Practice Questions
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Q65.If 20C1 + (22) 20C2 + (32) 20C3+. . . . . +(202) 20C20 = A(2Ξ²), then the ordered pair (A, Ξ²) is equal to JEE Main 2019 (12 Apr Shift 2) JEE Main Previous Year Paper (1) (380, 19) (2) (420, 18) (3) (420, 19) (4) (380, 18) β 3 ) 6 is equal to x2
Q65.If sin4Ξ± + 4cos4Ξ² + 2 = 4β2sinΞ±cosΞ², Ξ±, Ξ² β[0, Ο] , then cos(Ξ± + Ξ²) βcos(Ξ± βΞ²) is equal to (1) β1 (2) ββ2 (3) β2 (4) 0 JEE Main 2019 (12 Jan Shift 2) JEE Main Previous Year Paper
Q65.The sum of the following series 1 + 6 + 9(12+22+32)7 + 12(12+22+32+42)9 + 15(12+22+β¦+52)11 +. . . . is: (1) 7520 (2) 7510 (3) 7830 (4) 7820
Q65.The sum β π is equal to π= 1 2π 11 21 (1) 1 β (2) 2 β 220 220 3 11 (3) 2 β (4) 2 β 217 219 6 Q66. 1 1 If the fourth term in the binomial expansion of βπ₯ 1 + log10π₯+ π₯ 12 is equal to 200, and π₯> 1, then the value of π₯ is (1) 100 (2) 104 (3) 103 (4) 10
Q67.All the pairs (x, y), that satisfy the inequality 2βsin2xβ2sinx+5 β 1 β€1 also satisfy the equation: 4sin2y (1) 2 sin x = sin y (2) sin x = 2 sin y (3) |sin x| = |sin y| (4) 2|sin x| = 3 sin y
Q69.The locus of the centres of the circles, which touch the circle, π₯2 + π¦2 = 1 externally, also touch the π¦-axis and lie in the first quadrant, is: (1) π¦= β1 + 2π₯, π₯β₯0 (2) π¦= β1 + 4π₯, π₯β₯0 (3) π₯= β1 + 2π¦, π¦β₯0 (4) π₯= β1 + 4π¦, π¦β₯0
Q69.If a tangent to the circle x2 + y2 = 1 intersects the coordinate axes at distinct points P and Q, then the locus of the mid-point of PQ is: (1) x2 + y2β16x2y2 = 0 (2) x2 + y2β4x2y2 = 0 (3) x2 + y2β2xy = 0 (4) x2 + y2β2x2y2 = 0
Q69.If a circle of radius R passes through the origin O and intersects the coordinate axes at A and B, then the locus of the foot of perpendicular from O on AB is : (1) (x2 + y2)(x + y) = R2xy (2) (x2 + y2)3 = 4R2x2y2 (3) (x2 + y2) 2 = 4R2x2y2 (4) (x2 + y2) 2 = 4Rx2y2
Q70.Let the equations of two sides of a triangle be 3x β2y + 6 = 0 and 4x + 5y β20 = 0. If the orthocenter of this triangle is at (1, 1) then the equation of it's third side is: (1) 122y + 26x + 1675 = 0 (2) 26x β122y β1675 = 0 (3) 26x + 61y + 1675 = 0 (4) 122y β26x β1675 = 0
Q70.If the normal to the ellipse 3π₯2 + 4π¦2 = 12 at a point π on it is parallel to the line, 2π₯+ π¦= 4 and the tangent to the ellipse at π passes through π( 4,4 ) then ππ is equal to: (1) β61 (2) 5β5 2 2 (3) β157 (4) β221 2 2
Q70.Let S = {(x, 1}, where (1) An ellipse whose eccentricity is 1 , when (2) A hyperbola whose eccentricity is 2 , when βr+1 βr+1 r > 1. 0 < r < 1. (3) (4) A hyperbola whose eccentricity is 2 , when An ellipse whose eccentricity is , when β1βr β r+12 r > 1 0 < r < 1
Q70.If the line ππ₯+ π¦= π, touches both the curves π₯2 + π¦2 = 1 and π¦2 = 4β2π₯, then π is equal to: 1 (1) (2) β2 2 (3) 1 (4) 2 β2
Q70.Let π0,0 and π΄0,1 be two fixed points. Then, the locus of a point π such that the perimeter of π₯π΄ππ is 4 is (1) 8π₯2 + 9π¦2 - 9π¦= 18 (2) 9π₯2 - 8π¦2 + 8π¦= 16 (3) 8π₯2 - 9π¦2 + 9π¦= 18 (4) 9π₯2 + 8π¦2 - 8π¦= 16
Q71.If the parabolas y2 = 4b(x βc) and y2 = 8ax have a common normal, then which one of the following is a valid choice for the ordered triad (a, b, c) (1) (1, 1, 3) (2) ( 12 , 2, 0) (3) ( 12 , 2, 3) (4) All of above
Q71.If a variable line 3x + 4y βΞ» = 0 is such that the two circles x2 + y2 β2x β2y + 1 = 0 and x2 + y2 β18x β2y + 78 = 0 are on its opposite sides, then the set of all values of Ξ» is the interval : (1) [13, 23] (2) (23, 31) (3) [12, 21] (4) (2, 17)
Q71.Let π be the point of intersection of the common tangents to the parabola π¦2 = 12π₯ and the hyperbola 8π₯2 - π¦2 = 8. If π and π' denote the foci of the hyperbola where π lies on the positive π₯-axis then π divides ππ' in a ratio: (1) 5: 4 (2) 2: 1 (3) 13: 11 (4) 14: 13
Q71.The area (in sq. units) of the smaller of the two circles that touch the parabola, y2 = 4x at the point (1, 2) and the x -axis is (1) 8Ο(3 β2β2) (2) 8Ο(2 ββ2) + (3) 4Ο(3 β2) (4) 4Ο(2 ββ2)
Q72.Let A(4, β4) and B(9, 6) be points on the parabola, y2 = 4x. Let C be chosen on the arc AOB of the parabola, where O is the origin, such that the area of ΞACB is maximum. Then, the area (in sq. units) of ΞACB , is: (1) 32 (2) 31 34 (3) 30 12 (4) 31 14
Q72.Let P(4, β4) and Q(9, 6) be two points on the parabola, y2 = 4x and let X be any point on the arc POQ of this parabola, where O is the vertex of this parabola, such that the area of ΞPXQ is maximum. Then this maximum area (in sq. units) is : (1) 625 (2) 75 4 2 (3) 125 (4) 125 4 2
Q72.If tangents are drawn to the ellipse x2 + 2y2 = 2 at all points on the ellipse other than its four vertices then the mid points of the tangents intercepted between the coordinate axes lie on the curve : y2 (1) 1 + 1 = 1 (2) x2 4x2 2y2 4 + 2 = 1 y2 (3) 1 + 1 = 1 (4) x2 2x2 4y2 2 + 4 = 1
Q73.The equation of a common tangent to the curves, y2 = 16x and xy = β4, is: (1) x β2y + 16 = 0 (2) x βy + 4 = 0 (3) 2x βy + 2 = 0 (4) x + y + 4 = 0 JEE Main 2019 (12 Apr Shift 2) JEE Main Previous Year Paper
Q74.Let [x] denote the greatest integer less than or equal to X . Then : limxβ0 tan(Ο sin2 x)+(|x|βsin(x[x]))2x2 (1) does not exist (2) equals Ο (3) equals Ο + 1 (4) equals 0
Q75. ABC is a triangular park with AB = AC = 100 metres. A vertical tower is situated at the mid-point of BC. If the angles of elevation of the top of the tower at, A and B are cotβ1(3β2) and cosecβ1(2β2) respectively, then the height of the tower (in metres) is (1) 100 (2) 20 3β3 (3) 25 (4) 10β5
Q75. y + 1 Ξ± Ξ² Let Ξ± and Ξ² be the roots of the equation x2 + x + 1 = 0. Then for y β 0 in R, Ξ± y + Ξ² 1 is equal Ξ² 1 y + Ξ± to (1) y3 (2) y(y2β1) (3) y3β1 (4) y(y2β3)
Q75.Let π΄= cosπΌ-sinπΌ πβπ such that π΄32 = 0 -1 . Then, a value of πΌ is: sinπΌ cosπΌ, 1 0 (1) 0 (2) π (3) π (4) π 16 64 32 JEE Main 2019 (08 Apr Shift 1) JEE Main Previous Year Paper