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4,685 questions across 23 years of JEE Main β€” find and practise any topic!

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Q13.Suppose that the number of terms in an A.P. is 2k, k ∈N . If the sum of all odd terms of the A.P. is 40 , the sum of all even terms is 55 and the last term of the A.P. exceeds the first term by 27, then k is equal to : (1) 6 (2) 5 (3) 8 (4) 4 y+2

202522 Jan Shift 2Sequences & Series
MathsMedium

Q13.The area of the region, inside the circle (x βˆ’2√3)2 + y2 = 12 and outside the parabola y2 = 2√3x is : (1) 3Ο€ + 8 (2) 6Ο€ βˆ’16 (3) 3Ο€ βˆ’8 (4) 6Ο€ βˆ’8

202522 Jan Shift 1Definite Integration & Area
MathsHard

Q13.Let L1 : xβˆ’11 = yβˆ’2βˆ’1 = zβˆ’12 and L2 : x+1βˆ’1 = yβˆ’22 = 1z be two lines. Let L3 be a line passing through the point (Ξ±, Ξ², Ξ³) and be perpendicular to both L1 and L2 . If L3 intersects L1 , then |5Ξ± βˆ’11Ξ² βˆ’8Ξ³| equals : (1) 20 (2) 18 (3) 25 (4) 16

202529 Jan Shift 13D Geometry
MathsHard

Q14.Let R = {(1, 2), (2, 3), (3, 3)} be a relation defined on the set {1, 2, 3, 4}. Then the minimum number of elements, needed to be added in R so that R becomes an equivalence relation, is: (1) 10 (2) 7 (3) 8 (4) 9

202523 Jan Shift 1Sets Relations Functions
MathsMedium

Q14.Let the foci of a hyperbola be (1, 14) and (1, βˆ’12). If it passes through the point (1, 6), then the length of its latus-rectum is : (1) 24 (2) 25 5 6 (3) 144 (4) 288 5 5 is equal to :

202522 Jan Shift 1Hyperbola
MathsMedium

Q14.If the domain of the function log5 (18x βˆ’x2 βˆ’77) is (Ξ±, Ξ²) and the domain of the function is (Ξ³, Ξ΄), then Ξ±2 + Ξ²2 + Ξ³ 2 is equal to : log(xβˆ’1) ( 2x2+3xβˆ’2x2βˆ’3xβˆ’4 ) (1) 195 (2) 179 (3) 186 (4) 174

202529 Jan Shift 2Sets Relations Functions
MathsHard

Q14.The perpendicular distance, of the line xβˆ’1 2 = βˆ’1 = z+32 from the point P(2, βˆ’10, 1), is : (1) 6 (2) 5√2 (3) 4√3 (4) 3√5

202522 Jan Shift 23D Geometry
MathsMedium

Q14.The number of complex numbers z , satisfying |z| = 1 and zΒ―z + Β―zz = 1, is : (1) 4 (2) 8 (3) 10 (4) 6 Q15. ⎑ 0 ⎀ ⎑ 0 ⎀ ⎑4⎀ ⎑0⎀ ⎑2 ⎀ ⎑1 ⎀ Let A = [aij] be 3 Γ— 3 matrix such that A 1 = 0 , A 1 = 1 and A 1 = 0 , then a23 equals : ⎣ 0 ⎦ ⎣ 1 ⎦ ⎣3⎦ ⎣0⎦ ⎣2 ⎦ ⎣0 ⎦ (1) -1 (2) 2 (3) 1 (4) 0 2 x sin 2 dx equals : 3 3

202523 Jan Shift 2Complex Numbers
MathsMedium

Q14. IfI(m, n) = ∫10 xmβˆ’1(1 βˆ’x)nβˆ’1dx, m, (1) I(19, 27) (2) I(9, 1) (3) I(1, 13) (4) I(9, 13)

202524 Jan Shift 1Limits & Continuity
MathsHard

Q14. The function f : (βˆ’βˆž, ∞) β†’(βˆ’βˆž, 1), defined by f(x) = 2xβˆ’2βˆ’x2x+2βˆ’x is : (1) Neither one-one nor onto (2) Onto but not one-one (3) Both one-one and onto (4) One-one but not onto

202524 Jan Shift 2Sets Relations Functions
MathsMedium

Q14.Let Tr be the rth term of an A.P. If for some m, Tm = 251 , T25 = 201 , and 20 βˆ‘25r=1 Tr = 13, then 5 m βˆ‘2r=mm Tr is equal to (1) 98 (2) 126 (3) 142 (4) 112

202528 Jan Shift 1Sequences & Series
MathsMedium

Q14.If A and B are the points of intersection of the circle x2 + y2 βˆ’8x = 0 and the hyperbola x29 βˆ’y24 = 1 point P moves on the line 2x βˆ’3y + 4 = 0, then the centroid of β–³PAB lies on the line : (1) x + 9y = 36 (2) 4x βˆ’9y = 12 (3) 6x βˆ’9y = 20 (4) 9x βˆ’9y = 32

202528 Jan Shift 2Coordinate Geometry
MathsHard

Q14.Let M and m respectively be the maximum and the minimum values of 1 + sin2 x cos2 x 4 sin 4x f(x) = sin2 x 1 + cos2 x 4 sin 4x , x ∈R Then M 4 βˆ’m4 is equal to : sin2 x cos2 x 1 + 4 sin 4x (1) 1280 (2) 1295 (3) 1215 (4) 1040

202529 Jan Shift 1Applications of Derivatives
MathsHard

Q15.If f(x) = ∫ 1 dx, f(0) = βˆ’6, then f(1) is equal to : x1/4(1+x1/4) (1) 4 (loge 2 βˆ’2) (2) 2 βˆ’loge2 2 (3) loge 2 + 2 (4) 4 (loge 2 + 2)

202528 Jan Shift 2Indefinite Integration
MathsMedium

Q15.Let the area of a β–³PQR with vertices P(5, 4), Q(βˆ’2, 4) and R(a, b) be 35 square units. If its orthocenter and centroid are O (2, 145 ) and C(c, d) respectively, then c + 2d is equal to (1) 8 (2) 7 3 3 (3) 2 (4) 3 ((loge x)2+1)βˆ’1 1 e is

202523 Jan Shift 1Coordinate Geometry
MathsHard

Q15.Let a circle C pass through the points (4, 2) and (0, 2), and its centre lie on 3x + 2y + 2 = 0. Then the length of the chord, of the circle C , whose mid-point is (1, 2), is : (1) √3 (2) 2√2 (3) 2√3 (4) 4√2

202529 Jan Shift 2Circles
MathsMedium

Q15.If βˆ‘nr=1 Tr = (2nβˆ’1)(2n+1)(2n+3)(2n+5)64 , then limnβ†’βˆžβˆ‘nr=1 ( Tr1 ) (1) 0 (2) 23 (3) 1 (4) 13

202522 Jan Shift 1Sequences & Series
MathsHard

Q15. x + y + 2z = 6 If the system of linear equations : 2x + 3y + az = a + 1 where a, b ∈R, has infinitely many solutions, then βˆ’x βˆ’3y + bz = 2 b 7a + 3b is equal to : (1) 16 (2) 12 (3) 22 (4) 9 = 0, y ∈(βˆ’Ο€2 , Ο€2 ) with

202522 Jan Shift 2Matrices & Determinants
MathsMedium

Q15.Three defective oranges are accidently mixed with seven good ones and on looking at them, it is not possible to differentiate between them. Two oranges are drawn at random from the lot. If x denote the number of defective oranges, then the variance of x is (1) 28/75 (2) 18/25 (3) 26/75 (4) 14/25 x > 0 and f(2) = 3. Then f(6) is equal to

202528 Jan Shift 1Probability
MathsMedium

Q15.Let ABC be a triangle formed by the lines 7x βˆ’6y + 3 = 0, x + 2y βˆ’31 = 0 and 9x βˆ’2y βˆ’19 = 0. Let the point (h, k) be the image of the centroid of Ξ”ABC in the line 3x + 6y βˆ’53 = 0. Then h2 + k2 + hk is equal to: (1) 47 (2) 37 (3) 36 (4) 40 is:

202529 Jan Shift 1Straight Lines
MathsMedium

Q15. In an arithmetic progression, if S40 = 1030 and S12 = 57, then S30 βˆ’S10 is equal to : (1) 525 (2) 510 (3) 515 (4) 505

202524 Jan Shift 2Sequences & Series
MathsEasy

Q15. A and B alternately throw a pair of dice. A wins if he throws a sum of 5 before B throws a sum of 8 , and B wins if he throws a sum of 8 before A throws a sum of 5 . The probability, that A wins if A makes the first throw, is (1) 8 (2) 9 17 19 (3) 9 (4) 8 17 19

202524 Jan Shift 1Definite Integration & Area
MathsMedium

Q16.If I = ∫ 0Ο€ 3 dx, then ∫210 sin4x sinx+cos4x cos xx 2 2 x sin x+cos (1) Ο€2 (2) Ο€2 12 4 (3) Ο€2 (4) Ο€2 16 8 ∣∣ ⎒ βŽ₯ ⎒ βŽ₯ ⎒ βŽ₯ ⎒ βŽ₯ ⎒ βŽ₯ ⎒ βŽ₯ 2025 (23 Jan Shift 2) JEE Main Previous Year Paper

202523 Jan Shift 2Matrices
MathsMedium

Q16.If x = f(y) is the solution of the differential equation (1 + y2) + (x βˆ’2etanβˆ’1 y) dydx is equal to : f(0) = 1, then f ( √31 ) (1) eΟ€/12 (2) eΟ€/4 (3) eΟ€/3 (4) eΟ€/6

202522 Jan Shift 2Differential Equations
MathsMedium

Q16.The value of limnβ†’βˆž(βˆ‘nk=1 k3+6k2+11k+5(k+3)! ) (1) 4/3 (2) 2 (3) 7/3 (4) 5/3

202529 Jan Shift 1Sequences & Series
MathsHard

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