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MathsMediumMCQ2021 · 26 Feb Shift 2

Q62.The sum of the series ∑∞n=1 n2+6n+10(2n+1)! is equal to (1) 41 8 e + 198 e−1 + 10 (2) 418 e + 198 e−1 −10 (3) −418 e + 198 e−1 −10 (4) 418 e −198 e−1 −10 + + …

What This Question Tests

This question involves solving a system of equations to find exponents in prime factorization and then applying the formula for the number of odd divisors.

Concepts Tested

Prime factorizationNumber of divisorsFactors of a number

Formulas Used

Number of divisors = (x+1)(y+1)(z+1) for n = p1^x p2^y p3^z

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📋 Question Details

Chapter
Permutation & Combination
Topic
Number of divisors
Year
2021
Shift
26 Feb Shift 2
Q Number
Q62
Type
MCQ
NCERT Ref
Class 11 Mathematics Ch 7: Permutations and Combinations

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