Practice Questions
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Q45.A chemist has 4 samples of artificial sweetener A, B, C and D . To identify these samples, he performed certain experiments and noted the following observations: (i) A and D both form blue-violet colour with ninhydrin. (ii) Lassaigne extract of C gives positive AgNO3 test and negative Fe4[Fe(CN)6]3 test. (iii) Lassaigne extract of B and D gives positive sodium nitroprusside test. Based on these observations which option is correct? (1) A : Aspartame; B : Saccharin; C : Sucralose; D : (2) A : Alitame; B : Saccharin; C : Aspartame; D : Alitame Sucralose (3) A : Saccharin; B : Alitame; C : Sucralose; D : (4) A : Aspartame; B : Alitame; C : Saccharin; D : Aspartame Sucralose
Q52.If z1, z2 are complex numbers such that Re (z1) = |z1 β1| and Re (z2) = |z2 β1| and arg(z1 βz2) = Ο6 , then Im(z1 + z2) is equal to : (1) 2β3 (2) β3 2 (3) 1 (4) 2 β3 β3
Q53.Let u = zβki2z+i , z = x + iy and k > 0. If the curve represented by Re (u)+ Im (u) = 1 intersects the y-axis at points P and Q where PQ = 5 then the value of k is (1) 3 (2) 1 2 2 (3) 4 (4) 2
Q54.If Ξ± and Ξ², be the coefficients of x4 and x2 , respectively in the expansion of 6 6 + βx2 + ββx2 (x β1) (x β1) , then (1) Ξ± + Ξ² = 60 (2) Ξ± + Ξ² = β30 (3) Ξ± βΞ² = 60 (4) Ξ± βΞ² = β132
Q54.The value of ( 2 β 1 P0 β3 β 2 P1 + 4 β 3 P2β. . . . . . . . up to 51th term) +( 1! β2! + 3!β. . . . . . . up to 51th term) is equal to (1) 1 β51(51)! (2) 1 + (51)! (3) 1 + (52)! (4) 1 1 1 n 2 + 5 8 is exactly 33, then the least value of n is
Q54.Let a, b, c, d and p be non-zero distinct real numbers such that (a2 + b2 + c2)p2 β2(ab + bc + cd)p + (b2 + c2 + d2) = 0. Then (1) a, b, c are in A.P. (2) a, c, p are in G.P. (3) a, b, c, d are in G.P. (4) a, b, c, d are in A.P. is equal to
Q55.Let Ξ± > 0, Ξ² > 0 be such that Ξ±3 + Ξ²2 = 4 . If the maximum value of the term independent of x in the 1 10 10k, then k is equal to binomial expansion of (Ξ±x 9 + Ξ²xβ16 ) is (1) 336 (2) 352 (3) 84 (4) 176
Q55.The value of cos3( Ο8 ). cos( 3Ο8 ) + sin3( Ο8 ). sin( 3Ο8 ) is: (1) 1 (2) 1 β2 2β2 (3) 1 (4) 1 2 4
Q55.Let S be the sum of the first 9 term of the series : {x + ka} + {x2 + (k + 2)a} + {x3 + (k + 4)a} + {x4 + (k + 6)a} + β¦ where a β 0 and x β 1 . If x10βx+45a(xβ1) S = xβ1 , then k is equal to (1) β5 (2) 1 (3) β3 (4) 3
Q56.For a > 0, let the curves C1 : y2 = ax and C2 : x2 = ay intersect at origin O and a point P. Let the line x = b(0 < b < a) intersect the chord OP and the x -axis at points Q and R, respectively. If the line x = b bisects the area bounded by the curves, C1 and C2, and the area of ΞOQR = 21 , then β a β satisfies the equation: (1) x6 β6x3 + 4 = 0 (2) x6 β12x3 + 4 = 0 (3) x6 + 6x3 β4 = 0 (4) x6 β12x3 β4 = 0
Q56.Let P be a point on the parabola, y2 = 12x and N be the foot of the perpendicular drawn from P , on the axis of the parabola. A line is now drawn through the mid-point M of PN , parallel to its axis which meets the parabola at Q . If the yβintercept of the line NQ is 43 , then : JEE Main 2020 (03 Sep Shift 1) JEE Main Previous Year Paper (1) PN = 4 (2) MQ = 13 (3) MQ = 14 (4) PN = 3
Q56.In the expansion of ( cosx ΞΈ + x sin1 ΞΈ )16, if l1 is the least value of the term independent of 8 β€ΞΈ β€Ο4 and l2 is the least value of the term independent of x when 16Ο β€ΞΈ β€Ο8 , then the ratio l2 : l1 is equal to: (1) 1 : 8 (2) 16 : 1 (3) 8 : 1 (4) 1 : 16
Q56.A triangle ABC lying in the first quadrant has two vertices as A(1, 2) and B(3, 1). If β BAC = 90o,and ar (Ξ ABC) = 5β5 sq. units, then the abscissa of the vertex C is : JEE Main 2020 (04 Sep Shift 1) JEE Main Previous Year Paper (1) 1 + β5 (2) 1 + 2β5 (3) 2 + β5 (4) 2β5 β1 y2
Q57.If the point P on the curve, 4x2 + 5y2 = 20 is farthest from the point Q(0, β4), then PQ2 is equal to (1) 36 (2) 48 (3) 21 (4) 29
Q57.Let the line y = mx and the ellipse 2x2 + y2 = 1 intersect at a point P in the first quadrant. If the normal to , (0, Ξ²), then Ξ² is equal to 0) and this ellipse at P meets the co-ordinate axes at (β 3β21 (1) 2β2 (2) 2 3 β3 (3) 2 (4) β2 3 3 JEE Main 2020 (08 Jan Shift 1) JEE Main Previous Year Paper Q58. 3x2+2 x21 lim is equal to xβ0 ( 7x2+2 ) (1) 1 (2) 1 e e2 (3) e2 (4) e
Q58.Let P(3, 3) be a point on the hyperbola, x2 βy2 = 1. If the normal to it at P intersects the x-axis at (9, 0) a2 b2 and e is its eccentricity, then the ordered pair (a2, e2) is equal to: (1) ( 29 , 3) (2) ( 32 , 2) (3) ( 29 , 2) (4) (9, 3)
Q58.If Ξ± is the positive root of the equation, p(x) = x2 βx β2 = 0, then lim β1βcosx+Ξ±β4p(x) is equal to xβΞ±+ (1) 23 (2) β23 (3) 1 (4) 12 β2
Q58.The area (in sq. units) of an equilateral triangle inscribed in the parabola y2 = 8x, with one of its vertices on the vertex of this parabola is (1) 64β3 (2) 256β3 (3) 192β3 (4) 128β3 JEE Main 2020 (02 Sep Shift 2) JEE Main Previous Year Paper
Q58.If the line y = m x + c is a common tangent to the hyperbola 100x2 βy264 = 1 and the circle x2 + y2 = 36, then which one of the following is true? (1) c2 = 369 (2) 5m = 4 (3) 4c2 = 369 (4) 8m + 5 = 0
Q60.If the system of linear equations 2x + 2ay + az = 0 2x + 3by + bz = 0 2x + 4cy + cz = 0, where a, b, c βR are non-zero and distinct; has a non-zero solution, then (1) a 1 , 1b , 1c are in A. P. (2) a, b, c are in G. P. (3) a + b + c = 0 (4) a, b, c are in A. P.
Q60.Let 50βͺ = βͺn = T , where each Xi contains 10 elements and each Yi contains 5 elements. If each element i=1Xi i=1Yi of the set T is an element of exactly 20 of sets Xi 's and exactly 6 of sets Yi 's then n is equal to : (1) 15 (2) 50 (3) 45 (4) 30
Q60.Let A be a 2 Γ 2 real matrix with entries from {0, 1} and |A| β 0 . Consider the following two statements; (P) If A β l2 , then |A| = β1 (Q) If |A| = 1 , then tr(A) = 2 Where l2 denotes 2 Γ 2 identity matrix and tr(A) denotes the sum of the diagonal entries of A . Then (1) (P) is false and (Q) is true (2) Both (P) and (Q) are false (3) (P) is true and (Q) is false (4) Both (P) and (Q) are true
Q61.If for some Ξ± and Ξ² in R , the intersection of the following three planes x + 4y β2z = 1 x + 7y β5z = Ξ² x + 5y + Ξ±z = 5 is a line in R3 , then Ξ± + Ξ² is equal to: (1) 0 (2) 10 (3) 2 (4) β10 Q62. ; x < 0 β§ sin(a+2)x+sinxx If f(x) = is continuous at x = 0 , then a + 2b is equal to: β¨ b ; x = 0 ; x > 0 β© (x+3x2)1/3βx1/3x1/3 (1) 1 (2) β1 (3) 0 (4) β2
Q62.Let [t] denote the greatest integer β€t and xβ0x[lim discontinuous, when x is equal to: (1) βA + 1 (2) βA + 5 (3) βA + 21 (4) βA
Q63.Suppose f(x) is a polynomial of degree four having critical points at β1, 0, 1. If T = {x βR |f(x) = f(0)}, then the sum of squares of all the elements of T is : (1) 4 (2) 6 (3) 2 (4) 8