Practice Questions

Q60.Number of bridging CO ligands in [Mn2 (CO)10] is

Q60.Three moles of AgCl get precipitated when one mole of an octahedral co-ordination compound with empirical formula CrCl3 . 3NH3 . 3H2O reacts with excess of silver nitrate. The number of chloride ions satisfying the secondary valency of the metal ion is ______ .

Q60.The reaction of white phosphorus on boiling with alkali in inert atmosphere resulted in the formation of product A. The reaction 1 mol of A with excess of AgNO3 in aqueous medium gives ________ mole(s) of Ag. (Round off to the Nearest Integer).

Q60.On complete reaction of FeCl3 with oxalic acid in aqueous solution containing KOH, resulted in the formation of product A . The secondary valency of Fe in the product A is ______ . (Round off to the Nearest Integer).

Q60.The total number of amines among the following which can be synthesized by Gabriel synthesis is ________.

Q60.The number of optical isomers possible for [Cr (C2O4)3]3− is:

Q60.Gaseous cyclobutene isomerizes to butadiene in a first order process which has a 'K' value of 3 . 3 × 10-4 s-1 at 153°C . The time in minutes it takes for the isomerization to proceed 40% to completion at this temperature is_____. (Rounded off to the nearest integer)

Q60.The number of geometrical isomers possible in triamminetrinitrocobalt (III) is X and in trioxalatochromate (III) is Y. Then the value of X + Y is ____.

Q60.The total number of unpaired electrons present in [Co(NH3)6]Cl2 and [Co(NH3)6]Cl3 is ¯

Q60.A reaction of 0.1 mole of Benzylamine with bromomethane gave 23 g of Benzyl trimethyl ammonium bromide. The number of moles of bromomethane consumed in this reaction are n × 10−1, when n =_____ (Round off to the Nearest Integer). (Given : Atomic masses : C : 12. 0 u, H : 1. 0 u, N : 14. 0 u, Br : 80. 0 u)

Q60.The number of nitrogen atoms in a semicarbazone molecule of acetone is_____

Q60.In Tollen's test for aldehyde, the overall number of electron(s) transferred to the Tollen's reagent formula [Ag (NH3)2]+ per aldehyde group to form silver mirror is ___.(Round off to the Nearest integer)

Q60.The equivalents of ethylene diamine required to replace the neutral ligands from the coordination sphere of the trans-complex of CoCl3. 4 NH3 is _______ . (Round off to the Nearest Integer).

Q60.Number of electrons present in 4f orbital of Ho3+ ion is ________ (Given Atomic No. of Ho =67)

Q60.An aqueous solution of NiCl2 was heated with excess sodium cyanide in presence of strong oxidizing agent to form [Ni(CN)6]2−. The total change in number of unpaired electrons on metal centre is ___________.

Q60.A peptide synthesized by the reactions of one molecule each of Glycine, Leucine, Aspartic acid and Histidine will have _____ peptide linkages.

Q60.The number of compound/s given below which contain/s −COOH group is ___ . (Integer answer) (A) Sulphanilic acid (B) Picric acid (C) Aspirin (D) Ascorbic acid

Q60.Among the following, the number of halide(s) which is/ are inert to hydrolysis is (A) BF3 (B) SiCl4 (C) PCl5 (D) SF6

Q60.The number of stereo isomers possible for [Co (ox)2(Br)(NH3)]2− is __________. [ ox = oxalate] JEE Main 2021 (26 Feb Shift 2) JEE Main Previous Year Paper

Q61.Let 𝑝 and 𝑞 be two positive numbers such that 𝑝+ 𝑞= 2 and 𝑝4 + 𝑞4 = 272. Then 𝑝 and 𝑞 are roots of the equation: (1) 𝑥2 - 2𝑥+ 2 = 0 (2) 𝑥2 - 2𝑥+ 8 = 0 (3) 𝑥2 - 2𝑥+ 136 = 0 (4) 𝑥2 - 2𝑥+ 16 = 0

Q61.If (√3 + + + √3 = 0 1)x + √3 = 0 (2) x2 + (√3 1)x (1) x2 −(√3 = 0 = 0 (4) x2 −(√3 −1)x −√3 (3) x2 + (√3 −1)x −√3

Q61.Let α, β be two roots of the equation x2 + (20)1/4x + (5)1/2 = 0 . Then α8 + β8 is equal to JEE Main 2021 (27 Jul Shift 1) JEE Main Previous Year Paper (1) 10 (2) 100 (3) 50 (4) 160

Q61.If α and β are the distinct roots of the equation x2 + (3) 1 1 4 x + 3 2 = 0 , then the value of α96(α12 −1) + β96(β12 −1) is equal to: (1) 56 × 325 (2) 56 × 324 (3) 52 × 324 (4) 28 × 325

Q61.If x2 + 9y2 −4x + 3 = 0, x, y ∈R, then x and y respectively lie in the intervals (1) [−13 , 13 ] and [−13 , 13 ] (2) [1, 3] and [−13 , 13 ] (3) [−13 , 13 ] and [1, 3] (4) [1, 3] and [1, 3]

Q61.The sum of the roots of the equation, 𝑥+ 1 - 2log23 + 2𝑥+ 2log410 - 2-𝑥= 0, is : (1) log214 (2) log212 (3) log213 (4) log211