Practice Questions

Q50.Consider the hydrated ions of Ti2+, V2+, Ti3+ and Sc3+ . The correct order of their spin-only magnetic moments is: JEE Main 2019 (10 Apr Shift 1) JEE Main Previous Year Paper (1) Sc3+ < Ti3+ < V2+ < Ti2+ (2) Ti3+ < Ti2+ < Sc3+ < V2+ (3) Sc3+ < Ti3+ < Ti2+ < V2+ (4) V2+ < Ti2+ < Ti3+ < Sc3+

Q50.Match the ores (column A) with the metals (column B) : (1) (I) - (a); (II) - (b); (III) - (c); (IV) - (d) (2) (I) - (c); (II) - (d); (III) - (b); (IV) - (a) (3) (I) - (c); (II) - (d); (III) - (a); (IV) - (b) (4) (I) - (b); (II) - (c); (III) - (d); (IV) - (a)

Q51.The chloride that CANNOT get hydrolysed is: (1) PbCl4 (2) CCl4 (3) SnCl4 (4) SiCl2

Q51.Increasing order of reactivity of the following compounds for SN1 substitution is: (1) B < C < D < A (2) B < A < D < C (3) A < B < D < C (4) B < C < A < D

Q51.The coordination number of Th in K4 [Th(C2O4)4(H2O)2] is: (C2O2−4 = oxalato ) (1) 14 (2) 6 (3) 8 (4) 10

Q51.The magnetic moment of an octahedral homoleptic Mn(II) complex is 5 .9 B. M. . The suitable ligand for this complex is: (1) CN − (2) CO (3) Ethylenediamine (4) NCS −

Q51.The ore that contains both iron and copper is: (1) Azurite (2) Malachite (3) Dolomite (4) Copper pyrites JEE Main 2019 (09 Jan Shift 1) JEE Main Previous Year Paper

Q51.Hall Heroult's process is given by: (1) Cr2O3 + 2Al →Al2O3 + Cr (2) 2Al2O3 + 3C →4Al + 3CO2 − (3) Cu2+(aq) + H2(g) →Cu(s) + 2H +(aq) (4) ZnO + C Coke,1673→ Zn + CO

Q51.Homoleptic octahedral complexes of a metal ion ′M 3+′ with three monodentate ligands L1, L2 and L3 absorb wavelengths in the region of green, blue and red respectively. The increasing order of the ligand strength is: JEE Main 2019 (09 Jan Shift 2) JEE Main Previous Year Paper (1) L3 > L1 > L2 . (2) L1 > L2 > L3 . (3) L2 > L1 > L3 . (4) L3 > L2 > L1 .

Q51.The pair that has similar atomic radii is: (1) Mo and W (2) Sc and Ni (3) Mn and Re (4) Ti and Hf

Q51.The species that can have a trans-isomer is: (en = ethane −1, 2 −diamine, ox = oxalate) (1) [Cr(en)2(ox)]+ (2) [Pt(en)Cl2] (3) [Zn(en)Cl2] (4) [Pt(en)2Cl2]2+

Q51.The correct order of the oxidation states of nitrogen in NO, N2O, NO2 and N2O3 is (1) N2O < NO < N2O3 < NO2 (2) NO2 < N2O3 < NO < N2O (3) NO2 < NO < N2O3 < N2O (4) N2O < N2O3 < NO < NO2

Q51.A reaction of cobalt (III) chloride and ethylenediamine in a 1 : 2 mole ratio generates two isomeric products A (violet-coloured) and B (green-coloured). A can show optical activity, but, B is optically inactive. What type of isomers do A and B represent? JEE Main 2019 (10 Jan Shift 2) JEE Main Previous Year Paper (1) Coordination isomers (2) Linkage isomers (3) Ionisation isomers (4) Geometrical isomers

Q51.The pair of metal ions that can give a spin only magnetic moment of 3.9 BM for the complex [M(H2O)6]Cl2 , is: (1) Co2+ and Fe2+ (2) V 2+ and Fe2+ (3) Cr2+ and Mn2+ (4) V 2+ and Co2+

Q51.The lanthanide ion that would show colour is: (1) Lu3 + (2) La3 + (3) Gd3 + (4) Sm3 +

Q51.The statement that is INCORRECT about the interstitial compounds is: (1) They have high melting points. (2) They are very hard. (3) They are chemically reactive. (4) They have metallic conductivity.

Q51.The correct statement is: (1) Aniline is a froth stabilizer. (2) Zone refining process is used for the refining of titanium. (3) Zincite is a carbonate ore. (4) Sodium cyanide cannot be used in the metallurgy of silver. JEE Main 2019 (10 Apr Shift 2) JEE Main Previous Year Paper

Q51.The idea of froth flotation method came from a person X and this method is related to the process Y of ores. X and Y, respectivity, are: (1) Washer man and reduction (2) Fisher women and concentration (3) Fisher man and reduction (4) Washer woman and concentration

Q52.The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The metal ion is: (1) Fe2+ (2) Co2+ (3) Ni2+ (4) Mn2+

Q52.The metal's d− orbitals that are directly facing the ligands in K3[Co(CN)6] are: (1) dxy, dxz and dyz (2) dx2−y2 and dz2 (3) dxy and dx2−y2 (4) dxz, dyz and dz2

Q52.The effect of lanthanoid contraction in the lanthanoid series of elements by and large means (1) increase in atomic radii and decrease in ionic (2) decrease in atomic radii and increase in ionic radii, radii. (3) increase in both atomic and ionic radii. (4) decrease in both atomic and ionic radii. JEE Main 2019 (10 Jan Shift 1) JEE Main Previous Year Paper

Q52.The element that usually does NOT show variable oxidation states is: (1) Cu (2) Ti (3) Sc (4) V

Q52.The metal that gives hydrogen gas upon treatment with both the acid as well as the base is (1) Zinc (2) Magnesium (3) Iron (4) Mercury JEE Main 2019 (12 Apr Shift 1) JEE Main Previous Year Paper

Q52.The correct order of the spin –only magnetic moment of metal ions in the following low-spin complexes, 4 - 4 - 3 + 2 + [V ( CN ) 6] , [Fe ( CN ) 6] , [Ru ( NH3 ) 6] and [Cr ( NH3 ) 6] , is: (1) V2 + > Cr2 + > Ru3 +(2)>Cr2Fe2++ > V2 + > Ru3 +(3)> Cr2Fe2++ > Ru3 + > Fe2 +(4)> V2V2++ > Ru3 + > Cr2 + > Fe2 + JEE Main 2019 (08 Apr Shift 1) JEE Main Previous Year Paper

Q52.The major product of the following reaction is, (1) RCOOH (2) RCHO (3) RCH2NH2 (4) RCONH2