RankLab
Back to Questions
MathsMediumNumerical2021 ยท 31 Aug Shift 1

Q82.The number of six letter words (with or without meaning), formed using all the letters of the word 'VOWELS', so that all the consonants never come together, is k is equal to is the term, independent of x, in the binomial expansion of ( x4 โˆ’12x2 )12, then

What This Question Tests

This question tests the ability to solve permutation problems involving constraints, specifically using the complementary counting principle to find arrangements where certain items never come together.

Concepts Tested

PermutationComplementary counting

Formulas Used

n!

Total arrangements - arrangements where a condition is met = arrangements where condition is not met

๐Ÿ“š NCERT Sections This Tests

8.17 โ€” Complete Each Synthesis By Giving Missing Starting Material, Reagent Or Products

Chemistry Class 12 ยท Chapter 8

69% match

8.17 Complete each synthesis by giving missing starting material, reagent or products

5.15 โ€” Discuss The Nature Of Bonding In The Following Coordination Entities On The

Chemistry Class 11 ยท Chapter 5

69% match

5.15 Discuss the nature of bonding in the following coordination entities on the basis of valence bond theory: (i) [Fe(CN)6] 4โ€“ (ii) [FeF6] 3โ€“ (iii) [Co(C2O4)3]3โ€“ (iv) [CoF6] 3โ€“

11.6 โ€” The Threshold Frequency For A Certain Metal Is 3.3 ร— 1014 Hz. If Light

Physics Class 12 ยท Chapter 11

69% match

11.6 The threshold frequency for a certain metal is 3.3 ร— 1014 Hz. If light of frequency 8.2 ร— 1014 Hz is incident on the metal, predict the cut- off voltage for the photoelectric emission.

๐Ÿ“‹ Question Details

Chapter
Permutation & Combination
Topic
Arrangement problems with constraints
Year
2021
Shift
31 Aug Shift 1
Q Number
Q82
Type
Numerical
NCERT Ref
Class 11 Mathematics Ch 7: Permutations and Combinations

More from this Chapter

Q85.The set S = {1, 2, 3, โ€ฆ , 12) is to be partitioned into three sets A, B, C of equal size. Thus, A โˆชB โˆชC = S, A โˆฉB = B โˆฉC = A โˆฉC = ฯ• . The number of ways to partition S is (1) 12! (2) 12! 3!(4!)3 3!(3!)4 (3) 12! (4) 12! (4!)3 (3!)4

2007
Medium

Q74.In a shop there are five types of ice-creams available. A child buys six ice-creams. Statement -1: The number of different ways the child can buy the six ice-creams is 10C5 . Statement โˆ’2 : The number of different ways the child can buy the six ice-creams is equal to the number of different ways of arranging 6 A's and 4 B's in a row. (1) Statement โˆ’1 is false, Statement โˆ’2 is true (2) Statement โˆ’1 is true, Statement โˆ’2 is true, Statement โˆ’2 is a correct explanation for Statement โˆ’1 (3) Statement โˆ’1 is true, Statement โˆ’2 is true; (4) Statement โˆ’1 is true, Statement โˆ’2 is false. Statement โˆ’2 is not a correct explanation for Statement โˆ’1.

2008
Medium

Q75.How many different words can be formed by jumbling the letters in the word MISSISSIPPI in which no two S are adjacent? (1) 8 โ‹…6C4 โ‹…7C4 (2) 6.8 โ‹…7C4 (3) 6 โ‹…7 โ‹…8C4 (4) 7 โ‹…6C4 โ‹…8C4

2008
Hard

Q63.From 6 different novels and 3 different dictionaries, 4 novels and 1 dictionary are to be selected and arranged in a row on the shelf so that the dictionary is always in the middle. Then the number of such arrangements is (1) less than 500 (2) at least 500 but less than 750 (3) at least 750 but less than 1000 (4) at least 1000

2009
Medium
More Mathematics questions