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14,828 questions across 23 years of JEE Main β€” find and practise any topic!

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Q77.Let β†’π‘Ž= ^𝑖+ 𝛼 ^𝑗+ 𝛽 ^π‘˜ , 𝛼, π›½βˆˆπ‘…. Let a vector →𝑏 be such that the angle between β†’π‘Ž and →𝑏 is πœ‹ and →𝑏 = 6, If 4 β†’π‘ŽΒ· →𝑏= 3√2, then the value of 𝛼2 + 𝛽2 | β†’π‘ŽΓ— →𝑏|2 is equal to (1) 90 (2) 75 (3) 95 (4) 85 2 is equal to

202430 Jan Shift 2Vectors
MathsMedium

Q77.If y = y(x) is the solution of the differential equation dydx + 2y = sin(2x), y(0) = 43 , then y ( Ο€8 ) is equal to: JEE Main 2024 (05 Apr Shift 1) JEE Main Previous Year Paper (1) eΟ€/8 (2) eΟ€/4 (3) eβˆ’Ο€/4 (4) eβˆ’Ο€/8

202405 Apr Shift 1Differential Equations
MathsMedium

Q77.Let A(2, 3, 5) and C(βˆ’3, 4, βˆ’2) be opposite vertices of a parallelogram ABCD if the diagonal βˆ’β†’ BD = Λ†i + 2Λ†j + 3Λ†k then the area of the parallelogram is equal to (1) 1 2 √410 (2) 21 √474 (3) 1 2 √586 (4) 21 √306 β†’ β†’ β†’

202430 Jan Shift 1Vectors
MathsMedium

Q77.Consider a π›₯𝐴𝐡𝐢 where 𝐴1, 3, 2, π΅βˆ’2, 8, 0 and 𝐢3, 6, 7. If the angle bisector of ∠𝐡𝐴𝐢 meets the line 𝐡𝐢 at 𝐷, then the length of the projection of the vector →𝐴𝐷 on the vector →𝐴𝐢 is: (1) 37 (2) √38 2√38 2 39 (3) (4) √19 2√38

202401 Feb Shift 2Vectors
MathsMedium

Q77.Let y = y(x) be the solution of the differential equation (1 + x2) dxdy + y = etanβˆ’1 x , y(1) = 0. Then y(0) is (1) 2 1 (eΟ€/2 βˆ’1) (2) 21 (1 βˆ’eΟ€/2) (3) 4 1 (1 βˆ’eΟ€/2) (4) 14 (eΟ€/2 βˆ’1)

202406 Apr Shift 1Differential Equations
MathsMedium

Q77.Let three vectors β†’a = Ξ±^i + 4^j + 2^k, b = 5^i + 3^j + 4^k,β†’c= x^i + y^j + z^k form a triangle such that β†’c = β†’a βˆ’β†’b and the area of the triangle is 5√6. If Ξ± is a positive real number, then |β†’c|2 is equal to: (1) 16 (2) 14 (3) 12 (4) 10 β†’ β†’βˆ’βˆ’βˆ’

202409 Apr Shift 1Differential Equations
MathsMedium

Q78.Let the position vectors of the vertices A, B and C of a triangle be 2 ^i + 2 ^j + ^k, ^i + 2 ^j + 2 ^k and 2 ^i + ^j + 2 ^k respectively. Let l1, l2 and l3 be the lengths of perpendiculars drawn from the ortho centre of the triangle on the sides AB, BC and CA respectively, then l12 + l22 + l32 equals : 1 1 (1) (2) 5 2 (3) 1 (4) 1 4 3 x y - 1 z - 2

202427 Jan Shift 2Vectors
MathsHard

Q78.Let β†’a = ^i + 2^j + 3^k, b = 2^i + 3^j βˆ’5^k andβ†’c= 3^i βˆ’^j + Ξ»^k be three vectors. Letβ†’rbe anit vector along β†’b + β†’c. If β†’r β‹…β†’a = 3, then 3Ξ» is equal to: (1) 21 (2) 30 (3) 25 (4) 27

202408 Apr Shift 2Vectors
MathsMedium

Q78.Let β†’π‘Ž= βˆ’5 ^𝑖+ ^π‘—βˆ’3 ^π‘˜, →𝑏= ^𝑖+ 2 ^π‘—βˆ’4 ^π‘˜ and →𝑐= β†’π‘ŽΓ— →𝑏× ^𝑖× ^𝑖× ^𝑖. Then β†’π‘β‹…βˆ’ ^𝑖+ ^𝑗+ ^π‘˜ is equal to (1) -12 (2) -10 (3) -13 (4) -15

202401 Feb Shift 1Differential Equations
MathsHard

Q78.If the shortest distance between the lines is √n L2 : β†’r = 2(1 + ΞΌ)^i + 3(1 + ΞΌ)^j + (5 + ΞΌ)^k, ΞΌ ∈R , where gcd(m, n) = 1, then the value of m + n equals (1) 390 (2) 384 (3) 377 (4) 387

202408 Apr Shift 1Vectors
MathsMedium

Q78.Let β†’a = 2^i + 5^j βˆ’^k,β†’b = 2^i βˆ’2^j + 2^k andβ†’cbe three vectors such that (β†’c +^i) Γ— (β†’a + β†’b +^i) = β†’a Γ— (β†’c +^i). If β†’a β‹…β†’c = βˆ’29, then β†’c β‹…(βˆ’2^i + ^j + ^k) is equal to: (1) 15 (2) 12 (3) 10 (4) 5

202405 Apr Shift 2Vectors
MathsMedium

Q78.Let a unit vector Λ†u = xΛ†i + yΛ†j + zΛ†k make angles Ο€2 , Ο€3 and 2Ο€3 with the vectors √2Λ†i1 + √21 Λ†k, √21 Λ†j + √21 Λ†k and 1 + 1 Λ†j respectively. If β†’v= 1 + 1 Λ†j + 1 Λ†k, then |^u βˆ’β†’v|2 is equal to √2Λ†i √2 √2Λ†i √2 √2 (1) 11 (2) 5 2 2 (3) 9 (4) 7

202429 Jan Shift 2Vectors
MathsHard

Q78.Let 𝛼, 𝛽, 𝛾 be mirror image of the point 2, 3, 5 in the line π‘₯βˆ’1 = π‘¦βˆ’2 = π‘§βˆ’3 . Then 2𝛼+ 3𝛽+ 4𝛾 is equal to 2 3 4 (1) 32 (2) 33 (3) 31 (4) 34 π‘₯βˆ’1 𝑦+ 1 𝑧+ 4

202431 Jan Shift 23D Geometry
MathsMedium

Q78.Let β†’a = aiΛ†i + a2Λ†j + a3Λ†k and b = b1Λ†i + b2Λ†j + b3Λ†k be two vectors such that β†’a = 1;β†’aβ‹… b = 2 and b = 4. If Γ— βˆ’3b, then the angle between b and β†’cis equal to : β†’c= 2(β†’a β†’ β†’ β†’ b) JEE Main 2024 (30 Jan Shift 1) JEE Main Previous Year Paper (1) cosβˆ’1( √32 ) (2) cosβˆ’1(βˆ’1√3 ) 2 ) 3 (3) cosβˆ’1(βˆ’βˆš32 ) (4) cosβˆ’1(

202430 Jan Shift 1Vectors
MathsMedium

Q78.If β†’a = Λ†i + 2Λ†j + Λ†k, b = 3(Λ†i βˆ’Λ†j + Λ†k) is equal to Γ— βˆ’ b β†’aβ‹…((β†’c β†’ β†’ b) βˆ’β†’c) (1) 32 (2) 24 (3) 20 (4) 36

202427 Jan Shift 1Vectors
MathsMedium

Q78.Let β†’a = ^i + ^j + ^k,β†’b = 2^i + 4^j βˆ’5^k and β†’c = x^i + 2^j + 3^k, x ∈R. If β†’d is the unit vector in the direction of β†’b + β†’c such that β†’a β‹…β†’d = 1, then (β†’a Γ— β†’b) β‹…β†’c is equal to (1) 11 (2) 3 (3) 9 (4) 6

202404 Apr Shift 2Vectors
MathsMedium

Q78.If the mirror image of the point 𝑃( 3, 4, 9 ) in the line π‘₯βˆ’1 = 𝑦+ 1 = π‘§βˆ’2 is 𝛼, 𝛽, 𝛾, then 14𝛼+ 𝛽+ 𝛾 is: 3 2 1 (1) 102 (2) 138 (3) 108 (4) 132 π‘₯+ 3 π‘¦βˆ’4 𝑧+ 1

202401 Feb Shift 23D Geometry
MathsMedium

Q78.Let β†’a = 6^i + ^j βˆ’^k and b = ^i + ^j. Ifβ†’cis a is vector such that |β†’c| β‰₯6,β†’aβ‹…β†’c= 6|β†’c|, |β†’cβˆ’β†’a| = 2√2 and the angle between β†’a Γ— β†’b and β†’c is 60∘ , then |(β†’a Γ— β†’b) Γ— β†’c| is equal to: (1) 9 2 (6 βˆ’βˆš6) (2) 23 √6 (3) 9 2 (6 + √6) (4) 23 √3

202406 Apr Shift 2Vectors
MathsHard

Q78.Let O be the origin and the position vector of A and B be 2Λ†i + 2Λ†j + Λ†k and 2Λ†i + 4Λ†j + 4Λ†k respectively. If the internal bisector of ∠AOB meets the line AB at C , then the length of OC is (1) 3 2 √31 (2) 32 √34 (3) 3 4 √34 (4) 23 √31

202429 Jan Shift 1Differential Equations
MathsMedium

Q78.Let OAβ†’ = 2β†’a, OB = 6β†’a + 5β†’b and OC = 3β†’b, where O is the origin. If the area of the parallelogram with βˆ’βˆ’β†’ β†’ adjacent sides OA and OC is 15 sq. units, then the area (in sq. units) of the quadrilateral OABC is equal to : (1) 32 (2) 40 (3) 38 (4) 35

202409 Apr Shift 1Vectors
MathsMedium

Q78.If the line 2βˆ’x 3 = 4Ξ»+13yβˆ’2 = 4 βˆ’z makes a right angle with the line x+33ΞΌ = 1βˆ’2y6 = 5βˆ’z7 , then 4Ξ» + 9ΞΌ is equal to : (1) 4 (2) 13 (3) 5 (4) 6

202405 Apr Shift 13D Geometry
MathsMedium

Q78.Let y = y(x) be the solution of the differential equation (2x loge x) dxdy + 2y = x3 loge x, x > 0 and y (eβˆ’1) = 0. Then, y(e) is equal to (1) βˆ’3e (2) βˆ’32e (3) βˆ’23e (4) βˆ’2e

202406 Apr Shift 1Differential Equations
MathsMedium

Q78.Let a unit vector which makes an angle of 60∘ with 2^i + 2^j βˆ’^k and angle 45∘ with ^i βˆ’^k be C. Then β†’ is : C + + (βˆ’12^i 1 ^j βˆ’βˆš23 ^k) 3√2 (1) √2 + βˆ’ + 3 + 21 )^i 1 )^j + √23 )^k ^i βˆ’12 ^k (2) ( √31 ( √31 3√2 ( √31 2√2 (3) √2 ^i + + 3 3√2 1 ^j βˆ’12 ^k (4) βˆ’βˆš23 ^i + √23 ^j + ( 21 3 )^k

202404 Apr Shift 1Vectors
MathsMedium

Q78.Let β†’π‘Ž and →𝑏 be two vectors such that | →𝑏| = 1 and | →𝑏× β†’π‘Ž| = 2 Then |( →𝑏× β†’π‘Ž) - →𝑏| (1) 3 (2) 5 (3) 1 (4) 4

202430 Jan Shift 2Vectors
MathsEasy

Q78.Let β†’a = 2^i + Ξ±^j + ^k,β†’b = βˆ’^i + ^k, β†’c = Ξ²^j βˆ’^k, where Ξ± and Ξ² are integers and Ξ±Ξ² = βˆ’6. Let the values of the √21 ordered pair (Ξ±, Ξ²), for which the area of the parallelogram of diagonals β†’a + β†’b and β†’b + β†’c is , be (Ξ±1, Ξ²1) 2 and (Ξ±2, Ξ²2). Then Ξ±21 + Ξ²21 βˆ’Ξ±2Ξ²2 is equal to (1) 19 (2) 17 (3) 24 (4) 21

202409 Apr Shift 2Vectors & 3D
MathsMedium

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