All x satisfying the inequality (cotβ1 x)2 β7 (cotβ1 x) + 10 > 0 , lie in the interval : (1) (ββ, cot 5) βͺ(cot 4, cot 2) (2) (cot 2, β) (3) (ββ, cot 5) βͺ(cot 2, β) (4) (cot 5, cot 4)
Q76.If the lengths of the sides of a triangle are in A.P and the greatest angle is double the smallest, then a ratio of lengths of the sides of this triangle is: (1) 3: 4: 5 (2) 5: 6: 7 (3) 5: 9: 13 (4) 4: 5: 6 Q77. 1 1 1 Let the numbers 2, π, π be in an A.P. and π΄= 2 π π . If det ( π΄) β[2,16], then π lies in the interval: 4 π2 π2 (1) 2,3 (2) 4,6 3 (3) 3,2 + 2 4 (4) 2 + 2 34, 4
Q76.The angles π΄, π΅ & πΆ of a βπ΄π΅πΆ are in π΄. π. and π: π= 1: β3 . If π= 4 ππ, then the area (in π π. ππ) of this triangle is: 2 (1) 2β3 (2) β3 4 (3) (4) 4β3 β3
Q76.The outcome of each of 30 items was observed; 10 items gave an outcome 1 2 βd each, 10 items gave outcome 1 each and the remaining 10 items gave outcome 2 2 1 + d each. If the variance of this outcome data is 34 then |d| equals: (1) 2 (2) 2 3 (3) β5 (4) β2 2 Q77. β0 2q r β Let A = p q βr . If AAT = I3, then |p| is: βp βq r β (1) 1 (2) 1 β5 β3 (3) 1 (4) 1 β2 β6
Q76.Let a1, a2, a3 β¦ , a10 be in G. P. with ai > 0 for i = 1, 2, β¦ , 10 and S be the set of pairs (r, k), r, k βN (the set of natural numbers) for which JEE Main 2019 (10 Jan Shift 2) JEE Main Previous Year Paper loge ar1 ak2 loge ar2ak3 loge ar3ak4 loge ar4 ak5 loge ar5ak6 loge ar6ak7 = 0 loge ar7ak8 loge ar8ak9 loge ar9ak10 Then the number of elements in S, is: (1) Infinitely many (2) 4 (3) 10 (4) 2
Q76.Let Z be the set of integers. If A = {x βZ : 2(x+2)(x2β5x+6) = 1} then the number of subsets of the set A Γ B, is : (1) 212 (2) 210 (3) 218 (4) 215 Q77. β‘ 1 sin ΞΈ 1 β€ 3Ο 5Ο If A = βsin ΞΈ 1 sin ΞΈ , then for all ΞΈ β( 4 , 4 ), det(A) lies in the interval : β£ β1 βsin ΞΈ 1 β¦ (1) (1, 52 ] (2) [ 52 , 4) (3) ( 23 , 3] (4) (0, 32 ]
Q76.The angle of the top of a vertical tower standing on a horizontal plane is observed to be 45Β° from a point A on the plane. Let B be the point 30 m vertically above the point A. If the angle of elevation of the top of the tower from B be 30Β° , then the distance (in m) of the foot of the tower from the point A is: + + (1) 15(3 β3) (2) 15(1 β3) (3) 15(5 ββ3) (4) 15(3 ββ3)
Q77.The sum of the real roots of the equation π₯ -6 -1 2 -3π₯ π₯- 3 = 0, is equal to: -3 2π₯ π₯+ 2 (1) 0 (2) -4 (3) 6 (4) 1 JEE Main 2019 (10 Apr Shift 2) JEE Main Previous Year Paper
Q77.The system of linear equations π₯+ π¦+ π§= 2 2π₯+ 3π¦+ 2π§= 5 2π₯+ 3π¦+ π2 - 1π§= π+ 1 (1) is inconsistent when π= β3 (2) has a unique solution for π= β3 (3) has infinitely many solutions for π= 4 (4) is inconsistent when π= 4
Q77.The value of cot(β19n=1 cotβ1(1 + βnp=1 2p)) is: (1) 21 (2) 19 19 21 (3) 2223 (4) 2223
Q77.Let f(x) = 15β|x β10|; x βR. Then the set of all values of x, at which the function g(x) = f(f(x)) is not differentiable, is: (1) {5, 10, 15} (2) {10} (3) {10, 15} (4) {5, 10, 15, 20} β2cosxβ1 Ο cotxβ1 , x β Ο 4 is continuous, then k is equal to
Q77. et eβtcos t eβt sin t If A = β‘et βeβt cos t βeβt sin t βeβt sin t + eβt cos t β€, then A is: et 2eβt sin t β2eβt cos t β£ β¦ (1) Invertible only if t = Ο (2) Not invertible for any t βR (3) Invertible only if t = Ο2 (4) Invertible for all t βR
Q77.Let a function f : (0, β) β(0, β) be defined by f(x) = 1 β1x . Then f is : (1) not injective but it is surjective (2) injective only (3) neither injective nor surjective (4) None of the above
Q77.In a class of 140 students numbered 1 to 140 , all even numbered students opted Mathematics course, those whose number is divisible by 3 opted Physics course and those whose number is divisible by 5 opted Chemistry course. Then the number of students who did not opt for any of the three courses is: (1) 42 (2) 1 (3) 38 (4) 102
Q77. x sinΞΈ cosΞΈ x sin2ΞΈ cos2ΞΈ If Ξ1 = βsinΞΈ βx 1 and Ξ2 = βsin2ΞΈ βx 1 , x β 0; then for all ΞΈ β(0, Ο2 ) : cosΞΈ 1 x cos2ΞΈ 1 x (1) Ξ1 + Ξ2 = β2(x3 + x β1) (2) Ξ1 βΞ2 = x(cos2ΞΈ βcos4ΞΈ) (3) Ξ1 + Ξ2 = β2x3 (4) Ξ1 βΞ2 = β2x3
Q77.For π₯βπ , Let [π₯] denotes the greatest integer β€π₯, then the sum of the series -1 + -1 - 1 + -1 - 2 + . . . . . + -1 - 99 is 3 3 100 3 100 3 100 (1) -131 (2) -153 (3) -135 (4) -133
Q77.Let A, B and C be sets such that Ο β A β©B βC. Then which of the following statements is not true? (1) B β©C β Ο (2) (C βͺA) β©(C βͺB) = C (3) If (A βB) βC, then A βC (4) If (A βC) βB, then A βB Q78. 1 + cos2ΞΈ sin2ΞΈ 4 cos6ΞΈ A value of ΞΈ β(0, Ο3 ), for which cos2ΞΈ 1 + sin2ΞΈ 4 cos6ΞΈ = 0, is cos2ΞΈ sin2ΞΈ 1 + 4 cos6ΞΈ (1) Ο (2) 7Ο 9 24 (3) 7Ο (4) Ο 36 18
Q77.If πΌ= cos-13 , π½= tan-11 , where 0 < πΌ, π½< π then πΌ- π½ is equal to 5 3 2, (1) tan-1 9 (2) cos-1 9 (3) sin-1β‘ 9 (4) tan-1 9 14 5β10 5β10 5β10 2π₯ is equal to π₯< 1, then π
Q78.If the system of linear equations 2x + 2y + 3z = a 3x βy + 5z = b x β3y + 2z = c where, a, b, care non- zero real numbers, has more than onc solution, then (1) b βc + a = 0 (2) b βc βa = 0 (3) a + b + c = 0 (4) b + c βa = 0
Q78.If the system of equations x + y + z = 5, x + 2y + 3z = 9, x + 3y + Ξ±z = Ξ² has inifinitely many solutions, then Ξ² βΞ± equals (1) 8 (2) 21 (3) 5 (4) 18 Q79. β‘β2 4 + d (sin ΞΈ) β2 β€ Let d βR, and A = 1 (sin ΞΈ) + 2 d , ΞΈ β[0, 2Ο]. If the minimum value of det(A) is β£ 5 (2 sin ΞΈ) βd (βsin ΞΈ) + 2 + 2d β¦ 8, then a value of d is: + + (1) 2(β2 2) (2) 2(β2 1) (3) β5 (4) β7 . Let S be the set of points in the interval (β4, 4) at which f is not
Q78.An ordered pair (Ξ±, Ξ²) for which the system of linear equations (1 + Ξ±)x + Ξ²y + z = 2 Ξ±x + (1 + Ξ²)y + z = 3 Ξ±x + Ξ²y + 2z = 2 has a unique solution, is : (1) (β3, 1) (2) (1, β3) (3) (2, 4) (4) (β4, 2) JEE Main 2019 (12 Jan Shift 1) JEE Main Previous Year Paper
Q78.For π₯ π (0, 3 ), let ππ₯= ππ₯= tanπ₯ and βπ₯= 1 - π₯2 . If Οπ₯= ( hoπ) og ) ( π₯) , then Ο π is equal to: 2 βπ₯, 1 + π₯2 3 π 5π (1) tanβ‘ (2) tanβ‘ 12 12 7π 11π (3) tanβ‘ (4) tanβ‘ 12 12
Q78.If the system of linear equations π₯- 2π¦+ ππ§= 1 2π₯+ π¦+ π§= 2 3π₯- π¦- ππ§= 3 has a solution π₯, π¦, π§, π§β 0, then π₯, π¦ lies on the straight line whose equation is: (1) 4π₯- 3π¦- 4 = 0 (2) 3π₯- 4π¦- 4 = 0 (3) 3π₯- 4π¦- 1 = 0 (4) 4π₯- 3π¦- 1 = 0