Practice Questions
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Q61.If x2 + 9y2 β4x + 3 = 0, x, y βR, then x and y respectively lie in the intervals (1) [β13 , 13 ] and [β13 , 13 ] (2) [1, 3] and [β13 , 13 ] (3) [β13 , 13 ] and [1, 3] (4) [1, 3] and [1, 3]
Q61.Let Ξ±, Ξ² be two roots of the equation x2 + (20)1/4x + (5)1/2 = 0 . Then Ξ±8 + Ξ²8 is equal to JEE Main 2021 (27 Jul Shift 1) JEE Main Previous Year Paper (1) 10 (2) 100 (3) 50 (4) 160
Q61.If for x β(0, Ο2 ), log10 sin x + log10 cos x = β1 and log10(sin x + cos x) = 12 (log10 n β1), n > 0 , then the value of n is equal to : (1) 20 (2) 12 (3) 9 (4) 16
Q61.The number of pairs π, π of real numbers, such that whenever πΌ is a root of the equation π₯2 + ππ₯+ π= 0, πΌ2 - 2 is also a root of this equation, is : (1) 6 (2) 8 (3) 4 (4) 2
Q61.Let n denote the number of solutions of the equation z2 + 3z = 0, where z is a complex number. Then the value of ββk=0 nk1 is equal to (1) 1 (2) 34 (3) 32 (4) 2
Q61.Let Ξ± and Ξ² be the roots of x2 β6x β2 = 0. If an = Ξ±n βΞ²n for n β©Ύ1, then the value of a10β2a83a9 is: (1) 1 (2) 3 (3) 2 (4) 4
Q61.Let a complex number be w = 1 ββ3i . Let another complex number z be such that |zw| = 1 and arg(z) βarg(w) = Ο2 . Then the area of the triangle (in sq. units) with vertices origin, z and w is equal to (1) 4 (2) 12 (3) 1 (4) 2 4
Q61.The number of seven digit integers with sum of the digits equal to 10 and formed by using the digits 1, 2 and 3 only is: (1) 77 (2) 82 (3) 42 (4) 35
Q61.The value of 3 + 1 1 is equal to 4+ 1 3+ 1 4+ 3+β¦β (1) 1. 5 + β3 (2) 2 + β3 (3) 3 + 2β3 (4) 4 + β3 Β―Β―
Q61.The least value of |z| where z is complex number which satisfies the inequality ||z|+1| loge 2) e( (|z|+3)(|z|β1) β₯logβ2 5β7 + 9i , i = ββ1, is equal to : (1) 3 (2) β5 (3) 2 (4) 8
Q61.Let Ξ± = max{82 sin 3x β 44 cos 3x} and Ξ² = min sin 3x β 44 cos 3x}. If 8x2 + bx + c = 0 is a quadratic equation xβR xβR{82 whose roots are Ξ±1/5 and Ξ²1/5, then the value of c βb is equal to : (1) 42 (2) 47 (3) 43 (4) 50 JEE Main 2021 (27 Jul Shift 2) JEE Main Previous Year Paper
Q61.If (β3 + + + β3 = 0 1)x + β3 = 0 (2) x2 + (β3 1)x (1) x2 β(β3 = 0 = 0 (4) x2 β(β3 β1)x ββ3 (3) x2 + (β3 β1)x ββ3
Q61.The integer k, for which the inequality x2 β2(3k β1)x + 8k2 β7 > 0 is valid for every x in R is: (1) 4 (2) 2 (3) 3 (4) 0 JEE Main 2021 (25 Feb Shift 1) JEE Main Previous Year Paper Β―Β―
Q61.The equation arg( z+1zβ1 ) = Ο4 represents a circle with: (1) centre at (0, 0) and radius β2 (2) centre at (0, 1) and radius 2 (3) centre at (0, β1) and radius β2 (4) centre at (0, 1) and radius β2 22
Q61.Let π and π be two positive numbers such that π+ π= 2 and π4 + π4 = 272. Then π and π are roots of the equation: (1) π₯2 - 2π₯+ 2 = 0 (2) π₯2 - 2π₯+ 8 = 0 (3) π₯2 - 2π₯+ 136 = 0 (4) π₯2 - 2π₯+ 16 = 0
Q62.The sum of the infinite series 1 + 32 + 327 + 1233 + 1734 + 2235 + β¦ β¦ is equal to: (1) 94 (2) 154 (3) 114 (4) 134
Q62.Let the lines (2 βi)z = (2 + i)z and (2 + i)z + (i β2)z β4i = 0, (here i2 = β1) be normal to a circle C . If Β―the line iz + z + 1 + i = 0 is tangent to this circle C , then its radius is : (1) 3 (2) 3β2 β2 (3) 3 (4) 1 2β2 2β2
Q62.Let C be the set of all complex numbers. Let S1 = {z βC |zβ3β2i|2 = 8}, S2 = z βC| Re(z) β₯5 and Β―S3 = {z βC| |zβz| β₯8}. Then the number of elements in S1 β©S2 β©S3 is equal to (1) 1 (2) 0 (3) 2 (4) Infinite b β 0, are equal, then the value of b is equal
Q62.The sum of all those terms which are rational numbers in the expansion of 1 1 12 3 + 3 4 (2 ) is: (1) 89 (2) 27 (3) 35 (4) 43 , then the
Q62.If sum of the first 21 terms of the series log91/2 x + log91/3 x + log91/4 x + β¦ . . where x > 0 is 504, then x is equal to (1) 243 (2) 9 (3) 7 (4) 81
Q62.Let a complex number z, |z| β 1, satisfy log 1 |z|+11 β€2 . Then, the largest value of |z| is equal to β2 ( (|z|β1)2 ) _________. (1) 8 (2) 7 (3) 6 (4) 5
Q62.The sum of the series ββn=1 n2+6n+10(2n+1)! is equal to (1) 41 8 e + 198 eβ1 + 10 (2) 418 e + 198 eβ1 β10 (3) β418 e + 198 eβ1 β10 (4) 418 e β198 eβ1 β10 + + β¦
Q62.Let Sn denote the sum of first n-terms of an arithmetic progression. If S10 = 530, S5 = 140, then S20 βS6 is equal to: (1) 1862 (2) 1842 (3) 1852 (4) 1872
Q62.Let π1, π2 β¦ , π15 be 15 points on a circle. The number of distinct triangles formed by points ππ, ππ, ππ such that π+ π+ πβ 15, is : (1) 455 (2) 419 (3) 12 (4) 443
Q62.If n β©Ύ2 is a positive integer, then the sum of the series n+1C2 + 2(2C2 + 3C2 + 4C2 + β¦ + nC2) is (1) n(nβ1)(2n+1) (2) n(n+1)(2n+1) 6 6 (3) n(n+1)2(n+2) (4) n(2n+1)(3n+1) 12 6