Practice Questions

Q59.From 6.55 g of aniline, the maximum amount of acetanilide that can be prepared will be ______ ×10−1 g.

Q59.Time required for completion of 99 . 9% of first order reaction is ________ times of half life (t1 / 2 ) of the reaction

Q59.Consider the following data for the given reaction 2 HI(g) →H2( g) + I2( g) HI(molL−1) 0. 005 0. 01 0. 02 Rate (molL−1 s−1) 7. 5 × 10−4 3. 0 × 10−3 1. 2 × 10−2 The order of the reaction is __________.

Q59.Consider the given chemical reaction sequence : Total sum of oxygen atoms in Product A and Product B are _______

Q59.Two moles of benzaldehyde and one mole of acetone under alkaline conditions using aqueous NaOH after heating gives x as the major product. The number of π bonds in the product x is _______

Q59.If 279 g of aniline is reacted with one equivalent of benzenediazonium chloride, the maximum amount of aniline yellow formed will be _______ g. (nearest integer) (consider complete conversion).

Q59.Total number of species from the following with central atom utilising sp2 hybrid orbitals for bonding is _____. NH3, SO2, SiO2, BeCl2, C2H2, C2H4, BCl3, HCHO, C6H6, BF3, C2H4Cl2

Q59.The product (C) in the following sequence of reactions has ______ π bonds.

Q59.A compound 𝑥 with molar mass 108𝑔 mol−1 undergoes acetylation to give product with molar mass 192𝑔 mol−1. The number of amino groups in the compound 𝑥 is ________.

Q59.The half-life of radioisotopic bromine - 82 is 36 hours. The fraction which remains after one day is _________ ×10−2 . (Given antilog 0. 2006 = 1. 587) Round off to the nearest integer

Q59.The major products from the following reaction sequence are product A and product B. The total sum of π electrons in product A and product B are _______ (nearest integer) Q60. 9.3 g of pure aniline upon diazotisation followed by coupling with phenol gives an orange dye. The mass of orange dye produced (assume 100\% yield/conversion) is _______ g. (nearest integer)

Q60.The number of white coloured salts among the following is ....... A SrSO4 B MgNH4PO4 C BaCrO4 D Mn ( OH ) E PbSO4 F PbCrO4 2 G AgBr H PbI2 I CaC2O4 J Fe ( OH ) 2CH3COO

Q60.The Spin only magnetic moment value of square planar complex PtNH32ClNH2CH3Cl is _______ B.M. (Nearest integer) ( Given atomic number for Pt = 78 )

Q60.Vanillin compound obtained from vanilla beans, has total sum of oxygen atoms and π electrons is ______

Q60.From the compounds given below, number of compounds which give positive Fehling's test is Benzaldehyde, Acetaldehyde, Acetone, Acetophenone,Methanal, 4-nitrobenzaldehyde, cyclohexane carbaldehyde. + i = √−1 and α, β ∈R, then α + β is equal to

Q60.The total number of correct statements, regarding the nucleic acids is _________. A. RNA is regarded as the reserve of genetic information. B. DNA molecule self-duplicates during cell division C. DNA synthesizes proteins in the cell. D. The message for the synthesis of particular proteins is present in DNA E. Identical DNA strands are transferred to daughter cells.

Q60. Xg of ethylamine is subjected to reaction with NaNO2/HCl followed by water; evolved dinitrogen gas which occupied 2.24 L volume at STP. X is ×10−1 g.

Q60.Molar mass of the salt from NaBr, NaNO3, KI and CaF2 which does not evolve coloured vapours on heating with concentrated H2SO4 is ____ g mol – 1, (Molar mass in g mol – 1 : Na : 23, N : 14, K : 39, O : 16, Br : 80, I : 127, F : 19, Ca : 40 )

Q60.Number of amine compounds from the following giving solids which are soluble in NaOH upon reaction with Hinsberg's reagent is _______

Q60.Total number of essential amino acid among the given list of amino acids is _______ Arginine, Phenylalanine, Aspartic acid, Cysteine, Histidine, Valine, Proline

Q60. In a borax bead test under hot condition, a metal salt (one from the given) is heated at point B of the flame, JEE Main 2024 (05 Apr Shift 1) JEE Main Previous Year Paper resulted in green colour salt bead. The spin-only magnetic moment value of the salt is _______ BM (Nearest integer) [Given atomic number of Cu = 29, Ni = 28, Mn = 25, Fe = 26]

Q61.If 𝑧 is a complex number, then the number of common roots of the equation 𝑧1985 + 𝑧100 + 1 = 0 and 𝑧3 + 2𝑧2 + 2𝑧+ 1 = 0, is equal to : (1) 1 (2) 2 (3) 0 (4) 3

Q61.If 𝛼, 𝛽 are the roots of the equation, x2 - x - 1 = 0 and Sn = 2023𝛼n + 2024𝛽n, then (1) 2 S12 = S11 + S10 (2) S12 = S11 + S10 (3) 2 S11 = S12 + S10 (4) S11 = S10 + S12 4! ! 5! ( ) (

Q61.If 2 and 6 are the roots of the equation ax2 + bx + 1 = 0, then the quadratic equation, whose roots are 2a+b1 and 1 , is : 6a+b (1) 2x2 + 11x + 12 = 0 (2) x2 + 8x + 12 = 0 (3) 4x2 + 14x + 12 = 0 (4) x2 + 10x + 16 = 0

Q62.Let 𝛼= and 𝛽= 3! )4!.! Then : 4! 5! ( ( ) ) (1) 𝛼∈N and 𝛽∉N (2) 𝛼∉N and 𝛽∈N (3) 𝛼∈N and 𝛽∈N (4) 𝛼∉N and 𝛽∉N