Practice Questions

Q60.The total number of correct statements, regarding the nucleic acids is _________. A. RNA is regarded as the reserve of genetic information. B. DNA molecule self-duplicates during cell division C. DNA synthesizes proteins in the cell. D. The message for the synthesis of particular proteins is present in DNA E. Identical DNA strands are transferred to daughter cells.

Q60.The total number of carbon atoms present in tyrosine, an amino acid, is _______

Q60.Total number of essential amino acid among the given list of amino acids is _______ Arginine, Phenylalanine, Aspartic acid, Cysteine, Histidine, Valine, Proline

Q60.From the vitamins 𝐴, 𝐵1, 𝐵6, 𝐵12, 𝐶, 𝐷, 𝐸 and 𝐾, the number vitamins that can be stored in our body is ______.

Q60.The compound formed by the reaction of ethanal with semicarbazide contains _______ number of nitrogen atoms. ¯

Q60.Number of amine compounds from the following giving solids which are soluble in NaOH upon reaction with Hinsberg's reagent is _______

Q60. M2+ + H2 S →A (Black precipitate) + by product Consider the following test for a group-IV cation. A + aqua regia →B + NOCl + S + H2O The B + KNO2 + CH3COOH →C + by product spin-only magnetic moment value of the metal complex C is ______ BM (Nearest integer)

Q60.From the compounds given below, number of compounds which give positive Fehling's test is Benzaldehyde, Acetaldehyde, Acetone, Acetophenone,Methanal, 4-nitrobenzaldehyde, cyclohexane carbaldehyde. + i = √−1 and α, β ∈R, then α + β is equal to

Q60. In a borax bead test under hot condition, a metal salt (one from the given) is heated at point B of the flame, JEE Main 2024 (05 Apr Shift 1) JEE Main Previous Year Paper resulted in green colour salt bead. The spin-only magnetic moment value of the salt is _______ BM (Nearest integer) [Given atomic number of Cu = 29, Ni = 28, Mn = 25, Fe = 26]

Q60.The number of tripeptides formed by three different amino acids using each amino acid once is _______.

Q60.The Spin only magnetic moment value of square planar complex PtNH32ClNH2CH3Cl is _______ B.M. (Nearest integer) ( Given atomic number for Pt = 78 )

Q60. Xg of ethylamine is subjected to reaction with NaNO2/HCl followed by water; evolved dinitrogen gas which occupied 2.24 L volume at STP. X is ×10−1 g.

Q60.The number of white coloured salts among the following is ....... A SrSO4 B MgNH4PO4 C BaCrO4 D Mn ( OH ) E PbSO4 F PbCrO4 2 G AgBr H PbI2 I CaC2O4 J Fe ( OH ) 2CH3COO

Q60. Xg of ethanamine was subjected to reaction with NaNO2/HCl followed by hydrolysis to liberate N2 and HCl. The HCl generated was completely neutralised by 0.2 moles of NaOH. X is ______ g. ∈C : Im and S3 = {z ∈C : Re(z) ≥0}. Then the

Q61.If z = x + iy, xy ≠0, satisfies the equation z2 + iz = 0, then z2 is equal to : (1) 9 (2) 1 (3) 4 (4) 14

Q61.If 𝑧 is a complex number, then the number of common roots of the equation 𝑧1985 + 𝑧100 + 1 = 0 and 𝑧3 + 2𝑧2 + 2𝑧+ 1 = 0, is equal to : (1) 1 (2) 2 (3) 0 (4) 3

Q61.The number of solutions, of the equation 𝑒sin𝑥−2𝑒−sin𝑥= 2 is (1) 2 (2) more than 2 (3) 1 (4) 0

Q61.The sum of all the solutions of the equation (8)2x −16 ⋅(8)x + 48 = 0 is : (1) 1 + log8(6) (2) 1 + log6(8) (3) log8(6) (4) log8(4) –z+1 1

Q61.If z = 21 −2i, is such that z + 1 = αz + β(1 i), (1) −4 (2) 3 (3) 2 (4) −1

Q61.Let α, β; α > β , be the roots of the equation x2 −√2x −√3 = 0. Let Pn = αn −βn, n ∈N . Then (11√3 −10√2)P10 + (11√2 + 10)P11 −11P12 is equal to (1) 10√3P9 (2) 11√3P9 (3) 10√2P9 (4) 11√2P9

Q61.Let 𝑆= 𝑥∈𝑅: √3 + √2 𝑥+ √3 −√2 𝑥= 10. Then the number of elements in 𝑆 is: (1) 4 (2) 0 (3) 2 (4) 1

Q61.The area (in sq. units) of the region S = {z ∈C : |z −1| ≤2; (z + ¯z) + i(z −¯z) ≤2, Im(z) ≥0} is (1) 7π (2) 7π 3 4 (3) 17π (4) 3π 8 2

Q61.Let α, β be the roots of the equation x2 + 2√2x −1 = 0. The quadratic equation, whose roots are α4 + β4 and 1 (α6 + β6), is : 10 (1) x2 −190x + 9466 = 0 (2) x2 −180x + 9506 = 0 (3) x2 −195x + 9506 = 0 (4) x2 −195x + 9466 = 0

Q61.The sum of all possible values of θ ∈[−π, 2π], for which 1−2i1+i coscosθθ is purely imaginary, is equal (1) 3π (2) 2π (3) 5π (4) 4π

Q61.Let r and θ respectively be the modulus and amplitude of the complex number z = 2 −i(2 tan 5π8 ), then (r, θ) is equal to (1) (2 sec 3π8 , 3π8 ) (2) (2 sec 3π8 , 5π8 ) (3) (2 sec 5π8 , 3π8 ) (4) (2 sec 11π8 , 11π8 )