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Practice Questions

10,208 questions across 23 years of JEE Main β€” find and practise any topic!

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Q61.Let 𝛼 and 𝛽 be the roots of the equation 𝑝π‘₯2 + π‘žπ‘₯βˆ’π‘Ÿ= 0, where 𝑝≠0. If 𝑝, π‘ž and π‘Ÿ be the consecutive terms of a non-constant G.P and 1 1 3 then the value of π›Όβˆ’π›½2 is: 𝛼+ 𝛽= 4, (1) 80 (2) 9 9 20 (3) (4) 8 3

202401 Feb Shift 2Quadratic Equations
MathsMedium

Q61.Let Ξ±, Ξ² be the roots of the equation x2 + 2√2x βˆ’1 = 0. The quadratic equation, whose roots are Ξ±4 + Ξ²4 and 1 (Ξ±6 + Ξ²6), is : 10 (1) x2 βˆ’190x + 9466 = 0 (2) x2 βˆ’180x + 9506 = 0 (3) x2 βˆ’195x + 9506 = 0 (4) x2 βˆ’195x + 9466 = 0

202409 Apr Shift 1Quadratic Equations
MathsMedium

Q62.Let π‘Ž and 𝑏 be two distinct positive real numbers. Let 11th term of a GP, whose first term is π‘Ž and third term is 𝑏, is equal to 𝑝th term of another GP, whose first term is π‘Ž and fifth term is 𝑏. Then 𝑝 is equal to (1) 20 (2) 25 (3) 21 (4) 24

202430 Jan Shift 2Complex Numbers
MathsHard

Q62.In an A.P., the sixth term a6 = 2. If the a1a4a5 is the greatest, then the common difference of the A.P., is equal to (1) 3 (2) 8 2 5 (3) 2 (4) 5 3 8

202429 Jan Shift 1Sequences & Series
MathsHard

Q62.If the sum of the series 1 + 1 + … + 1 is equal to 5 , then 50 d is equal to : 1β‹…(1+d) (1+d)(1+2 d) (1+9 d)(1+10 d) (1) 10 (2) 5 (3) 15 (4) 20

202409 Apr Shift 1Sequences & Series
MathsMedium

Q62.If 𝑧 is a complex number such that 𝑧≀1, then the minimum value of 𝑧+ 1 + 4𝑖 is: 23 5 (1) 2 (2) 2 3 (3) (4) 3 2

202401 Feb Shift 2Complex Numbers
MathsMedium

Q62.If 1 + 1 + … + 1 = m and 1β‹…21 + 2β‹…31 + … + 99β‹…1001 = n , then the point (m, n) lies on the √1+√2 √2+√3 √99+√100 line (1) 11(x βˆ’1) βˆ’100(y βˆ’2) = 0 (2) 11x βˆ’100y = 0 (3) 11(x βˆ’2) βˆ’100(y βˆ’1) = 0 (4) 11(x βˆ’1) βˆ’100y = 0

202405 Apr Shift 1Sequences & Series
MathsMedium

Q62.Let z be a complex number such that the real part of zβˆ’2i is zero. Then, the maximum value of |z βˆ’(6 + 8i)| z+2i is equal to (1) 12 (2) 10 (3) 8 (4) ∞

202409 Apr Shift 2Complex Numbers
MathsMedium

Q62.The number of triangles whose vertices are at the vertices of a regular octagon but none of whose sides is a side of the octagon is (1) 48 (2) 56 (3) 24 (4) 16

202406 Apr Shift 1Permutation & Combination
MathsMedium

Q62.The number of ways five alphabets can be chosen from the alphabets of the word MATHEMATICS, where the chosen alphabets are not necessarily distinct, is equal to : (1) 179 (2) 177 (3) 181 (4) 175

202408 Apr Shift 2Permutation & Combination
MathsMedium

Q62.Let 𝑆= π‘§βˆˆπΆ: π‘§βˆ’1 = 1 and √2 βˆ’1𝑧+ ¯𝑧- 𝑖𝑧- ¯𝑧= 2√2. Let 𝑧1, 𝑧2 βˆˆπ‘† be such that 𝑧1 = maxπ‘§βˆˆπ‘ π‘§ and 2 𝑧2 = minπ‘§βˆˆπ‘ π‘§. Then √2𝑧1 βˆ’π‘§2 equals: (1) 1 (2) 4 (3) 3 (4) 2

202401 Feb Shift 1Complex Numbers
MathsHard

Q62.Number of ways of arranging 8 identical books into 4 identical shelves where any number of shelves may remain empty is equal to (1) 18 (2) 16 (3) 12 (4) 15

202429 Jan Shift 2Permutation & Combination
MathsHard

Q62.The number of common terms in the progressions 4, 9, 14, 19, … …, up to 25th term and 3, 6, 9, 12,.... up to 37th term is : (1) 9 (2) 5 (3) 7 (4) 8 n

202427 Jan Shift 1Sequences & Series
MathsMedium

Q62.The value of 1Γ—22+2Γ—32+…+100Γ—(101)2 is 12Γ—2+22Γ—3+….+1002Γ—101 (1) 32 (2) 31 31 30 (3) 306 (4) 305 305 301 JEE Main 2024 (04 Apr Shift 2) JEE Main Previous Year Paper

202404 Apr Shift 2Sequences & Series
MathsMedium

Q62.For 0 < 𝑐< 𝑏< π‘Ž, let ( π‘Ž+ 𝑏– 2𝑐) π‘₯2 + ( 𝑏+ 𝑐– 2π‘Ž) π‘₯+ ( 𝑐+ π‘Žβ€“ 2𝑏) = 0 and 𝛼≠1 be one of its root. Then, among the two statements (I) If π›Όβˆˆ-1, 0, then 𝑏 cannot be the geometric mean of π‘Ž and 𝑐. (II) If π›Όβˆˆ0, 1, then 𝑏 may be the geometric mean of π‘Ž and 𝑐. (1) Both (I) and (II) are true (2) Neither (I) nor (II) is true (3) Only (II) is true (4) Only (I) is true 1 2 3

202431 Jan Shift 1Quadratic Equations
MathsHard

Q62.Let 0 ≀r ≀n. If n+1Cr+1 : nCr : nβˆ’1Crβˆ’1 = 55 : 35 : 21, then 2n + 5r is equal to: JEE Main 2024 (06 Apr Shift 2) JEE Main Previous Year Paper (1) 50 (2) 62 (3) 55 (4) 60

202406 Apr Shift 2Permutation & Combination
MathsMedium

Q62.Let z be a complex number such that |z + 2| = 1 and Im ( z+2 ) = 5 . Then the value of |Re(z + 2)| is (1) 2√6 (2) 24 5 5 (3) 1+√6 (4) √6 5 5

202408 Apr Shift 1Complex Numbers
MathsMedium

Q62.Let 𝑧1 and 𝑧2 be two complex number such that 𝑧1 + 𝑧2 = 5 and 𝑧13 + 𝑧23 = 20 + 15𝑖. Then 𝑧14 + 𝑧24 equals- (1) 30√3 (2) 75 (3) 15√15 (4) 25√3

202431 Jan Shift 2Complex Numbers
MathsMedium

Q62.Let α and β be the sum and the product of all the non-zero solutions of the equation (¯z)2 + |z| = 0, z ∈ C. Then 4 (α2 + β2) is equal to : (1) 6 (2) 8 (3) 2 (4) 4

202404 Apr Shift 1Complex Numbers
MathsMedium

Q63.Let A = {n ∈[100, 700] ∩N : n is neither a multiple of 3 nor a multiple of 4 }. Then the number of elements in A is (1) 290 (2) 280 (3) 300 (4) 310

202406 Apr Shift 1Sets Relations Functions
MathsMedium

Q63.In an increasing geometric progression of positive terms, the sum of the second and sixth terms is 70 and the 3 product of the third and fifth terms is 49 . Then the sum of the 4th , 6th and 8th terms is equal to : (1) 96 (2) 91 (3) 84 (4) 78

202408 Apr Shift 2Sequences & Series
MathsMedium

Q63.If in a G.P. of 64 terms, the sum of all the terms is 7 times the sum of the odd terms of the G.P, then the common ratio of the G.P. is equal to (1) 7 (2) 4 (3) 5 (4) 6

202429 Jan Shift 1Sequences & Series
MathsMedium

Q63.There are 5 points P1, P2, P3, P4, P5 on the side AB, excluding A and B, of a triangle ABC . Similarly there are 6 points P6, P7, … , P11 on the side BC and 7 points P12, P13, … , P18 on the side CA of the triangle. The number of triangles, that can be formed using the points P1, P2, … , P18 as vertices, is : (1) 776 (2) 796 (3) 751 (4) 771

202404 Apr Shift 1Permutation & Combination
MathsMedium

Q63.If A denotes the sum of all the coefficients in the expansion of (1 βˆ’3x + 10x2) and B denotes the sum of all the coefficients in the expansion of (1 + x2)n , then : (1) A = B3 (2) 3 A = B (3) B = A3 (4) A = 3 B

202427 Jan Shift 1Binomial Theorem
MathsEasy

Q63.Let three real numbers a, b, c be in arithmetic progression and a + 1, b, c + 3 be in geometric progression. If a > 10 and the arithmetic mean of a, b and c is 8, then the cube of the geometric mean of a, b and c is (1) 128 (2) 316 (3) 120 (4) 312

202404 Apr Shift 2Sequences & Series
MathsMedium

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