Q83.Let n be a non-negative integer. Then the number of divisors of the form 4n + 1 of the number (10)10 โ (11)11 โ (13)13 is equal to _____.
What This Question Tests
This question tests the ability to find the prime factorization of a large number and then count the number of its divisors that are of the specific form 4n+1, requiring modular arithmetic analysis of prime factors.
Concepts Tested
Formulas Used
If N = p1^a1 * p2^a2 * ... * pk^ak, number of divisors is (a1+1)(a2+1)...(ak+1)
๐ NCERT Sections This Tests
1.3 โ Define The Following Terms:
Chemistry Class 11 ยท Chapter 1
1.3 Define the following terms: (i) Mole fraction (ii) Molality (iii) Molarity (iv) Mass percentage.
12.5 โ A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 ยท Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
5.23 โ Give The Oxidation State, D Orbital Occupation And Coordination Number Of
Chemistry Class 11 ยท Chapter 5
5.23 Give the oxidation state, d orbital occupation and coordination number of the central metal ion in the following complexes: (i) K3[Co(C2O4)3] (iii) (NH4)2[CoF4] (ii) cis-[CrCl2(en)2]Cl (iv) [Mn(H2O)6]SO4
๐ Question Details
- Chapter
- Permutation & Combination
- Topic
- Number of divisors
- Year
- 2021
- Shift
- 27 Jul Shift 2
- Q Number
- Q83
- Type
- Numerical
- NCERT Ref
- Class 11 Mathematics Ch 7: Permutations and Combinations
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