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14,828 questions across 23 years of JEE Main β€” find and practise any topic!

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Q72.Consider the function f : [ 12 , 1] β†’R defined by f(x) = 4√2x3 βˆ’3√2x βˆ’1. Consider the statements (I) The curve y = f(x) intersects the x-axis exactly at one point (II) The curve y = f(x) intersects the x-axis at x = cos 12Ο€ Then (1) Only (II) is correct (2) Both (I) and (II) are incorrect (3) Only (I) is correct (4) Both (I) and (II) are correct

202429 Jan Shift 1Matrices
MathsMedium

Q72.The function f: R->R, f(x) = x2+2xβˆ’15 , x ∈R is x2βˆ’4x+9 (1) one-one but not onto. (2) both one-one and onto. (3) onto but not one-one. (4) neither one-one nor onto. JEE Main 2024 (06 Apr Shift 1) JEE Main Previous Year Paper 1 ), x β‰ 0 x then

202406 Apr Shift 1Sets Relations Functions
MathsHard

Q72.Suppose for a differentiable function h, h(0) = 0, h(1) = 1 and hβ€²(0) = hβ€²(1) = 2. If g(x) = h (ex)eh(x) , then gβ€²(0) is equal to: (1) 5 (2) 4 (3) 8 (4) 3

202406 Apr Shift 2Differentiation
MathsMedium

Q72.If 𝑓π‘₯= 4π‘₯+ 3 , π‘₯β‰ 2 and ( π‘“π‘œπ‘“) ( π‘₯) = 𝑔( π‘₯) , where 𝑔: 𝑅- 2 →𝑅- 2 then ( π‘”π‘œπ‘”π‘œπ‘”) ( 4 ) is equal to 6π‘₯- 4 3 3 3, 19 19 (1) - (2) 20 20 (3) -4 (4) 4 Q73. 𝑔π‘₯, π‘₯≀0 Let 𝑔π‘₯ be a linear function and 𝑓π‘₯= 1 , is continuous at π‘₯= 0. If 𝑓'1 = π‘“βˆ’1, then the value of 1 + π‘₯ π‘₯, π‘₯> 0 2 + π‘₯ 𝑔3 is JEE Main 2024 (31 Jan Shift 1) JEE Main Previous Year Paper 1 4 1 4 (1) 3log𝑒 1 (2) 3log𝑒 9 + 1 9𝑒 3 4 4 (3) log𝑒 9 βˆ’1 (4) log𝑒 1 9𝑒 3 π‘₯𝑦π‘₯- 1π‘₯- 2

202431 Jan Shift 1Differentiation
MathsHard

Q72.A variable line L passes through the point (3, 5) and intersects the positive coordinate axes at the points A and B. The minimum area of the triangle OAB, where O is the origin, is : (1) 30 (2) 25 (3) 40 (4) 35

202409 Apr Shift 1Applications of Derivatives
MathsMedium

Q72.Let the sum of the maximum and the minimum values of the function f(x) = 2x2+3x+82x2βˆ’3x+8 be mn , where gcd(m, n) = 1. Then m + n is equal to : (1) 195 (2) 201 (3) 217 (4) 182 2x , x < 0

202404 Apr Shift 1Applications of Derivatives
MathsMedium

Q72.Given that the inverse trigonometric function assumes principal values only. Let x, y be any two real numbers in [βˆ’1, 1] such that cosβˆ’1 x βˆ’sinβˆ’1 y = Ξ±, βˆ’Ο€2 ≀α ≀π. Then, the minimum value of x2 + y2 + 2xy sin Ξ± is (1) 0 (2) -1 (3) 1 2 (4) βˆ’12 72xβˆ’9xβˆ’8x+1

202404 Apr Shift 2Inverse Trigonometric Functions
MathsMedium

Q72.Let 𝑓: 𝑅→𝑅 and 𝑔: 𝑅→𝑅 be defined as 𝑓π‘₯= log𝑒π‘₯, π‘₯> 0 and 𝑔π‘₯= π‘₯, π‘₯β‰₯0 . Then, π‘”π‘œπ‘“: 𝑅→𝑅 is: π‘’βˆ’π‘₯, π‘₯≀0 𝑒π‘₯, π‘₯< 0 (1) one-one but not onto (2) neither one-one nor onto (3) onto but not one-one (4) both one-one and onto

202401 Feb Shift 1Sets Relations Functions
MathsMedium

Q72.If the domain of the function f(x) = cosβˆ’1( 2βˆ’|x|4 ) equal to : (1) 12 (2) 9 (3) 11 (4) 8

202430 Jan Shift 1Sets Relations Functions
MathsMedium

Q72.Let f : [βˆ’1, 2] β†’R be given by f(x) = 2x2 + x + [x2] βˆ’[x], where [t] denotes the greatest integer less than or equal to t. The number of points, where f is not continuous, is : (1) 5 (2) 6 (3) 3 (4) 4

202405 Apr Shift 2Sets Relations Functions
MathsMedium

Q72.Let y = loge( 1βˆ’x21+x2 ), (1) 732 (2) 746 (3) 742 (4) 736

202429 Jan Shift 2Differentiation
MathsMedium

Q73.Let ∫2βˆ’tan3+tan xx dx = 12 (Ξ±x + loge |Ξ² sin x + Ξ³ cos x|) + C , where C is the constant of integration. Then Ξ± + Ξ²Ξ³ is equal to : (1) 7 (2) 4 (3) 1 (4) 3

202409 Apr Shift 1Applications of Derivatives
MathsMedium

Q73.The function f(x) = 2x + 3x 23 , x ∈R, has (1) exactly one point of local minima and no point of (2) exactly one point of local maxima and no point local maxima of local minima (3) exactly one point of local maxima and exactly (4) exactly two points of local maxima and exactly one point of local minima one point of local minima

202429 Jan Shift 2Applications of Derivatives
MathsMedium

Q73.If the function f(x) = 2x3 βˆ’9x2 + 12a2x + 1, a > 0 has a local maximum at x = Ξ± and a local minimum at x = Ξ±2 , then Ξ± and Ξ±2 are the roots of the equation : JEE Main 2024 (08 Apr Shift 2) JEE Main Previous Year Paper (1) x2 βˆ’6x + 8 = 0 (2) x2 + 6x + 8 = 0 (3) 8x2 + 6x βˆ’1 = 0 (4) 8x2 βˆ’6x + 1 = 0 = Ο€6 . Then eΞ± and eβˆ’Ξ± are the roots of the equation :

202408 Apr Shift 2Applications of Derivatives
MathsMedium

Q73. x2 ⎧ 1βˆ’cos where Ξ±, Ξ² ∈R. If f is continuous at Let f : R β†’R be a function given by f(x) = ⎨ Ξ±, x = 0, β√1βˆ’cos x ⎩ x , x > 0 x = 0, then Ξ±2 + Ξ²2 is equal to : (1) 3 (2) 12 (3) 48 (4) 6 JEE Main 2024 (04 Apr Shift 1) JEE Main Previous Year Paper

202404 Apr Shift 1Limits & Continuity
MathsMedium

Q73.If the function 𝑓: βˆ’βˆž, βˆ’1 β†’π‘Ž, 𝑏 defined by 𝑓π‘₯= 𝑒π‘₯3 βˆ’3π‘₯+ 1 is one-one and onto, then the distance of the point 𝑃2𝑏+ 4, π‘Ž+ 2 from the line π‘₯+ π‘’βˆ’3𝑦= 4 is: (1) 2√1 + 𝑒6 (2) 4√1 + 𝑒6 (3) 3√1 + 𝑒6 (4) √1 + 𝑒6 JEE Main 2024 (31 Jan Shift 2) JEE Main Previous Year Paper

202431 Jan Shift 2Sets Relations Functions
MathsHard

Q73.Let g : R β†’R be a non constant twice differentiable such that gβ€²( 21 ) = gβ€²( 23 ). If a real valued function f is defined as f(x) = 12 [ g(x) + g(2 βˆ’x)], then (1) f β€²β€²(x) = 0 for atleast two x in (0, 2) (2) f β€²β€²(x) = 0 for exactly one x in (0, 1) (3) f β€²β€²(x) = 0 for no x in (0, 1) (4) f β€²( 23 ) + f β€²( 21 ) = 1

202430 Jan Shift 1Applications of Derivatives
MathsHard

Q73.Let 𝑓: 𝑅- {0} →𝑅 be a function satisfying 𝑓 π‘₯ 𝑓( π‘₯) for all π‘₯, 𝑦, 𝑓( 𝑦) β‰ 0. If 𝑓' (1) = 2024, then 𝑦= 𝑓( 𝑦) (1) π‘₯𝑓'π‘₯- 2024𝑓π‘₯= 0 (2) π‘₯𝑓'π‘₯+ 2024𝑓π‘₯= 0 (3) π‘₯' (π‘₯) + 𝑓(π‘₯) = 2024 (4) π‘₯𝑓' (π‘₯) - 2023𝑓(π‘₯) = 0

202430 Jan Shift 2Differential Equations
MathsMedium

Q73.If the function f(x) = , x β‰ 0 √2βˆ’βˆš1+cos x is continuous at x = 0, then the value of a2 is equal to { a loge 2 loge 3 , x = 0 (1) 968 (2) 1152 (3) 746 (4) 1250

202404 Apr Shift 2Limits & Continuity
MathsMedium

Q73.If loge y = 3 sinβˆ’1 x, then (1 βˆ’x2)yβ€²β€² βˆ’xyβ€² at x = 12 is equal to (1) 3eΟ€/6 (2) 9eΟ€/2 (3) 3eΟ€/2 (4) 9eΟ€/6 y β‰₯0, y(0) = 0. Then at x = 2, yβ€²β€² + y + 1 is equal to

202409 Apr Shift 2Functions
MathsMedium

Q73.Let 𝑓: 𝑅→𝑅 be defined as π‘Žβˆ’π‘cos2π‘₯ ; π‘₯< 0 π‘₯2 𝑓π‘₯= π‘₯2 + 𝑐π‘₯+ 2; 0 ≀π‘₯≀1 2π‘₯+ 1; π‘₯> 1 If 𝑓 is continuous everywhere in 𝑅 and π‘š is the number of points where 𝑓 is NOT differential then π‘š + π‘Ž + 𝑏 + 𝑐 equals: JEE Main 2024 (01 Feb Shift 1) JEE Main Previous Year Paper (1) 1 (2) 4 (3) 3 (4) 2 1

202401 Feb Shift 1Limits & Continuity
MathsHard

Q73.The function f : N βˆ’{1} β†’N; defined by f(n) = the highest prime factor of n, is : (1) both one-one and onto (2) one-one only (3) onto only (4) neither one-one nor onto JEE Main 2024 (27 Jan Shift 1) JEE Main Previous Year Paper Q74. , x < 3 ⎧ a(7xβˆ’12βˆ’x2)b|x2βˆ’7x+12| Consider the function f(x) = sin(xβˆ’3) ,where [x] denotes the greatest integer less than or equal xβˆ’[x] ⎨ 2 , x > 3 ⎩ b , x = 3 to x . If S denotes the set of all ordered pairs (a, b) such that f(x) is continuous at x = 3, then the number of elements in S is : (1) 2 (2) Infinitely many (3) 4 (4) 1 dx = a + b√2 + c√3, where a, b, c are rational numbers, then 2a + 3 b βˆ’4c is equal to :

202427 Jan Shift 1Sets Relations Functions
MathsMedium

Q73.If y(ΞΈ) = cos 3ΞΈ+42 coscosΞΈ+cos2ΞΈ+52ΞΈcos ΞΈ+2 , then at ΞΈ = Ο€2 , yβ€²β€² + yβ€² + y is equal to : (1) 21 (2) 1 (3) 2 (4) 32 20

202405 Apr Shift 2Limits & Continuity
MathsMedium

Q73.If f(x) = {x30 sin, x (= 0 (1) f β€²β€² ( Ο€2 ) = 24βˆ’Ο€22Ο€ (2) f β€²β€² ( Ο€2 ) = 12βˆ’Ο€22Ο€ (3) f β€²β€²(0) = 1 (4) f β€²β€²(0) = 0

202406 Apr Shift 1Differentiation
MathsHard

Q73.If the function f(x) = ( x1 ) 2x; x > 0 attains the maximum value at x = 1e then : (1) eΟ€ < Ο€e (2) eΟ€ > Ο€e (3) (2e)Ο€ > Ο€(2e) (4) e2Ο€ < (2Ο€)e 1

202406 Apr Shift 2Applications of Derivatives
MathsMedium

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