Practice Questions
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Q83.Let A be the area of the region {(x, y) : y β₯x2, y β₯(1 βx)2, y β€2x(1 βx)}. Then 540A is equal to y(1) = 0 is
Q83.Let Ξ be the area of the region {(x, y) βR2 : x2 + y2 β€21, y2 β€4x, x β₯1}. Then 21 (Ξ β7 equal to (1) 2β3 β13 (2) β3 β23 (3) 2β3 β23 (4) β3 β43
Q83.If the area of the region bounded by the curves y2 β2y = βx and x + y = 0 is A , then 8A =
Q83.The number of 9 digit numbers, that can be formed using all the digits of the number 123412341 so that the even digits occupy only even places, is ______ 1
Q83.Let the area enclosed by the lines x + y = 2, y = 0 , x = 0 and the curve f(x) = min{x2 + 43 , 1 + [x]} where [x] denotes the greatest integer β€x, be A . Then the value of 12A is
Q83.Let π= 109 + 108 + 107 + β¦ . + 2 + 1 Then the value of 16π- ( 25 -54 is equal to 5 52 5107 5108. ) 1 1 680 4 is equal to
Q84.Let πΌ> 0, be the smallest number such that the expansion of π₯ 3 + 2 has a term π½π₯-πΌ, π½βπ. Then πΌ is π₯3 equal to _____ .
Q84.If the solution curve f(x, y) = 0 of the differential equation (1 + loge x) dxdy βx loge x = ey, x > 0, passes through the points (1, 0) and (a, 2), then aa is equal to (1) e2e2 (2) ee2 (3) eβ2e2 (4) e2eβ2 β
Q84.Let the point π, π+ 1 lie inside the region πΈ= π₯, π¦: 3 - π₯β€π¦β€β9 - π₯2 , 0 β€π₯β€3 . If the set of all values of π is the interval π, π, then π2 + π- π2 is equal to ________ .
Q84.The remainder when 19200 + 23200 is divided by 49, is _____ .
Q84.The remainder, when 7103 is divided by 17, is
Q84.Let y = y(x) be the solution of the differential equation (x2β 3y2)dx + 3 xy dy = 0, y(1) = 1 . Then 6y2(e) is equal to (1) 3e2 (2) e2 (3) 2e2 (4) 3e22 β β β β β β
Q84.Let y = y(x) be the solution of the differential equation (3y2 β5x2)ydx + 2x(x2 βy2)dy = 0 such that y(1) = 1. Then (y(2))3 β12y(2) is equal to : (1) 64 (2) 32β2 (3) 32 (4) 16β2 β
Q84.Let Ξ±x = exp(xΞ²yΞ³) be the solution of the differential equation 2x2ydy β(1 βxy2)dx = 0 , x > 0, y(2) = βloge 2 . Then Ξ± + Ξ² βΞ³ equals : (1) 1 (2) β1 (3) 0 (4) 3 β
Q84.Let y = y(x) be the solution of the differential equation dxdy + x(x5+1)5 y(2) is equal to (1) 637 (2) 679 128 128 (3) 693 (4) 697 128 128 is equal to
Q84.If the solution curve of the differential equation (y β2 loge x)dx + (x loge x2)dy = 0, x > 1 passes through the points (e, 34 ) and (e4, Ξ±) , then Ξ± is equal to _______
Q84.Let y = y(x) be the solution curve of the differential equation dxdy = xy (1 + x2(1 + loge x)), x > 0, y(1) = 3. y2(x) Then is equal to : 9 (1) x2 (2) x2 5β2x3(2+loge x3) 2x3(2+loge x3)β3 (3) x2 (4) x2 3x3(1+loge x2)β2 7β3x3(2+loge x2) JEE Main 2023 (25 Jan Shift 1) JEE Main Previous Year Paper be a vector such that = 2 . If βd
Q84.The mean and variance of 7 observations are 8 and 16 respectively. If one observation 14 is omitted, π and π are respectively mean and variance of remaining 6 observation, then π+ 3 π- 5 is equal to ________
Q84.The sum of all those terms, of the arithmetic progression 3, 8, 13, . . . , 373, which are not divisible by 3, is equal to ________. JEE Main 2023 (10 Apr Shift 1) JEE Main Previous Year Paper
Q84.The number of integral terms in the expansion of 3 2 + 5
Q84.Let y = y(x) be the solution of the differential equation x loge x dxdy + y = x2 loge x, (x 1). If then y(e) is equal to (1) 4+e2 (2) 1+e2 4 4 (3) 2+e2 (4) 1+e2 2 2
Q84.Let the solution curve x = x(y), 0 < y < Ο2 , of the differential equation (loge(cos y))2 cos y dx β(1 + 3x loge(cos y)) sin y dy = 0 satisfy x( Ο3 ) = 2 loge1 2 . If x( Ο6 ) = loge mβloge1 n , where m and n are coprime, then mn is equal to βββ
Q84.Let a, b, c be three distinct real numbers, none equal to one. If the vectors aΛi + Λj + Λk, Λi + bΛj + Λk and Λi + Λj + cΛk are coplanar, then 1βa1 + 1βb1 + 1βc1 is equal to (1) 2 (2) β1 (3) β2 (4) 1 β
Q84.If the four points, whose position vectors are 3Λi β4Λj + 2Λk,Λi + 2Λj βΛk, β2Λi βΛj + 3Λk and 5Λi β2Ξ±Λj + 4Λk are coplanar, then Ξ± is equal to (1) 7317 (2) β10717 (3) β7317 (4) 10717 β β β
Q84.Let y = f(x) be the solution of the differential equation y(x + 1)dx βx2dy = 0, y(1) = e. Then lim xβ0+ f(x) is equal to (1) 0 (2) 1e (3) e2 (4) 1 e2 β