Q62.Let ๐1, ๐2 โฆ , ๐15 be 15 points on a circle. The number of distinct triangles formed by points ๐๐, ๐๐, ๐๐ such that ๐+ ๐+ ๐โ 15, is : (1) 455 (2) 419 (3) 12 (4) 443
What This Question Tests
This question tests the ability to calculate the total number of triangles that can be formed from a given set of points on a circle, and then subtract the specific triangles that satisfy a given condition.
Concepts Tested
Formulas Used
C(n, r) = n! / (r! * (n-r)!)
๐ NCERT Sections This Tests
5.12 โ Write All The Geometrical Isomers Of [Pt(Nh3)(Br)(Cl)(Py)] And How Many Of
Chemistry Class 11 ยท Chapter 5
5.12 Write all the geometrical isomers of [Pt(NH3)(Br)(Cl)(py)] and how many of these will exhibit optical isomers?
14.2 โ Which Of The Statements Given In Exercise 14.1 Is True For P-Type
Physics Class 12 ยท Chapter 14
14.2 Which of the statements given in Exercise 14.1 is true for p-type semiconductos.
5.15 โ Discuss The Nature Of Bonding In The Following Coordination Entities On The
Chemistry Class 11 ยท Chapter 5
5.15 Discuss the nature of bonding in the following coordination entities on the basis of valence bond theory: (i) [Fe(CN)6] 4โ (ii) [FeF6] 3โ (iii) [Co(C2O4)3]3โ (iv) [CoF6] 3โ
๐ Question Details
- Chapter
- Permutation & Combination
- Topic
- Combinations
- Year
- 2021
- Shift
- 01 Sep Shift 2
- Q Number
- Q62
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 7: Permutation and Combination
More from this Chapter
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