Practice Questions

Q46.Consider the following reaction sequence ​ The product ' B ' is JEE Main 2022 (29 Jul Shift 1) JEE Main Previous Year Paper (1) (2) (3) (4)

Q46. Consider the above reaction sequence and identify the product B. (1) (2) (3) (4)

Q46.Given below are two statements : Statement I: The esterification of carboxylic acid with an alcohol is a nucleophilic acyl substitution. Statement II: Electron withdrawing groups in the carboxylic acid will increase the rate of esterification reaction. Choose the most appropriate option (1) Statement I is correct but Statement II is (2) Both Statement I and Statement II are incorrect. incorrect. (3) Both Statement I and Statement II are correct. (4) Statement I is incorrect but Statement II is correct.

Q46.Decarboxylation of all six possible forms of diaminobenzoic acids C6H3(NH2)2 COOH yields three products A, B and C . Three acids give a product ' A ', two acids gives a product ' B ' and one acid give a product ' C '. The melting point of product ' C ' is (1) 63 °C (2) 90 °C (3) 104 °C (4) 142 °C

Q46.What is the major product of the following reaction? (1) (2) (3) (4)

Q46.In Friedel-Crafts alkylation of aniline, one gets: (1) alkylated product with ortho and (2) secondary amine after acidic treatment. para substitution. (3) an amide product. (4) positively charged nitrogen at benzene ring.

Q46. Consider the above reaction and predict the major product. (1) (2) (3) (4)

Q46.Two statements are given belwo : Statement I : The melting point of monocarboxylic acid with even number of carbon atoms is higher than that of with odd number of carbon atoms acid immediately below and above it in the series. Statement II : The solubility of monocarboxylic acids in water decreases with increase in molar mass. Choose the most appropriate option : (1) Both Statement I and Statement II are correct. (2) Both Statement I and Statement II are incorrect. (3) Statement I is correct but Statement II is (4) Statement I is incorrect but Statement II is incorrect. correct.

Q46.The correct structure of product ' A ' formed in the following reaction, JEE Main 2022 (28 Jun Shift 1) JEE Main Previous Year Paper (1) (2) (3) (4)

Q46.The difference in the reaction of phenol with bromine in chloroform and bromine in water medium is due to (1) Hyperconjugation in substrate (2) Polarity of solvent (3) Free radical formation (4) Electromeric effect of the substrate

Q46. In the above reaction product B is JEE Main 2022 (27 Jul Shift 1) JEE Main Previous Year Paper (1) (2) (3) (4)

Q46.Hex- 4 -ene- 2 -ol on treatment with PCC gives ' A '. ' A ' on reaction with sodium hypoiodite gives ' B ', which on further heating with soda lime gives ' C '. The compound ' C ' is (1) 2 -pentene (2) proponaldehyde (3) 2 -butene (4) 4 -methylpent- 2 -ene

Q46. Find out the major product for the above reaction. JEE Main 2022 (28 Jul Shift 2) JEE Main Previous Year Paper (1) (2) (3) (4)

Q46.Which statement is NOT correct for p-toluenesulphonyl chloride? (1) It is hinsberg's reagent (2) It is used to distinguish primary and secondary amines. (3) On treatment with secondary amine, it leads to a (4) It does not react with tertiary amine. product, that is soluble in alkali. JEE Main 2022 (26 Jun Shift 2) JEE Main Previous Year Paper

Q46.The intermediate X, in the reaction (1) (2) (3) (4)

Q47.Identify the major product A and B for the below given reaction sequence. JEE Main 2022 (28 Jul Shift 1) JEE Main Previous Year Paper ​ (1) (2) (3) (4)

Q47.During halogen test, sodium fusion extract is boiled with concentrated HNO3 to (1) remove unreacted sodium (2) decompose cyanide or sulphide of sodium (3) extract halogen from organic compound (4) maintain the pH of extract.

Q47. CH3 MgBr H3O+ Zn−Hg−−−CH3 −CH2 −CN → A → B → C. The correct structure of C is Ether HCl JEE Main 2022 (25 Jul Shift 2) JEE Main Previous Year Paper (1) (2) (3) (4) CH3 −CH2 −CH = CH2

Q47.Match List-I with List-II List-I List-II A Benzenesulphonyl chloride I Test for primary amines B Hoffmann bromamide reaction II Anti Saytzeff C Carbylamine reaction III Hinsberg reagent D Hoffmann orientation IV Known reaction of Isocyanates. Choose the correct answer from the options given below (1) A −IV, B −III, C −II, D −I (2) A −IV, B −II, C −I, D −III (3) A −III, B −IV, C −I, D −II (4) A −IV, B −III, C −I, D −II

Q47.An organic compound ' A ' contains nitrogen and chlorine. It dissolves readily in water to give a solution that turns litmus red. Titration of compound ' A ' with standard base indicates that the molecular weight of ' A ' is 131 ± 2 . When a sample of ' A ' is treated with aq. NaOH, a liquid separates which contains N but not Cl. Treatment of the obtained liquid with nitrous acid followed by phenol gives orange precipitate. The compound ' A ' is (1) (2) (3) (4)

Q47.Hydrolysis of which compound will give carbolic acid? (1) Cumene (2) Benzenediazonium chloride (3) Benzal chloride (4) Ethylene glycol ketal

Q47.Given below are two statements : Statement - I : In Hofmann degradation reaction, the migration of only an alkyl group takes place from carbonyl carbon of the amide to the nitrogen atom. Statement - II : The group is migrated in Hofmann degradation reaction to electron deficient atom. JEE Main 2022 (27 Jun Shift 1) JEE Main Previous Year Paper In the light of the above statements, choose the most appropriate answer from the options given below (1) Both Statement I and Statement II are correct. (2) Both Statement I and Statement II are incorrect. (3) Statement I is correct but Statement II is (4) Statement I is incorrect but Statement II is incorrect. correct.

Q47.When enthanol is heated with conc. H2SO4, a gas is produced. The compound formed, when this gas is treated with cold dilute aqueous solution of Baeyer's reagent, is (1) Formaldehyde (2) Formic acid (3) Glycol (4) Ethanoic acid

Q47.Which among the following is the strongest Bronsted base? (1) (2) (3) (4)

Q47.The conversion of propan- 1 -ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents is (1) (i) SOCl2 (2) (i) HCl (ii) KCN (ii) H2/ Ni, Na(Hg)/C2H5 OH (iii) H2/ Ni, Na(Hg)/C2H5 OH (3) (i) SOCl2 (4) (i) HCl (ii) KCN (ii) CH3 NH2 (iii) CH3 NH2