Practice Questions
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Q76.If the functions are defined as f(x) = βx and g(x) following functions: f + g, f βg, f/g, g/f, g βf , where (f Β± g)(x) = f(x) Β± g(x), (f/g)(x) = f(x) g(x) (1) 0 β€x β€1 (2) 0 β€x < 1 (3) 0 < x < 1 (4) 0 < x β€1 1 ; |x| β₯1 |x| is differentiable at every point of the domain, then the values of a and b are
Q76.If a curve passes through the origin and the slope of the tangent to it at any point (x, y) is x2β4x+y+8xβ2 , curve also passes through the point: (1) (5, 4) (2) (4, 4) (3) (4, 5) (4) (5, 5)
Q76.The value of β« β11 1 ) β2 (( xβ1x+1 + ( xβ1x+1 ) 2 β2) 2 β2 (1) loge 4 (2) 2 loge 16 + (3) loge 16 (4) 4 loge(3 2β2)
Q76.If the area of the bounded region R = {(x, y) : max{0, loge x} β€y β€2x, 21 β€x β€2} is, Ξ±(loge 2)β1 + Ξ²(loge 2) + Ξ³ then the value of (Ξ± + Ξ² β2Ξ³)2 is equal to: (1) 8 (2) 2 (3) 4 (4) 1 = 3x + 4y, with y(0) = 0. If
Q76.Let a vector Ξ±Λi + Ξ²Λj be obtained by rotating the vector β3Λi +Λj by an angle 45Β° about the origin in counterclockwise direction in the first quadrant. Then the area (in sq. units) of triangle having vertices (Ξ±, Ξ²), (0, Ξ²) and (0, 0) is equal to (1) 1 (2) 1 2 (3) 1 (4) 2β2 β2
Q76.Let slope of the tangent line to a curve at any point P(x, y) be given by xy2+yx x + 2y = 4 at x = β2, then the value of y, for which the point (3, y) lies on the curve, is : (1) β43 (2) 3518 (3) β1819 (4) β1811 ββ
Q76.If a curve y = f(x) passes through the point (1, 2) and satisfies x dydx + y = bx4, then for what value of b, β«21 f(x)dx = 625 ? (1) 31 (2) 10 5 (3) 5 (4) 625
Q76.If the solution curve of the differential equation (2x β10y3)dy + ydx = 0 , passes through the points (0, 1) and (2, Ξ²), then Ξ² is a root of the equation? (1) y5 β2y β2 = 0 (2) y5 βy2 β1 = 0 (3) 2y5 βy2 β2 = 0 (4) 2y5 β2y β1 = 0
Q76. y sin x 1 dy β‘ β€ Let y = y(x) satisfies the equation dx β|A| = 0, for all x > 0, where A = 0 β1 1 . If y(Ο) = Ο + 2, β£ 2 0 x1 β¦ then the value of y( Ο2 ) is: (1) Ο 2 + Ο4 (2) Ο2 β1Ο (3) 3Ο 2 β1Ο (4) Ο2 β4Ο βββββ
Q76.The area, enclosed by the curves π¦= sinπ₯+ cosπ₯ and π¦= | cosπ₯- sinπ₯| and the lines π₯= 0, π₯= 2, is : (1) 2β2 ( β2 + 1 ) (2) 2β2 ( β2 - 1 ) (3) 4 ( β2 - 1 ) (4) 2 ( β2 + 1 )
Q76.The area (in sq. units) of the part of the circle π₯2 + π¦2 = 36, which is outside the parabola π¦2 = 9π₯, is equal to (1) 12π+ 3β3 (2) 24π+ 3β3 (3) 24π- 3β3 (4) 12π- 3β3
Q76.Let us consider a curve, y = f(x) passing through the point (β2, 2) and the slope of the tangent to the curve at any point (x, f(x)) is given by f(x) + xf β²(x) = x2. Then (1) x3 β3xf(x) β4 = 0 (2) x2 + 2xf(x) β12 = 0 (3) x3 + xf(x) + 12 = 0 (4) x2 + 2xf(x) + 4 = 0
Q76.The area (in sq. unit) bounded by the curve 4y2 = x2(4 βx)(x β2) is equal to (1) Ο8 (2) 3Ο8 (3) 3Ο (4) Ο 2 16 0 < x < 2. 1 , with
Q76.The value of the integral β«1β1 log(x + βx2 + 1)dx is: (1) 2 (2) 0 (3) β1 (4) 1
Q76.The area of the region bounded by y βx = 2 and x2 = y is equal to :- (1) 16 (2) 2 3 3 (3) 9 (4) 4 2 3
Q76.The value of the integral β«1β1 loge(β1 x)dx is equal to: (1) 2 1 loge 2 + Ο4 β32 (2) 2 loge 2 + Ο4 β1 (3) loge 2 + Ο2 β1 (4) 2 loge 2 + Ο2 β12
Q76.Let a vector βa be coplanar with vectors b = 2Λi + Λj + Λk and βc= Λi βΛj + Λk. If βa is perpendicular to β β β β β d = 3Λi + 2Λj + 6Λk, and βa = β10. Then a possible value of [βa b βc] + [βa b d ] + [βa βc d ] is equal to: (1) β42 (2) β40 (3) β29 (4) β38 β β β
Q76.Let C1 be the curve obtained by the solution of differential equation 2xy dxdy = y2 βx2, x > 0 . Let the curve C2 be the solution of x2βy22xy = dxdy . If both the curves pass through (1, 1), then the area (in sq. units) enclosed by the curves C1 and C2 is equal to : (1) Ο β1 (2) Ο2 β1 (3) Ο + 1 (4) Ο4 + 1 β β = 3 and
Q76.If In = β« Ο2 cotn xdx, then 4 (1) I2 + I4, (I3 + I5)2, I4 + I6 are in G. P. (2) I2 + I4, I3 + I5, I4 + I6 are in A. P. (3) 1 , 1 , 1 are in A. P. (4) 1 , 1 , 1 are in G. P. I2+I4 I3+I5 I4+I6 I2+I4 I3+I5 I4+I6 is equal to lim n1 + (n+1)2n + (n+2)2n + β¦ + (2nβ1)2n ]
Q76.The integral β« 1 dx is equal to : (where C is a constant of integration) 4β(xβ1)3(x+2)5 (1) 5 1 4 + C 4 3 ( xβ1x+2 ) 4 + C (2) 34 ( x+2xβ1 ) (3) 4 xβ1 54 (4) 3 x+2 14 3 ( x+2 ) + C 4 ( xβ1 ) + C JEE Main 2021 (31 Aug Shift 1) JEE Main Previous Year Paper
Q77.Let y = y(x) be solution of the differential equation loge( dxdy ) y(β23 loge 2) = Ξ± loge 2 , then the value of Ξ± is equal to: JEE Main 2021 (27 Jul Shift 1) JEE Main Previous Year Paper (1) β14 (2) 41 (3) 2 (4) β12 β
Q77.In a triangle ABC, if BCβ = 3, CAβ = 5 and BAβ = 7, then the projection of the vector BAβ on BCβ is equal to JEE Main 2021 (20 Jul Shift 2) JEE Main Previous Year Paper (1) 19 (2) 13 2 2 (3) 11 (4) 15 2 2
Q77.A differential equation representing the family of parabolas with axis parallel to yβaxis and whose length of latus rectum is the distance of the point (2, β3) from the line 3x + 4y = 5, is given by: (1) 11 d2x dy2 = 10 (2) 11 dx2d2y = 10 d2y (3) 10 = 11 (4) 10 d2xdy2 = 11 dx2 = 1 and
Q77.Let three vectors βa, b and βcbe such that βaΓ b =βc, b Γβc=βa and βa = 2. Then which one of the following is not true? b b b Γ is 2 (1) βaΓ ((β β β (2) β +βc) ( ββc)) = 0 Projection of βa on ( Γβc) + = 8 (4) 3βa+βb β2βc 2 = 51 (3) [βa βb βc] [βc βa βb ] JEE Main 2021 (22 Jul Shift 1) JEE Main Previous Year Paper = 2. If P(Ξ±, Ξ², Ξ³) is the
Q77.Let y = y(x) be the solution of the differential equation dydx = 2(y + 2 sin x β5)x β2 cos x such that y(0) = 7. Then y(Ο) is equal to (1) 7eΟ2 + 5 (2) eΟ2 + 5 (3) 2eΟ2 + 5 (4) 3eΟ2 + 5