Q63.If ๐ is the number of ways five different employees can sit into four indistinguishable offices where any office may have any number of persons including zero, then ๐ is equal to: (1) 47 (2) 53 (3) 51 (4) 43
What This Question Tests
This problem involves distributing 5 distinct employees into 4 indistinguishable offices, which is a classic application of Stirling numbers of the second kind, or can be solved by considering partitions of the set of employees.
Concepts Tested
Formulas Used
S(n, k) = (1/k!) * ฮฃ(j=0 to k) (-1)^j * (kCj) * (k-j)^n (Stirling number of second kind)
Alternatively, sum of distributions into 1, 2, 3, 4 non-empty boxes.
๐ NCERT Sections This Tests
5.15 โ Discuss The Nature Of Bonding In The Following Coordination Entities On The
Chemistry Class 11 ยท Chapter 5
5.15 Discuss the nature of bonding in the following coordination entities on the basis of valence bond theory: (i) [Fe(CN)6] 4โ (ii) [FeF6] 3โ (iii) [Co(C2O4)3]3โ (iv) [CoF6] 3โ
12.5 โ A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 ยท Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
5.18 โ What Is Crystal Field Splitting Energy? How Does The Magnitude Of Do Decide
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๐ Question Details
- Chapter
- Permutation & Combination
- Topic
- Distribution of distinct items into indistinguishable boxes
- Year
- 2024
- Shift
- 01 Feb Shift 1
- Q Number
- Q63
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 7: Permutations and Combinations
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