Practice Questions
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Q72.The function ππ₯= π₯3 - 6π₯2 + ππ₯+ π is such that π2 = π4 = 0. Consider two statements: π1 there exists π₯1, π₯2 β2, 4, π₯1 < π₯2, such that π'π₯1 = - 1 and π'π₯2 = 0 . π2 there exists π₯3, π₯4 β2, 4, π₯3 < π₯4, such that π is decreasing in 2, π₯4, increasing in π₯4, 4 and 2π'π₯3 = β3ππ₯4 then (1) π1 is true and π2 is false (2) both π1 and π2 are false (3) both π1 and π2 are true (4) π1 is false and π2 is true JEE Main 2021 (01 Sep Shift 2) JEE Main Previous Year Paper Q73. π sec2π₯π(π₯)dπ₯ 4 β«2 Let f : R βR be a continuous function. Then lim π2 is equal to: π₯βπ/ 4 π₯2 - 16 (1) π( 2 ) (2) 2π( β2 ) (3) 2π( 2 ) (4) 4π( 2 )
Q72.If lim sinβ1 xβtanβ1 x is equal to L, then the value of (6L + 1) is xβ0 3x3 (1) 1 (2) 1 6 2 (3) 6 (4) 2 JEE Main 2021 (18 Mar Shift 1) JEE Main Previous Year Paper Q73. 1 2 0 2 β1 5 Let A + 2B = β‘ 6 β3 3β€ and 2A βB = β‘2 β1 6β€ . If Tr(A) denotes the sum of all diagonal elements β5 3 1 0 1 2 β£ β¦ β£ β¦ of the matrix A, then Tr (A)βTr (B) has value equal to (1) 1 (2) 2 (3) 0 (4) 3
Q72. x3 1+2xeβ2x , x β 0 (1βcos 2x)2 loge( (1βxeβx)2 ) Let f : R βR be defined as f(x) = { Ξ± , x = 0 If f is continuous at x = 0, then Ξ± is equal to: (1) 1 (2) 3 (3) 0 (4) 2
Q72.The domain of the function, ππ₯= sin-13π₯2 + cos-1 2 ( π₯- 1 π₯+ 1 ) 1 1 (1) 0, (2) 0, 2 4 (3) 1 1 βͺ0 (4) -2, 0 βͺ1 1 4, 2 4, 2
Q72.Let A and B be two 3 Γ 3 real matrices such that (A2 βB2) is invertible matrix. If A5 = B5 and A3 B2 = A2 B3, then the value of the determinant of the matrix A3 + B3 is equal to : (1) 2 (2) 4 (3) 1 (4) 0
Q72.The system of equations kx + y + z = 1, x + ky + z = k and x + y + zk = k2 has no solution if k is equal to: (1) 0 (2) 1 (3) β1 (4) β2
Q72.The triangle of maximum area that can be inscribed in a given circle of radius ' r' is : (1) An equilateral triangle having each of its side of (2) An isosceles triangle with base equal to 2r. length β3r. (3) An equilateral triangle of height 2r . (4) A right angle triangle having two of its sides of 3 length 2r and r. dt, then f(e) + f( 1e ) is equal to
Q72.Let the system of linear equations 4x + Ξ»y + 2z = 0 2x βy + z = 0 ΞΌx + 2y + 3z = 0, Ξ», ΞΌ βR has a non-trivial solution. Then which of the following is true? JEE Main 2021 (18 Mar Shift 2) JEE Main Previous Year Paper (1) ΞΌ = 6, Ξ» βR (2) Ξ» = 2, ΞΌ βR (3) Ξ» = 3, ΞΌ βR (4) ΞΌ = β6, Ξ» βR
Q72.If P = [ ], 2 1 (1) [125 10 ] (2) [10 501 ] (3) [10 251 ] (4) [150 10 ] is equal to:
Q72.The number of solutions of the equation sinβ1[x2 + 13 ] + cosβ1[x2 β23 ] = x2 for x β[β1, 1], and [x] denotes the greatest integer less than or equal to x, is : (1) 2 (2) 0 (3) 4 (4) Infinite . Then f is:
Q72.A box open from top is made from a rectangular sheet of dimension a Γ b by cutting squares each of side x from each of the four corners and folding up the flaps. If the volume of the box is maximum, then x is equal to: (1) a+b+βa2+b2βab (2) a+bββa2+b2βab 6 12 (3) a+bββa2+b2βab (4) a+bββa2+b2+ab 6 6
Q72.Let A = [β11 24 ]. If Aβ1 = Ξ±I + Ξ²A, Ξ±, Ξ² βR, I is a 2 Γ 2 identity matrix, then 4(Ξ± βΞ²) is equal to : (1) 5 (2) 83 (3) 2 (4) 4 (1 + |sin x|) |sin x| , βΟ4 < x < 0Q73. β§ 3a b , x = 0 Let f : (βΟ4 , Ο4 ) βR be defined as, f(x) = β¨ β© ecot 4x/ cot 2x , 0 < x < Ο4 If f is continuous at x = 0 then the value of 6a + b2 is equal to: (1) 1 βe (2) e β1 (3) 1 + e (4) e
Q72.The function ππ₯= 4π₯3 - 3π₯2 - 2sinπ₯+ 2π₯- 1cosπ₯: 6 1 1 (1) increases in 2, β (2) decreases in - β, 2 1 1 (3) decreases in 2, β (4) increases in - β, 2
Q72.The sum of all the local minimum values of the twice differentiable function f : R βR defined by β²β²(2) x + f β²β²(1) is: f(x) = x3 β3x2 β3f 2 (1) β22 (2) 5 (3) β27 (4) 0
Q72. sin x βex if x β€0 β§ Let a function f : R βR be defined as, f(x) = a + [βx] if 0 < x < 1 β¨ β© 2x βb if x β₯1 JEE Main 2021 (20 Jul Shift 1) JEE Main Previous Year Paper Where [x] is the greatest integer less than or equal to x. If f is continuous on R, then (a + b) is equal to: (1) 4 (2) 3 (3) 2 (4) 5 Q73. β§ 1 , if i = j Let A = [aij] be a 3 Γ 3 matrix, where aij = βx , if |i βj| = 1 β¨ β©2x + 1 , otherwise Let a function f : R βR be defined as f(x) =det (A). Then the sum of maximum and minimum values of f on R is equal to: (1) β2027 (2) 2788 (3) 27 20 (4) β8827
Q72.Let f, g : N βN such that f(n + 1) = f(n) + f(1) β n βN and g be any arbitrary function. Which of the following statements is NOT true? (1) If f is onto, then f(n) = nβn βN (2) If g is onto, then fog is one-one (3) f is one-one (4) If fog is one-one, then g is one-one
Q72.Let f be a real valued function, defined on R β{β1, 1} and given by f(x) = 3 loge x+1xβ1 β xβ12 . Then in which of the following intervals, function f(x) is increasing? (1) (ββ, β1) βͺ([ 21 , β) β{1}) (2) (ββ, β) β{β1, 1} (3) (β1, 12 ] (4) (ββ, 21 ] β{β1} dx where [x] denotes the greatest integer less than or equal to x. Then the
Q72.If (sinβ1 x)2 β(cosβ1 x)2 = a; 0 < x < 1, a β 0, then the value of 2x2 β1 is (1) cos( 2aΟ ) (2) sin( 2aΟ ) (3) cos( 4aΟ ) (4) sin( 4aΟ )
Q73.If cotβ1(Ξ±) = cotβ1 2 + cotβ1 8 + cotβ1 18 + cotβ1 32 + β¦ . upto 100 terms, then Ξ± is: JEE Main 2021 (17 Mar Shift 1) JEE Main Previous Year Paper (1) 1. 01 (2) 1. 00 (3) 1. 02 (4) 1. 03
Q73.If Rolle's theorem holds for the function f(x) = x3 βax2 + bx β4, x β[1, 2] with f β²( 43 ) = 0 , then ordered pair (a, b) is equal to : (1) (β5, β8) (2) (β5, 8) (3) (5, 8) (4) (5, β8) dΞΈ is (where c is a constant of integration)
Q73.For x > 0 , if f(x) = β«x1 (1+t)loge t (1) 0 (2) 21 (3) β1 (4) 1 x βR. Then f(x) equals :
Q73.If [x] denotes the greatest integer less than or equal to x, then the value of the integral β«Ο/2βΟ/2[[x] βsin x]dx is equal to: (1) βΟ (2) Ο (3) 0 (4) 1
Q73.If the tangent to the curve π¦= π₯3 at the point ππ‘, π‘3 meets the curve again at π, then the ordinate of the point which divides ππ internally in the ratio 1: 2 is: (1) 0 (2) -2π‘3 (3) -π‘3 (4) 2π‘3
Q73.Consider the integral I = β«100 [x]e[x]exβ1 value of I is equal to : (1) 9(e β1) (2) 45(e + 1) (3) 45(e β1) (4) 9(e + 1)
Q73.Let M and m respectively be the maximum and minimum values of the function f(x) = tanβ1(sin x + cos x) in [0, Ο2 ]. Then the value of tan(M βm) is equal to: (1) 2 ββ3 (2) 3 β2β2 (3) 3 + 2β2 (4) 2 + β3