Practice Questions
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Q63.For x β©Ύ0, the least value of K, for which 41+x + 41βx, K2 , 16x + 16βx are three consecutive terms of an A.P., is equal to : (1) 8 (2) 4 (3) 10 (4) 16
Q63.If the set R = {(a, b) : a + 5b = 42, a, b βN} has m elements and βmn=1 (1 βin!) = x + iy, where i = ββ1 , then the value of m + x + y is (1) 12 (2) 4 (3) 8 (4) 5
Q63.Suppose 28 - π, π, 70 - πΌ, πΌ are the coefficient of four consecutive terms in the expansion of ( 1 + π₯) π. Then the value of 2πΌ- 3π equals (1) 7 (2) 10 (3) 4 (4) 6 π
Q63.The sum of the series + + + . ... up to 10 terms is 1 β3 β 12 + 14 1 β3 β 22 + 24 1 β3 β 32 + 34 (1) 45 (2) - 45 109 109 55 55 (3) (4) - 109 109
Q63.Let three real numbers a, b, c be in arithmetic progression and a + 1, b, c + 3 be in geometric progression. If a > 10 and the arithmetic mean of a, b and c is 8, then the cube of the geometric mean of a, b and c is (1) 128 (2) 316 (3) 120 (4) 312
Q63.Suppose ΞΈΟ΅ [0, Ο4 ] is a solution of 4 cos ΞΈ β3 sin ΞΈ = 1. Then cos ΞΈ is equal to : (1) 4 (2) 6+β6 (3β6+2) (3β6+2) (3) 4 (4) 6ββ6 (3β6β2) (3β6β2)
Q63.Let A = {n β[100, 700] β©N : n is neither a multiple of 3 nor a multiple of 4 }. Then the number of elements in A is (1) 290 (2) 280 (3) 300 (4) 310
Q63.If loge a, loge b, loge c are in an A. P. and loge a βloge 2b, loge 2b βloge 3c, loge 3c βloge a are also in an A. P., then a : b : c is equal to (1) 9 : 6 : 4 (2) 16 : 4 : 1 (3) 25 : 10 : 4 (4) 6 : 3 : 2
Q63.Let ππ denote the sum of the first n terms of an arithmetic progression. If π10 = 390 and the ratio of the tenth and the fifth terms is 15 : 7, then π15 βπ5 is equal to: (1) 800 (2) 890 (3) 790 (4) 690 1 18 1 1
Q63.If in a G.P. of 64 terms, the sum of all the terms is 7 times the sum of the odd terms of the G.P, then the common ratio of the G.P. is equal to (1) 7 (2) 4 (3) 5 (4) 6
Q63.If π is the number of ways five different employees can sit into four indistinguishable offices where any office may have any number of persons including zero, then π is equal to: (1) 47 (2) 53 (3) 51 (4) 43
Q63.In an increasing geometric progression of positive terms, the sum of the second and sixth terms is 70 and the 3 product of the third and fifth terms is 49 . Then the sum of the 4th , 6th and 8th terms is equal to : (1) 96 (2) 91 (3) 84 (4) 78
Q63.Let a, ar, ar2 , be an infinite G.P. If ββn=0 arn = 57 and ββn=0 a3r3n = 9747, then a + 18r is equal to (1) 46 (2) 38 (3) 31 (4) 27 is
Q63.If all the words with or without meaning made using all the letters of the word "NAGPUR" are arranged as in a dictionary, then the word at 315th position in this arrangement is : (1) NRAGUP (2) NRAPUG (3) NRAPGU (4) NRAGPU
Q63.There are 5 points P1, P2, P3, P4, P5 on the side AB, excluding A and B, of a triangle ABC . Similarly there are 6 points P6, P7, β¦ , P11 on the side BC and 7 points P12, P13, β¦ , P18 on the side CA of the triangle. The number of triangles, that can be formed using the points P1, P2, β¦ , P18 as vertices, is : (1) 776 (2) 796 (3) 751 (4) 771
Q64.The sum of the coefficient of x2/3 and xβ2/5 in the binomial expansion of (x2/3 + 12 xβ2/5) 9 (1) 21/4 (2) 63/16 (3) 19/4 (4) 69/16
Q64.Let ABC be an equilateral triangle. A new triangle is formed by joining the middle points of all sides of the triangle ABC and the same process is repeated infinitely many times. If P is the sum of perimeters and Q is be the sum of areas of all the triangles formed in this process, then : (1) P2 = 6β3Q (2) P2 = 36β3Q (3) P = 36β3Q2 (4) P2 = 72β3Q
Q64.If the term independent of x in the expansion of (βax2 + 2x31 )10 is 105 , then a2 is equal to : (1) 2 (2) 4 (3) 6 (4) 9 JEE Main 2024 (08 Apr Shift 2) JEE Main Previous Year Paper cos 36β+5 sin 18β
Q64.Let |cos ΞΈ cos(60 βΞΈ) cos(60 + ΞΈ)| β€18 , ΞΈΟ΅[0, 2Ο]. Then, the sum of all ΞΈΟ΅[0, 2Ο], where cos 3ΞΈ attains its maximum value, is : (1) 15Ο (2) 18Ο (3) 6Ο (4) 9Ο
Q64.If the constant term in the expansion of 12 + , x β 0, is Ξ± Γ 28 Γ 5β3, then 25Ξ± is equal to : ( 5β3x 2x ) 3β5 (1) 724 (2) 742 (3) 639 (4) 693
Q64. nβ1Cr = (k2 β8)nCr+1 if and only if : (1) 2β2 < k β€3 (2) 2β3 < k β€3β2 (3) 2β3 < k < 3β3 (4) 2β2 < k < 2β3 JEE Main 2024 (27 Jan Shift 1) JEE Main Previous Year Paper
Q64.Let the first three terms 2, p and q , with q β 2, of a G.P. be respectively the 7th , 8th and 13th terms of an A.P. If the 5th term of the G.P. is the nth term of the A.P., then n is equal to: (1) 163 (2) 151 (3) 177 (4) 169
Q64.If the coefficients of x4, x5 and x6 in the expansion of (1 + x)n are in the arithmetic progression, then the maximum value of n is: (1) 7 (2) 21 (3) 28 (4) 14
Q64.If each term of a geometric progression a1, a2, a3, β¦ with a1 = 18 and a2 β a1 , is the arithmetic mean of the next two terms and Sn = a1 + a2 + β¦ + an , then S20 βS18 is equal to (1) 215 (2) β218 (3) 218 (4) β215
Q64.If Ξ±, βΟ2 < Ξ± < Ο2 is the solution of 4 cos ΞΈ + 5 sin ΞΈ = 1, then the value of tan Ξ± is (1) 10ββ10 (2) 10ββ10 6 12 (3) β10β10 (4) β10β10 12 6