Practice Questions

Q44.The group of chemicals used as pesticide is (1) Aldrin, Sodium Chlorate, Sodium arsinite (2) DDT, Aldrin (3) Sodium chlorate, DDT, PAN (4) Dieldrin, Sodium arsinite, Tetrachloroethene

Q44.Given below are two statements, one is labelled as Assertion A and the other is labelled as Reason R . Assertion A: The spin only magnetic moment value for Fe ( CN ) 3 - is 1 . 74 BM, whereas for [Fe(H2O)6] 6 FeH2O6 3 + is 5 . 92 BM . Reason B: In both complexes, Fe is present in +3 oxidation state. In the light of the above statements, choose the correct answer from the options given below: (1) A is false but R is true (2) A is true but R is false (3) Both A and R are true but R is NOT the correct (4) Both A and R are true andR is the correct explanation of A explanation of A

Q44.The vapour pressure vs. temperature curve for a solution solvent system is shown below. The boiling point of the solvent is _____°C.

Q44.The number of pairs of the solution having the same value of the osmotic pressure from the following is (Assume 100% ionization) A. 0. 500 M C2H5 OH(aq) and 0. 25 M KBr(aq) B. 0. 100 M K4[Fe(CN)6](aq) and 0. 100 M FeSO4 (NH4)2 SO4(aq) C. 0. 05 M K4[Fe(CN)6] (aq) and 0. 25 M NaCl (aq) D. 0. 15 M NaCl(aq) and 0. 1 M BaCl2(aq) E. 0. 02 M KCl. MgCl2. 6H2O(aq) and 0. 05 M KCl(aq)

Q44.Match List I with List II List I List II A I Fittig reaction B II Wurtz Fittig reaction JEE Main 2023 (30 Jan Shift 1) JEE Main Previous Year Paper C III Finkelstein reaction D C2H5Cl + NaI →C2H5I + Nacl IV Sandmeyer reaction (1) A–II, B–I, C–III, D–IV (2) A–III, B–II, C–IV, D–I (3) A–IV, B–II, C–III, D–I (4) A–II, B–I, C–IV, D–III

Q44.Consider the cell Pt(s)|H2( s)(latm)|H+(aq, [H+] = 1) Fe3+(aq), Fe2+(aq) ∣Pt (s) 1 H2°= 0 V, T = 298 K Given: EFe3+ / Fe2+°= 0. 771 V and EH+/ 2 If the potential of the cell is 0. 712 V the ratio of concentration of Fe2+ to Fe3+ is (Nearest integer)

Q44.The industrial activity held least responsible for global warming is : (1) manufacturing of cement (2) steel manufacturing (3) Electricity generation in thermal power plants. (4) Industrial production of urea

Q44.A hydrocarbon 'X' with formula C6H8 uses two moles of H2 on catalystic hydrogenation of its one mole. On ozonolysis, 'X' yields two moles of methane dicarbaldehyde. The hydrocarbon 'X' is : (1) hexa- 1, 3, 5 -triene (2) 1-methylcyclopenta- 1, 4−diene (3) cyclohexa −1, 3−diene (4) cyclohexa −1, 4−diene

Q44.Cobalt chloride when dissolved in water forms pink colored complex X which has octahedral geometry. This solution on treating with cone HCl forms deep blue complex, Y which has a Z geometry. X, Y and Z, respectively, are (1) X = CoH2O6 2 + , Y = CoCl4 2 - , Z = Tetrahedral(2) X = CoH2O6 2 + , Y = CoCl6 3 - , Z = Octahedral (3) X = CoH2O6 3 + , Y = CoCl6 3 - , Z = Octahedral(4) X = CoH2O4Cl2 +, Y = CoCl4 2 - , Z = Tetrahedral

Q44.Match List-I with List-II. Choose the correct answer from the options given below: (1) A-II, B-IV, C-I, D-III (2) A-IV, B-I, C-III, D-II (3) A-IV, B-I, C-II, D-III (4) A-II, B-IV, C-III, D-I

Q44.Which of the following are the example of double salt? (A) FeSO4 · NH42SO4 · 6H2O (B) CuSO4 · 4NH3 · H2O (C) K2SO4 · Al2SO43 · 24H2O (D) Fe ( CN · 4KCN ) 2 Choose the correct answer. (1) A and C only (2) A and B only (3) A, B and D only (4) B and D only

Q44.Given below are two statements, one is labelled as Assertion A and the other is labelled as Reason R. Assertion A : Benzene is more stable than hypothetical cyclohexatriene. Reason R : The delocalized π electron cloud is attracted more strongly by nuclei of carbon atoms. In the light of the above statements, choose the correct answer from the options given below: (1) A is true but R is false. (2) A is false but R is true. (3) Both A and R are correct and R is the correct (4) Both A and R are correct but R is NOT the explanation of A. correct explanation of A.

Q44.The descending order of acidity for the following carboxylic acid is- (A) CH3 COOH (B) F3C −COOH JEE Main 2023 (08 Apr Shift 2) JEE Main Previous Year Paper (C) ClCH2 −COOH (D) FCH2 −COOH (E) BrCH2 −COOH Choose the correct answer from the options given below: (1) B > C > D > E > A (2) E > D > B > A > C (3) B > D > C > E > A (4) D > B > A > E > C

Q44.The water quality of a pond was analysed and its BOD was found to be 4. The pond has (1) Highly polluted water (2) Water has high amount of fluoride compounds (3) Very clean water (4) Slightly polluted water

Q44.Match List I with List II. List I List II A.van't Hoff I. Cryoscopic constant factor, i B. kf II. Isotonic solutions Solutions with same C. III. Normal molar mass osmotic pressure Abnormal molar mas Solutions with same composition D.Azeotropes IV. of vapour above it Choose the correct answer from the options given below: (1) A-III, B-I, C-II, D-IV (2) A-III, B-II, C-I, D-IV (3) A-III, B-I, C-IV, D-II (4) A-I, B-III, C-II, D-IV

Q44.In the following reaction ‵X′ is Anhy.AlCl3 −CH3 (CH2)4 CH3 → X HCl major product △ (1) (2) (3) CH3 (CH2)4 CH2 Cl (4) Cl −CH2 −(CH2)4 −CH2 −Cl

Q44.The covalency and oxidation state respectively of boron in BF4 -, are (1) 3 and 5 (2) 3 and 4 (3) 4 and 4 (4) 4 and 3

Q44.The complex with highest magnitude of crystal field splitting energy (Δ0) is (1) [Ti(OH2)6]3+ (2) [Cr (OH2)6]3+ (3) [Mn (OH2)6]3+ (4) [Fe (OH2)6]3+

Q45. (i) O3 −2 −hexene → Products (ii) H2O The two products formed in above reaction are (1) Butanal and acetaldehyde (2) Butanoic acid and acetaldehyde (3) Butanal and acetic acid (4) Butanoic acid and acetic acid

Q45.The octahedral diamagnetic low spin complex among the following is (1) CoNH36 3 + (2) CoF6 3 - (3) CoCl6 3 - (4) NiCl4 2

Q45.The set which does not have ambidentate ligand(s) is (1) C2O42 - , ethylene diammine, H2O (2) EDTA 4 - , NCS-, C2O42 - (3) NO2- , C2O42 - , EDTA 4- (4) C2O42 - , NO2- , NCS-

Q45.Which of the following complexes will exhibit maximum attraction to an applied magnetic field? (1) [Ni ( H2O ) 6] 2 + (2) [Co ( en ) 3] 3 + (3) [Zn ( H2O ) 6] 2 + (4) [Co ( H2O ) 6] 2 +

Q45.Assertion A: Hydrolysis of an alkyl chloride is a slow reaction but in the presence of NaI, the rate of hydrolysis increases. Reason R: I- is a good nucleophile as well as a good leaving group. In the light of the above statements, choose the correct answer from the options given below. (1) A is false but R is true (2) A is true but R is false (3) Both A and R are true and R is the correct (4) Both A and R are true and R is not the correct explanation of A explanation of A

Q45.Correct statement about smog is (1) NO2 is present in classical smog (2) Both NO2 and SO2 are present in classical smog (3) Photochemical smog has high concentration of (4) Classical smog also has high concentration of oxidizing agents oxidizing agents

Q45.The major product formed in the Friedel-Craft acylation of chlorobenzene is (1) (2) (3) (4) Q46. ‘ A’ formed in the above reaction is (1) (2) (3) (4)