Practice Questions

Q56.What amount of bromine will be required to convert 2 g of phenol into 2,4,6-tribromophenol? (Given molar mass in gmol−1 of C, H, O, Br are 12, 1, 16, 80 respectively ) (1) 20 .44 g (2) 4.0 g (3) 6.0 g (4) 10.22

Q56.Given below are two statements : Statement I : One mole of propyne reacts with excess of sodium to liberate half a mole of H2 gas. Statement II : Four g of propyne reacts with NaNH2 to liberate NH3 gas which occupies 224 mL at STP. In the light of the above statements, choose the most appropriate answer from the options given below: (1) Statement I is incorrect but Statement II is (2) Both Statement I and Statement II are correct correct (3) Statement I is correct but Statement II is (4) Both Statement I and Statement II are incorrect incorrect 2025 (22 Jan Shift 1) JEE Main Previous Year Paper

Q56.Given below are two statements : Statement (I) : NaCl is added to the ice at 0∘C, present in the ice cream box to prevent the melting of ice cream. Statement (II) : On addition of NaCl to ice at 0∘C, there is a depression in freezing point. In the light of the above statements, choose the correct answer from the options given below : (1) Both Statement I and Statement II are false (2) Statement I is false but Statement II is true (3) Statement I is true but Statement II is false (4) Both Statement I and Statement II are true

Q57.In a multielectron atom, which of the following orbitals described by three quantum numbers will have same energy in absence of electric and magnetic fields? A. n = 1, l = 0, m1 = 0 B. n = 2, l = 0, m1 = 0 C. n = 2, l = 1, m1 = 1 D. n = 3, l = 2, m1 = 1 E. n = 3, l = 2, m1 = 0 Choose the correct answer from the options given below: (1) B and C Only (2) A and B Only (3) C and D Only (4) D and E Only

Q57.Given below are two statements : Statement (I) : For a given shell, the total number of allowed orbitals is given by n2 . Statement (II) : For any subshell, the spatial orientation of the orbitals is given by −l to +l values including zero. In the light of the above statements, choose the correct answer from the options given below : (1) Both Statement I and Statement II are false (2) Statement I is true but Statement II is false (3) Both Statement I and Statement II are true (4) Statement I is false but Statement II is true

Q57.Match List - I with List - II : Choose the correct answer from the options given below : (1) (A)-(III), (B)-(II), (C)-(IV), (D)-(I) (2) (A)-(II), (B)-(III), (C)-(IV), (D)-(I) (3) (A)-(III), (B)-(I), (C)-(IV), (D)-(II) (4) (A)-(IV), (B)-(III), (C)-(II), (D)-(I)

Q57.For bacterial growth in a cell culture, growth law is very similar to the law of radioactive decay. Which of the following graphs is most suitable to represent bacterial colony growth ? Where N - Number of Bacteria at any time, N0 - Initial number of Bacteria. (1) (2) (3) (4)

Q57. Which among the following react with Hinsberg's reagent? Choose the correct answer from the options given below: (1) A, B and E Only (2) A, C and E Only (3) C and D Only (4) B and D Only

Q57.The species which does not undergo disproportionation reaction is : (1) ClO−3 (2) ClO− (3) ClO−2 (4) ClO−4

Q57.Preparation of potassium permanganate from MnO2 involves two step process in which the 1st step is a reaction with KOH and KNO3 to produce (1) K3MnO4 (2) K4 [Mn(OH)6] (3) KMnO4 (4) K2MnO4

Q57.Given below are two statements : Statement ( I): The radii of isoelectronic species increases in the order. Mg2+ < Na+ < F−< O2− Statement (II): The magnitude of electron gain enthalpy of halogen decreases in the order. Cl > F > Br > I In the light of the above statements, choose the most appropriate answer from the options given below : (1) Statement I is incorrect but Statement II is (2) Statement I is correct but Statement II is correct incorrect (3) Both Statement I and Statement II are incorrect (4) Both Statement I and Statement II are correct 2025 (29 Jan Shift 1) JEE Main Previous Year Paper

Q57. E∘Cr2O2−7 /Cr3+ = 1.33 V E∘Cl2/Cl(−) = 1.36 V Based on the data given below : the strongest reducing agent is : E∘ = 1.51 V E∘ = −0.74 V MnO−4 /Mn2+ Cr3+/Cr (1) Cr (2) Cl− (3) MnO−4 (4) Mn2+

Q57. The compounds which give positive Fehling's test are : (A) (B) (C) HOCH2 −CO −(CHOH)3 −CH2 −OH (D) (E) Choose the correct answer from the options given below : (1) (A), (D) and (E) Only (2) (C), (D) and (E) Only (3) (A), (C) and (D) Only (4) (A), (B) and (C) Only

Q58.For a reaction, N2O5( g) →2NO2( g) + 12 O2( g) in a constant volume container, no products were present initially. The final pressure of the system when 50% of reaction gets completed is (1) 5 times of initial pressure (2) 5/2 times of initial pressure (3) 7/2 times of initial pressure (4) 7/4 times of initial pressure

Q58.The molar solubility(s) of zirconium phosphate with molecular formula (Zr4+)3(PO3−4 )4 is given by relation : (1) Ksp 13 (2) Ksp 17 ( 9612 ) ( 6912 ) (3) Ksp 17 (4) Ksp 16 ( 8435 ) ( 5348 )

Q58.The amphoteric oxide among V2O3, V2O4 and V2O5 , upon reaction with alkali leads to formation of an oxide anion. The oxidation state of V in the oxide anion is : (1) +3 (2) +4 (3) +7 (4) +5

Q58.For hydrogen like species, which of the following graphs provides the most appropriate representation of E vs Z plot for a constant n ? [E: Energy of the stationary state, Z : atomic number, n = principal quantum number] (1) (2) (3) (4)

Q58.Which of the following electrolyte can be used to obtain H2 S2O8 by the process of electrolysis? (1) Dilute solution of sodium sulphate. (2) Acidified dilute solution of sodium sulphate. (3) Dilute solution of sulphuric acid (4) Concentrated solution of sulphuric acid

Q58.For the reaction, H2( g) + I2( g) ⇌2HI( g) Attainment of equillibrium is predicted correctly by : 2025 (24 Jan Shift 2) JEE Main Previous Year Paper (1) (2) (3) (4) −−

Q58.Standard electrode potentials for a few half cells are mentioned below : E∘ = 0.34 V, E∘ = −0.76 V Cu2+/Cu Zn2+/Zn Which one of the following cells gives the most negative value of E∘Ag+/Ag = 0.80 V, E∘Mg2+/Mg = −2.37 V ΔG∘ ? (1) Zn Zn2+(1M) Ag+(1M) Ag (2) Zn Zn2+(1M) Mg2+(1M) Mg (3) Ag Ag+(1M) Mg2+(1M) Mg (4) Cu Cu2+(1M)∥Ag+(1M) Ag

Q58.The correct set of ions (aqueous solution) with same colour from the following is: 2025 (23 Jan Shift 1) JEE Main Previous Year Paper (1) Sc3+, Ti3+, Cr2+ (2) V2+, Cr3+, Mn3+ (3) Ti4+, V4+, Mn2+ (4) Zn2+, V3+, Fe3+

Q58. List - I List - II (Carbohydrate) (Linkage Source) (A) Amylose (I) β −C1 −C4, plant Match List - I with List - II. Choose the (B) Cellulose (II) α −C1 −C4, animal (C) Glycogen (III) α −C1 −C4, α −C1 −C6, plant (D) Amylopectin (IV) α −C1 −C4, plant correct answer from the options given below : (1) (A)-(IV), (B)-(I), (C)-(III), (D)-(II) (2) (A)-(III), (B)-(II), (C)-(I), (D)-(IV) (3) (A)-(II), (B)-(III), (C)-(I), (D)-(IV) (4) (A)-(IV), (B)-(I), (C)-(II), (D)-(III)

Q58.A weak acid HA has degree of dissociation x . Which option gives the correct expression of ( pH pKa )? (1) 0 (2) log(1 + 2x) (3) log ( 1−xx ) (4) log ( 1−xx )

Q59.The molecules having square pyramidal geometry are (1) BrF5&PCl5 (2) SbF5&PCl5 (3) SbF5&XeOF4 (4) BrF5&XeOF4

Q59.Arrange the following in increasing order of solubility product : Ca(OH)2, AgBr, PbS, HgS (1) HgS < AgBr < PbS < Ca(OH)2 (2) Ca(OH)2 < AgBr < HgS < PbS (3) PbS < HgS < Ca(OH)2 < AgBr (4) HgS < PbS < AgBr < Ca(OH)2