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Practice Questions

14,828 questions across 23 years of JEE Main β€” find and practise any topic!

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Q58.Given E∘ = βˆ’0.72 V, E∘ = βˆ’0.42 V. The potential for the cell Cr3+/Cr Fe2+//Fe Cr Cr3+(0.1M) Fe2+(0.01M) Fe is (1) 0.26 V (2) 0.399 V (3) βˆ’0.339 V (4) βˆ’0.26 V

2008UnknownElectrochemistry
ChemistryMedium

Q59.For a reaction 1 A β†’2B, rate of disappearance of ' A ' is related to the rate of appearance of 'B' by the 2 expression (1) βˆ’d[A]dt = 12 d[B]dt (2) βˆ’d[A]dt = 14 d[B]dt (3) βˆ’d[A]dt = d[B]dt (4) βˆ’d[A]dt = 4 d[B]dt

2008UnknownChemical Kinetics
ChemistryEasy

Q60.Gold numbers of protective colloids A, B, C and D are 0.50, 0.01, 0.10 and 0.005, respectively. The correct order of their protective powers is (1) D < A < C < B (2) C < B < D < A (3) A < C < B < D (4) B < D < A < C

2008UnknownSurface Chemistry
ChemistryEasy

Q61.The hydrocarbon which can react with sodium in liquid ammonia is (1) CH3CH2CH2C ≑CCH2CH2CH3 (2) CH3CH2C ≑CH (3) CH3CH = CHCH3 (4) CH3CH2C ≑CCH2CH3

2008UnknownHydrocarbons
ChemistryEasy

Q62.Which of the following factors is of no significance for roasting sulphide ores to the oxides and not subjecting the sulphide ores to carbon reduction directly? JEE Main 2008 JEE Main Previous Year Paper (1) Metal sulphides are thermodynamically more (2) CO2 is thermodynamically more stable than CS2 stable than CS2 (3) Metal sulphides are less stable than the (4) CO2 is more volatile than CS2 corresponding oxides

2008UnknownMetallurgy
ChemistryMedium

Q63.Larger number of oxidation states are exhibited by the actinoids than those by the lanthanoids, the main reason being (1) 4 f orbitals more diffused than the 5f orbitals (2) lesser energy difference between 5f and 6d than between 4f and 5d orbitals (3) more energy difference between 5f and 6d than (4) more reactive nature of the actinoids than the between 4f and 5d orbitals lanthanoids

2008Unknownd-block & f-block Elements
ChemistryMedium

Q64.Amount of oxalic acid present in a solution can be determined by its titration with KMnO4 solution in the presence of H2SO4 . The titration gives unsatisfactory result when carried out in the presence of HCl , because HCl (1) gets oxidised by oxalic acid to chlorine (2) furnishes H+ ions in addition to those from oxalic acid (3) reduces permanganate to Mn2+ (4) oxidises oxalic acid to carbon dioxide and water

2008UnknownRedox Reactions
ChemistryMedium

Q65.The coordination number and the oxidation state of the element ' E ' in the complex [E(en)2 (C2O4)]NO2 (where (en) is ethylene diamine) are, respectively, (1) 6 and 2 (2) 4 and 2 (3) 4 and 3 (4) 6 and 3

2008UnknownCoordination Compounds
ChemistryMedium

Q66.In which of the following octahedral complexes of Co (at. no. 27), will the magnitude of Ξ”βˆ˜ be the highest? (1) [Co(CN)6]3βˆ’ (2) [Co(C2O4)3]3βˆ’ (3) [Co(H2O)6]3+ (4) [Co(NH3)6]3+

2008UnknownCoordination Compounds
ChemistryMedium

Q67.The organic chloro compound, which shows complete stereochemical inversion during a SN2 reaction, is (1) (C2H5)2CHCl (2) (CH3)3CCl (3) (CH3)2CHCl (4) CH3Cl

2008UnknownHaloalkanes & Haloarenes
ChemistryMedium

Q68.Phenol, when it first reacts with concentrated sulphuric acid and then with concentrated nitric acid, gives (1) 2,4,6-trinitrobenzene (2) o-nitrophenol (3) p-nitrophenol (4) nitrobenzene

2008UnknownAlcohols Phenols Ethers
ChemistryMedium

Q69.Bakelite is obtained from phenol by reacting with (1) (CH2OH)2 (2) CH3CHO (3) CH3COCH3 (4) HCHO Q70. Ξ± βˆ’D βˆ’(+)-glucose and Ξ² βˆ’D βˆ’(+) βˆ’glucose are (1) conformers (2) epimers (3) anomers (4) enantiomers JEE Main 2008 JEE Main Previous Year Paper

2008UnknownPolymers; Biomolecules
ChemistryEasy

Q71.Statement - 1: For every natural number n β‰₯2, 1 + 1 + … + 1 > √n. Statement βˆ’2 : For every √1 √2 √n natural number n β‰₯2, √n(n + 1) < n + 1. (1) Statement βˆ’1 is false, Statement βˆ’2 is true (2) Statement βˆ’1 is true, Statement βˆ’2 is true, Statement βˆ’2 is a correct explanation for Statement βˆ’1 (3) Statement βˆ’1 is true, Statement βˆ’2 is true; (4) Statement βˆ’1 is true, Statement βˆ’2 is false. Statement βˆ’2 is not a correct explanation for Statement βˆ’1.

2008UnknownSequences & Series
MathsHard

Q72.The quadratic equations x2 βˆ’6x + a = 0 and x2 βˆ’cx + 6 = 0 have one root in common. The other roots of the first and second equations are integers in the ratio 4 : 3. Then the common root is (1) 1 (2) 4 (3) 3 (4) 2

2008UnknownQuadratic Equations
MathsMedium

Q73.The conjugate of a complex number is 1 . Then the complex number is iβˆ’1 (1) βˆ’1 (2) 1 iβˆ’1 i+1 (3) βˆ’1 (4) 1 i+1 iβˆ’1

2008UnknownComplex Numbers
MathsEasy

Q74.In a shop there are five types of ice-creams available. A child buys six ice-creams. Statement -1: The number of different ways the child can buy the six ice-creams is 10C5 . Statement βˆ’2 : The number of different ways the child can buy the six ice-creams is equal to the number of different ways of arranging 6 A's and 4 B's in a row. (1) Statement βˆ’1 is false, Statement βˆ’2 is true (2) Statement βˆ’1 is true, Statement βˆ’2 is true, Statement βˆ’2 is a correct explanation for Statement βˆ’1 (3) Statement βˆ’1 is true, Statement βˆ’2 is true; (4) Statement βˆ’1 is true, Statement βˆ’2 is false. Statement βˆ’2 is not a correct explanation for Statement βˆ’1.

2008UnknownPermutation & Combination
MathsMedium

Q75.How many different words can be formed by jumbling the letters in the word MISSISSIPPI in which no two S are adjacent? (1) 8 β‹…6C4 β‹…7C4 (2) 6.8 β‹…7C4 (3) 6 β‹…7 β‹…8C4 (4) 7 β‹…6C4 β‹…8C4

2008UnknownPermutation & Combination
MathsHard

Q76.The first two terms of a geometric progression add up to 12. The sum of the third and the fourth terms is 48. If the terms of the geometric progression are alternately positive and negative, then the first term is (1) βˆ’4 (2) βˆ’12 (3) 12 (4) 4

2008UnknownSequences & Series
MathsMedium

Q77.Statement-1: βˆ‘nr=0(r + 1)nCr = (n + 2)2nβˆ’1 Statement -2: βˆ‘nr=0(r + 1)nCrxr = (1 + x)n + nx(1 + x)nβˆ’1 . JEE Main 2008 JEE Main Previous Year Paper (1) Statement βˆ’1 is false, Statement βˆ’2 is true (2) Statement βˆ’1 is true, Statement βˆ’2 is true, Statement βˆ’2 is a correct explanation for Statement βˆ’1 (3) Statement βˆ’1 is true, Statement βˆ’2 is true; (4) Statement βˆ’1 is true, Statement βˆ’2 is false. Statement βˆ’2 is not a correct explanation for Statement βˆ’1.

2008UnknownBinomial Theorem
MathsMedium

Q78.The perpendicular bisector of the line segment joining P(1, 4) and Q(k, 3) has y-intercept - 4. Then a possible value of k is (1) 1 (2) 2 (3) βˆ’2 (4) βˆ’4

2008UnknownCoordinate Geometry
MathsMedium

Q79.The point diametrically opposite to the point P(1, 0) on the circle x2 + y2 + 2x + 4y βˆ’3 = 0 is (1) (3, βˆ’4) (2) (βˆ’3, 4) (3) (βˆ’3, βˆ’4) (4) (3, 4)

2008UnknownCircles
MathsEasy

Q80.A parabola has the origin as its focus and the line x = 2 as the directrix. Then the vertex of the parabola is at (1) (0, 2) (2) (1, 0) (3) (0, 1) (4) (2, 0)

2008UnknownParabola
MathsEasy

Q81.A focus of an ellipse is at the origin. The directrix is the line x = 4 and the eccentricity is 1/2. Then the length of the semi-major axis is (1) 8 (2) 2 3 3 (3) 4 (4) 5 3 3

2008UnknownEllipse
MathsMedium

Q82.Let p be the statement " x is an irrational number", q be the statement " y is a transcendental number", and r be the statement " x is a rational number iff y is a transcendental number". Statement βˆ’1 : r is equivalent to either q or p Statement βˆ’2 : r is equivalent to ∼(p β†”βˆΌq). (1) Statement βˆ’1 is false, Statement βˆ’2 is true (2) Statement βˆ’1 is true, Statement βˆ’2 is true, Statement βˆ’2 is a correct explanation for Statement βˆ’1 (3) Statement βˆ’1 is true, Statement βˆ’2 is true; (4) Statement βˆ’1 is true, Statement βˆ’2 is false. Statement βˆ’2 is not a correct explanation for Statement βˆ’1.

2008UnknownMathematical Reasoning
MathsHard

Q83.The statement p β†’(q β†’p) is equivalent to (1) p β†’(p β†’q) (2) p β†’(p ∨q) (3) p β†’(p ∧q) (4) p β†’(p ↔q)

2008UnknownMathematical Reasoning
MathsMedium

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