Practice Questions
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Q68.A spherical gas balloon of radius 16 meter subtends an angle 60Β° at the eye of the observer π΄ while the angle of elevation of its center from the eye of π΄ is 75Β°. Then the height (in meter) of the top most point of the balloon from the level of the observer's eye is : (1) 8 ( 2 + 2β3 + β2 ) (2) 8 ( β6 + β2 + 2 ) (3) 8 ( β2 + 2 + β3 ) (4) 8 ( β6 - β2 + 2 )
Q68.The value of xβ0( (1) 0 (2) 4 (3) β4 (4) β1
Q68.Let A = [aij] be a real matrix of order 3 Γ 3, such that ai1 + ai2 + ai3 = 1, for i = 1, 2, 3 . Then, the sum of all the entries of the matrix A3 is equal to: (1) 2 (2) 1 (3) 3 (4) 9 JEE Main 2021 (22 Jul Shift 1) JEE Main Previous Year Paper
Q68.A ray of light through (2, 1) is reflected at a point P on the yβ axis and then passes through the point (5, 3). If this reflected ray is the directrix of an ellipse with eccentricity 1 and the distance of the nearer focus from this 3 directrix is 8 , then the equation of the other directrix can be: β53 JEE Main 2021 (27 Jul Shift 1) JEE Main Previous Year Paper (1) 11x + 7y + 8 = 0 or 11x + 7y β15 = 0 (2) 11x β7y β8 = 0 or 11x + 7y + 15 = 0 (3) 2x β7y + 29 = 0 or 2x β7y β7 = 0 (4) 2x β7y β39 = 0 or 2x β7y β7 = 0 x2f(2)β4f(x) is equal to:
Q68.Which of the following Boolean expression is a tautology ? (1) (p β§q) β¨(p β¨q) (2) (p β§q) β¨(p βq) (3) (p β§q) β§(p βq) (4) (p β§q) β(p βq)
Q68.Negation of the statement ( πβ¨π) β( πβ¨π) is : (1) ~πβ§πβ§~π (2) ~πβ§πβ§π (3) πβ§~πβ§~π (4) πβ§πβ§π
Q68.Let in a right angled triangle, the smallest angle be ΞΈ. If a triangle formed by taking the reciprocal of its sides is also a right angled triangle, then sin ΞΈ is equal to: (1) β5+1 (2) β5β1 4 2 (3) β2β1 (4) β5β1 2 4
Q68.Let *, β‘β{β§, β¨} be such that the Boolean expression (p*~q) β(p β‘q) is a tautology. Then : (1) *= β¨, β‘= β§ (2) *= β¨, β‘= β¨ (3) *= β§, β‘= β¨ (4) *= β§, β‘= β§
Q68.If in a triangle ABC, AB = 5 units, β B = cosβ1( 53 ) and radius of circumcircle of ΞABC is 5 units, then the area (in sq. units) of ΞABC is: (1) 10 + 6β2 (2) 8 + 2β2 (3) 6 + 8β3 (4) 4 + 2β3 a βR be written as P + Q where P is a symmetric matrix and Q is skew symmetric matrix.
Q68.Consider the following system of equations: x + 2y β3z = a 2x + 6y β11z = b x β2y + 7z = c where a, b and c are real constants. Then the system of equations : (1) has a unique solution when 5a = 2b + c (2) has no solution for all a, b and c (3) has infinite number of solutions when (4) has a unique solution for all a, b and c 5a = 2b + c
Q68.Let A and B be 3 Γ 3 real matrices such that A is a symmetric matrix and B is a skew-symmetric matrix. Then the system of linear equations (A2 B2 βB2 A2)X = O, where X is a 3 Γ 1 column matrix of unknown variables and O is a 3 Γ 1 null matrix, has (1) exactly two solutions (2) infinitely many solutions (3) a unique solution (4) no solution is:
Q68.If for the matrix, A = [ Ξ±1 βΞ±Ξ² ], (1) 3 (2) 1 (3) 2 (4) 4
Q68. sin2 x 1 + cos2 x cos 2x The maximum value of f(x) = 1 + sin2 x cos2 x cos 2x , x βR is sin2 x cos2 x sin 2x (1) β7 (2) 34 (3) β5 (4) 5
Q68.Let Z be the set of all integers, A = {(x, y) βZ Γ Z : (x β2)2 + y2 β€4} B = {(x, y) βZ Γ Z : x2 + y2 β€4} and C = {(x, y) βZ Γ Z : (x β2)2 + (y β2)2 β€4} If the total number of relations from A β©B to A β©C is 2p , then the value of p is: (1) 25 (2) 9 (3) 16 (4) 49
Q68.The value of lim [r]+[2r]+...+[nr] , where r is non-zero real number and [r] denotes the greatest integer less than nββ n2 or equal to r, is equal to : (1) r (2) r 2 (3) 2r (4) 0
Q68.The value of lim cosβ1(xβ[x]2)β sinβ1(xβ[x]2) , where [x] denotes the greatest integer β€x is: xβ0+ xβx3 (1) Ο (2) 0 (3) Ο (4) Ο 4 2
Q68.The number of integral values of m so that the abscissa of point of intersection of lines 3x + 4y = 9 and y = mx + 1 is also an integer, is: (1) 1 (2) 2 (3) 3 (4) 0
Q68.Consider the two statements : (S1) : (p βq) β¨(~q βp) is a tautology. (S2) : (p β§~q) β§(~p β¨q) is a fallacy. Then : (1) only (S1) is true. (2) both (S1) and (S2) are false. (3) only (S2) is true. (4) both (S1) and (S2) are true. Q69. β‘ 1 0 0β€ Let A = 0 1 1 . Then A2025 βA2020 is equal to β£ 1 0 0β¦ (1) A6 βA (2) A6 (3) A5 (4) A5 βA
Q69.Let A = [2a 30 ], If det (Q) = 9 , then the modulus of the sum of all possible values of determinant of P is equal to: (1) 36 (2) 24 (3) 45 (4) 18
Q69.A possible value of tan( 41 sinβ1 β638 ) (1) 2β2 β1 (2) 1 2β2 (3) β7 β1 (4) 1 β7
Q69.The value of k βR, for which the following system of linear equations 3x βy + 4z = 3 x + 2y β3z = β2 JEE Main 2021 (20 Jul Shift 2) JEE Main Previous Year Paper 6x + 5y + kz = β3 has infinitely many solutions, is: (1) 3 (2) β5 (3) 5 (4) β3
Q69.The values of π and π, for which the system of equations 2π₯+ 3π¦+ 6π§= 8 π₯+ 2π¦+ ππ§= 5 3π₯+ 5π¦+ 9π§= π JEE Main 2021 (25 Jul Shift 1) JEE Main Previous Year Paper has no solution, are : (1) π= 3, πβ 13 (2) πβ 3, πβ 13 (3) πβ 3, π= 3 (4) π= 3, π= 13
Q69.The system of linear equations 3π₯- 2π¦- ππ§= 10 2π₯- 4π¦- 2π§= 6 π₯+ 2π¦- π§= 5 π is inconsistent if : 4 4 (1) π= 3, πβ (2) π= 3, π= 5 5 (3) πβ 3, πβπ (4) πβ 3, πβ 4 5 1 2 Then the composition
Q69.Which of the following is the negation of the statement "for all M > 0, there exists x βS such that x β₯M β²β²? (1) there exists M > 0, such that x < M for all (2) there exists M > 0, there exists x βS such that x βS x β₯M (3) there exists M > 0, there exists x βS such that (4) there exists M > 0 such that x β₯M for all x < M x βS
Q69.Let A be a symmetric matrix of order 2 with integer entries. If the sum of the diagonal elements of A2 is 1, then the possible number of such matrices is: (1) 12 (2) 4 (3) 1 (4) 6