Practice Questions
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Q72.Consider the function f : [ 12 , 1] βR defined by f(x) = 4β2x3 β3β2x β1. Consider the statements (I) The curve y = f(x) intersects the x-axis exactly at one point (II) The curve y = f(x) intersects the x-axis at x = cos 12Ο Then (1) Only (II) is correct (2) Both (I) and (II) are incorrect (3) Only (I) is correct (4) Both (I) and (II) are correct
Q72.The function f: R->R, f(x) = x2+2xβ15 , x βR is x2β4x+9 (1) one-one but not onto. (2) both one-one and onto. (3) onto but not one-one. (4) neither one-one nor onto. JEE Main 2024 (06 Apr Shift 1) JEE Main Previous Year Paper 1 ), x β 0 x then
Q72.Suppose for a differentiable function h, h(0) = 0, h(1) = 1 and hβ²(0) = hβ²(1) = 2. If g(x) = h (ex)eh(x) , then gβ²(0) is equal to: (1) 5 (2) 4 (3) 8 (4) 3
Q72.If ππ₯= 4π₯+ 3 , π₯β 2 and ( πππ) ( π₯) = π( π₯) , where π: π - 2 βπ - 2 then ( πππππ) ( 4 ) is equal to 6π₯- 4 3 3 3, 19 19 (1) - (2) 20 20 (3) -4 (4) 4 Q73. ππ₯, π₯β€0 Let ππ₯ be a linear function and ππ₯= 1 , is continuous at π₯= 0. If π'1 = πβ1, then the value of 1 + π₯ π₯, π₯> 0 2 + π₯ π3 is JEE Main 2024 (31 Jan Shift 1) JEE Main Previous Year Paper 1 4 1 4 (1) 3logπ 1 (2) 3logπ 9 + 1 9π 3 4 4 (3) logπ 9 β1 (4) logπ 1 9π 3 π₯π¦π₯- 1π₯- 2
Q72.A variable line L passes through the point (3, 5) and intersects the positive coordinate axes at the points A and B. The minimum area of the triangle OAB, where O is the origin, is : (1) 30 (2) 25 (3) 40 (4) 35
Q72.Let the sum of the maximum and the minimum values of the function f(x) = 2x2+3x+82x2β3x+8 be mn , where gcd(m, n) = 1. Then m + n is equal to : (1) 195 (2) 201 (3) 217 (4) 182 2x , x < 0
Q72.Given that the inverse trigonometric function assumes principal values only. Let x, y be any two real numbers in [β1, 1] such that cosβ1 x βsinβ1 y = Ξ±, βΟ2 β€Ξ± β€Ο. Then, the minimum value of x2 + y2 + 2xy sin Ξ± is (1) 0 (2) -1 (3) 1 2 (4) β12 72xβ9xβ8x+1
Q72.Let π: π βπ and π: π βπ be defined as ππ₯= logππ₯, π₯> 0 and ππ₯= π₯, π₯β₯0 . Then, πππ: π βπ is: πβπ₯, π₯β€0 ππ₯, π₯< 0 (1) one-one but not onto (2) neither one-one nor onto (3) onto but not one-one (4) both one-one and onto
Q72.If the domain of the function f(x) = cosβ1( 2β|x|4 ) equal to : (1) 12 (2) 9 (3) 11 (4) 8
Q72.Let f : [β1, 2] βR be given by f(x) = 2x2 + x + [x2] β[x], where [t] denotes the greatest integer less than or equal to t. The number of points, where f is not continuous, is : (1) 5 (2) 6 (3) 3 (4) 4
Q72.Let y = loge( 1βx21+x2 ), (1) 732 (2) 746 (3) 742 (4) 736
Q73.Let β«2βtan3+tan xx dx = 12 (Ξ±x + loge |Ξ² sin x + Ξ³ cos x|) + C , where C is the constant of integration. Then Ξ± + Ξ²Ξ³ is equal to : (1) 7 (2) 4 (3) 1 (4) 3
Q73.The function f(x) = 2x + 3x 23 , x βR, has (1) exactly one point of local minima and no point of (2) exactly one point of local maxima and no point local maxima of local minima (3) exactly one point of local maxima and exactly (4) exactly two points of local maxima and exactly one point of local minima one point of local minima
Q73.If the function f(x) = 2x3 β9x2 + 12a2x + 1, a > 0 has a local maximum at x = Ξ± and a local minimum at x = Ξ±2 , then Ξ± and Ξ±2 are the roots of the equation : JEE Main 2024 (08 Apr Shift 2) JEE Main Previous Year Paper (1) x2 β6x + 8 = 0 (2) x2 + 6x + 8 = 0 (3) 8x2 + 6x β1 = 0 (4) 8x2 β6x + 1 = 0 = Ο6 . Then eΞ± and eβΞ± are the roots of the equation :
Q73. x2 β§ 1βcos where Ξ±, Ξ² βR. If f is continuous at Let f : R βR be a function given by f(x) = β¨ Ξ±, x = 0, Ξ²β1βcos x β© x , x > 0 x = 0, then Ξ±2 + Ξ²2 is equal to : (1) 3 (2) 12 (3) 48 (4) 6 JEE Main 2024 (04 Apr Shift 1) JEE Main Previous Year Paper
Q73.If the function π: ββ, β1 βπ, π defined by ππ₯= ππ₯3 β3π₯+ 1 is one-one and onto, then the distance of the point π2π+ 4, π+ 2 from the line π₯+ πβ3π¦= 4 is: (1) 2β1 + π6 (2) 4β1 + π6 (3) 3β1 + π6 (4) β1 + π6 JEE Main 2024 (31 Jan Shift 2) JEE Main Previous Year Paper
Q73.Let g : R βR be a non constant twice differentiable such that gβ²( 21 ) = gβ²( 23 ). If a real valued function f is defined as f(x) = 12 [ g(x) + g(2 βx)], then (1) f β²β²(x) = 0 for atleast two x in (0, 2) (2) f β²β²(x) = 0 for exactly one x in (0, 1) (3) f β²β²(x) = 0 for no x in (0, 1) (4) f β²( 23 ) + f β²( 21 ) = 1
Q73.Let π: π - {0} βπ be a function satisfying π π₯ π( π₯) for all π₯, π¦, π( π¦) β 0. If π' (1) = 2024, then π¦= π( π¦) (1) π₯π'π₯- 2024ππ₯= 0 (2) π₯π'π₯+ 2024ππ₯= 0 (3) π₯' (π₯) + π(π₯) = 2024 (4) π₯π' (π₯) - 2023π(π₯) = 0
Q73.If the function f(x) = , x β 0 β2ββ1+cos x is continuous at x = 0, then the value of a2 is equal to { a loge 2 loge 3 , x = 0 (1) 968 (2) 1152 (3) 746 (4) 1250
Q73.If loge y = 3 sinβ1 x, then (1 βx2)yβ²β² βxyβ² at x = 12 is equal to (1) 3eΟ/6 (2) 9eΟ/2 (3) 3eΟ/2 (4) 9eΟ/6 y β₯0, y(0) = 0. Then at x = 2, yβ²β² + y + 1 is equal to
Q73.Let π: π βπ be defined as πβπcos2π₯ ; π₯< 0 π₯2 ππ₯= π₯2 + ππ₯+ 2; 0 β€π₯β€1 2π₯+ 1; π₯> 1 If π is continuous everywhere in π and π is the number of points where π is NOT differential then π + π + π + π equals: JEE Main 2024 (01 Feb Shift 1) JEE Main Previous Year Paper (1) 1 (2) 4 (3) 3 (4) 2 1
Q73.The function f : N β{1} βN; defined by f(n) = the highest prime factor of n, is : (1) both one-one and onto (2) one-one only (3) onto only (4) neither one-one nor onto JEE Main 2024 (27 Jan Shift 1) JEE Main Previous Year Paper Q74. , x < 3 β§ a(7xβ12βx2)b|x2β7x+12| Consider the function f(x) = sin(xβ3) ,where [x] denotes the greatest integer less than or equal xβ[x] β¨ 2 , x > 3 β© b , x = 3 to x . If S denotes the set of all ordered pairs (a, b) such that f(x) is continuous at x = 3, then the number of elements in S is : (1) 2 (2) Infinitely many (3) 4 (4) 1 dx = a + bβ2 + cβ3, where a, b, c are rational numbers, then 2a + 3 b β4c is equal to :
Q73.If y(ΞΈ) = cos 3ΞΈ+42 coscosΞΈ+cos2ΞΈ+52ΞΈcos ΞΈ+2 , then at ΞΈ = Ο2 , yβ²β² + yβ² + y is equal to : (1) 21 (2) 1 (3) 2 (4) 32 20
Q73.If f(x) = {x30 sin, x (= 0 (1) f β²β² ( Ο2 ) = 24βΟ22Ο (2) f β²β² ( Ο2 ) = 12βΟ22Ο (3) f β²β²(0) = 1 (4) f β²β²(0) = 0
Q73.If the function f(x) = ( x1 ) 2x; x > 0 attains the maximum value at x = 1e then : (1) eΟ < Οe (2) eΟ > Οe (3) (2e)Ο > Ο(2e) (4) e2Ο < (2Ο)e 1