Practice Questions
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Q73.Consider the function f : R βR defined by f(x) = { (2 βsin(0, x1 )) x , xx =β 00 (1) monotonic on (ββ, 0) βͺ(0, β) (2) not monotonic on (ββ, 0) and (0, β) (3) monotonic on (0, β) only (4) monotonic on (ββ, 0) only
Q73.Let f : R βR be defined as f(x) = { β43 x3 +3xex2x2 + 3x,, xx >β€00 . Then f is increasing function in the interval (1) (β12 , 2) (2) (0, 2) (3) (β1, 23 ) (4) (β3, β1) , Ξ± βR where [x] is the greatest integer less than or equal to x, then the value of
Q73.Let f : R β{3} βR β{1} be defined by f(x) = xβ3xβ2 . Let g : R βR be given as g(x) = 2x β3 . Then, the sum of all the values of x for which f β1(x) + gβ1(x) = 132 is equal to (1) 7 (2) 2 (3) 5 (4) 3
Q73.Let the functions f : R βR and g : R βR be defined as : + 2, x < 0 x < 1 f(x) = and g(x) = {xx2, x β₯0 {x3,3x β2, x β₯1 Then, the number of points in R where (fog)(x) is NOT differentiable is equal to : (1) 3 (2) 1 (3) 0 (4) 2
Q73.If [x] be the greatest integer less than or equal to x, then 100β [ (β1)nn2 ] n=8 (1) 0 (2) 4 (3) β2 (4) 2
Q73.Let f : R βR be defined as f(x + y) + f(x βy) = 2f(x)f(y), f( 21 ) = β1. Then the value of β20k=1 sin(k) sin(k+f(k))1 is equal to : (1) cosec2 (21) cos(20) cos(2) (2) sec2(1) sec(21) cos(20) (3) cosec2 (1) cosec (21) sin(20) (4) sec2(21) sin(20) sin(2) . Then which of
Q73.An angle of intersection of the curves, π₯2 + π¦2 = 1 and π₯2 + π¦2 = ππ, π> π, is : π2 π2 (1) tan-12βππ (2) tan-1π+ π βππ (3) tan-1π- π (4) tan-1 π- π βππ 2βππ
Q73.A wire of length 20 m is to be cut into two pieces. One of the pieces is to be made into a square and the other into a regular hexagon. Then the length of the side (in meters) of the hexagon, so that the combined area of the square and the hexagon is minimum, is (1) 10 (2) 5 2+3β3 3+β3 (3) 10 (4) 5 3+2β3 2+β3 + β¦ + n2
Q73.Let ππ₯= 3sin4π₯+ 10sin3π₯+ 6sin2π₯- 3, π₯β- 6, 2. Then, π is : (1) increasing in -π π (2) decreasing in 0, π 6, 2 2 π π (3) increasing in - 6, 0 (4) decreasing in - 6, 0
Q73.Let x denote the total number of one-one functions from a set A with 3 elements to a set B with 5 elements and y denote the total number of one-one functions from the set A to the set A Γ B. Then : JEE Main 2021 (25 Feb Shift 2) JEE Main Previous Year Paper (1) y = 273x (2) 2y = 273x (3) 2y = 91x (4) y = 91x
Q73.Let ΞΈ β(0, Ο2 ). If the system of linear equations (1 + cos2 ΞΈ)x + sin2 ΞΈy + 4 sin 3ΞΈz = 0 cos2 ΞΈx + (1 + sin2 ΞΈ)y + 4 sin 3ΞΈz = 0 cos2 ΞΈx + sin2 ΞΈy + (1 + 4 sin 3ΞΈ)z = 0 has a non-trivial solution, then the value of ΞΈ is: (1) 4Ο (2) 5Ο 9 18 (3) 7Ο (4) Ο 18 18 = tanβ1 0 < x < 1. Then: x
Q73.Let [t] denote the greatest integer less than or equal to t. Let f(x) = x β[x], g(x) = 1 βx + [x], and h(x) = min{f(x), g(x)}, x β[β2, 2]. Then h is : (1) continuous in [β2, 2] but not differentiable at (2) Continous in [β2, 2] but not differentiable at more than four points in (β2, 2) exactly three poionts in (β2, 2) (3) not continuous at exactly four points in [β2, 2] (4) not continuous at exactly three points in [β2, 2] is
Q73.The value of the integral, β«31 [x2 β2x β2]dx, where [x] denotes the greatest integer less than or equal to x, is (1) β4 (2) β5 (3) ββ2 ββ3 + 1 (4) ββ2 ββ3 β1
Q73.The maximum slope of the curve y = 21 x4 β5x3 + 18x2 β19x occurs at the point (1) (3, 212 ) (2) (2, 2) (3) (2, 9) (4) (0, 0)
Q73.The function f(x) = x2 β2x β3 β e9x2β12x+4 is not differentiable at exactly : (1) Four points (2) Two points (3) three points (4) one point 1 1+ xaQ74. , x < 0 β§ x loge( 1βxb ) If the function f(x) = k , x = 0 β¨ cos2 xβsin2 xβ1 , x > 0 β© βx2+1β1 is continuous at x = 0, then a1 + 1b + k4 is equal to : (1) 4 (2) 5 (3) β4 (4) β5
Q74.The value of the integral β«10 (1+x)(1+3x)(3+x)βxdx is: (1) Ο 4 (1 ββ32 ) (2) Ο8 (1 ββ36 ) (3) Ο 8 (1 ββ32 ) (4) Ο4 (1 ββ36 )
Q74.Let f(x) = β«x0 etf(t)dt + ex be a differentiable function for all (1) e(exβ1) (2) eex β1 (3) 2eex β1 (4) 2e(exβ1) β1
Q74.Let Ξ±, Ξ², Ξ³ be the real roots of the equation, x3 + ax2 + bx + c = 0, ( a, b, c βR and a, b β 0). If the system of equations (in, u, v, w) given by Ξ±u + Ξ²v + Ξ³w = 0, Ξ²u + Ξ³v + Ξ±w = 0, Ξ³u + Ξ±v + Ξ²w = 0 has non-trivial solution, then the value of a2 is b (1) 5 (2) 3 (3) 1 (4) 0
Q74.Consider function f : A βB and g : B βC(A, B, C βR) such that (gof)β1 exists, then: (1) f and g both are one-one (2) f and g both are onto (3) f is one-one and g is onto (4) f is onto and g is one-one JEE Main 2021 (25 Jul Shift 2) JEE Main Previous Year Paper β«x0 (5 + |1 βt|)dt, , then
Q74.Let f : [0, β) β[0, 3] be a function defined by f(x) = {max{sin2 + cos x,t :x0>β€tΟ β€Ο}, x β[0, Ο] the following is true ? (1) f is continuous everywhere but not differentiable (2) f is differentiable everywhere in (0, β) exactly at one point in (0, β) (3) f is not continuous exactly at two points in (4) f is continuous everywhere but not differentiable (0, β) exactly at two points in (0, β)
Q74.Let 1 / 2 π₯π βπ> π and π, πβπ. Consider a matrix π΄= where π½π, π= β«0 π₯π- 1ππ₯, πππ3 Γ 3 J6 + π, 3 - Jπ+ 3, 3 , πβ€π aππ= Then adj A-1 is : 0 , π> π. (1) (15 ) 2 Γ 234 (2) (15 ) 2 Γ 242 (3) (105 ) 2 Γ 236 (4) (105 ) 2 Γ 238
Q74.Let a be a real number such that the function f(x) = ax2 + 6x β15, x βR is increasing in (ββ, 43 ) and decreasing in ( 34 , β) . Then the function g(x) = ax2 β6x + 15, x βR has a (1) local maximum at x = β34 (2) local minimum at x = β34 (3) local maximum at x = 34 (4) local minimum at x = 34
Q74.If f : R βR is given by f(x) = x + 1, then the value of lim n1 [f(0) + f( n5 ) + f( 10n ) + β¦ . . +f( 5(nβ1)n )] is: nββ (1) 3 (2) 5 2 2 (3) 1 (4) 7 2 2 + βx2 + x βR. Then which one of the
Q74.If Un = (1 + n2 2 n β4 n2 1 )(1 22 ) (1 n2 ) , then nββ(Un)lim n2 is equal to (1) 16e2 (2) 4e (3) e24 (4) 16e2 dx is equal to Q75. β«166 loge x2+loge(x2β44x+484)loge x2 (1) 5 (2) 10 (3) 8 (4) 6
Q74.If β«cosπ₯- sinπ₯ ππ₯= πsin-1sinπ₯+ cosπ₯ + π, where π is a constant of integration, then the ordered pair π, π is β8 - sin2π₯ π equal to: (1) 1, - 3 (2) 3, 1 (3) -1, 3 (4) 1, 3 Q75. β«0π₯2 sinβπ‘ππ‘ lim is equal to: π₯β0 π₯3 JEE Main 2021 (24 Feb Shift 1) JEE Main Previous Year Paper 2 (1) 0 (2) 3 (3) 3 (4) 1 2 15